Maxima - Minima Based DILR || 4 Sets Comprehensively Covering The Concept For CAT
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- Опубліковано 6 вер 2024
- In this video students will learn the concept and approach of solving questions Based on Maxima Minima Set. The video comprehensively cover the various concepts of set theory with 9 excellent set of Venn Diagram. This video is helpful for all students preparing for CAT
Timing and Details of 9 Sets Discussed in this videos are Given below-
Set-1 : Section Wise Marks Cut-Off Set of Maxima - Minima
Set-2 : Maxima - Minima Set With Distribution Method
Set-3 : Maxima Minima Set Based On Percentage Concept (Pie Chart)
Set-4 : Maxima - Minima Set Advance Level (Bar Graph)
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Timestamps:
00:00 Marks cutoff Set
14:20 Distribution method
01:02:00 % based pie chart
01:34:13 Bar chart
sir in pie chart i.e. 1:23:51 please treat it in % or proper value you always mix both into each other sir that is very confusing
Thankyou sir
Thanks sir for this ..all revised at once 😊
Thank you for the session sir !
Most welcome!
In a Nut - Bolt factory 180 workers are working 6 hours a day . Out of 180 workers there are some men, some women and rest are boys . All the workers can produce either nut or bolt or both of them . A man can produce 60 nuts and 80 bolts in each hour and a woman can produce 30 nuts and 60 bolts per hour. A man is thrice as efficient as a boy and 3/2 times as efficient as a women . Given that all men,all women and all boys produce equal number of items of one kind ( i.e either nut or bolt ) per hour.
Q:1 Working 6 hours a day , how many nuts they can produce with 52500 bolt in each day ?
a) 17500 b) 23760 c) 50850 d) 60280 e) 80336
105 - 5 = 110
At 26:41, why did you take 45-21 ?
sir, I dont in question 11:43 i dont think the ans is 50+50+50+25, bcz if he scores 50 in 3 sections he'll get calls from all the 6 colleges., wherein in question it is asked he gets calls from 2 colleges.
so, I think ans is 41.
If he scores 41 in sec C, he wont get calls from clg 1-2-3-5.
so, now he has to clear both clg 4 and 6.
since he scores 41 in sec C , he gets 43 and 45 in Sec A and D(given in Q) for clg 4., so, 178-129= 49 in sec B.
for clg 6: sec C=41, sec D=44 , sec B=41, so 176-126= 50.
so therfore to get calls from both clgs he has to score a min of 178.
So considering clg 4: if he scores 43 in Sec A, 45 in Sec D, 41 in Sec C, 49 or 50 in sec B, he'll call from only 2 clgs.
therfore min in a sec is 41.
25 is right answer. Look carefully he is clearing 2 college cutoff
See you are no wrong but the student needs to clear the aggreagte cutoff as well and the minimum is 175 so he gets calls from only 2 colleges . Its like you cleared all cutoffs but didnt get the final cutoff marks hence you dont get a call . I hope it helps
58:46 question 4 I got answer =97
we can solve second set as chocolate distribution 105 chocolate amounf 45 student first step we will give 1 chocolate to each one we left with 60 then again we will distribute 1 chocolate we will left with 15 and then we will distribute 15 chocolate which is our ans
This should be correct answer, because otherwise time taken by his methods are too much
You have a Rodha concept here btw 😅
thanks buddy .. i didn't understand his method and its too complicated .
Sir 3rd set pie chart ke second que me apne gymnatic zero liya hai ..par que me bola hai kam se kam 1 to har event me participate karega ..to 1 hona chahiye ????
Sir in the second set of this video
In the first question you satisfied that all 45 students should get one prize at least
But in the second question all 45 students didn't got at least one prize
Sir I think if the condition"the number of students in the class 6,7,8,9,10 are 45, 50,40,35 and 48 respectively" ,implies that there are in total 45 students in the 6th class irrespective of the 80%criteria ,then the answer of first question would change .
And if that condition implies that all the 45 students in 6th class have scored 80%in at least 1subject ,then it's hampering the answer of question no.2 ,as each student should get at least one prize is not satisfied.
Sir answer of question no.2 I think would be 20
Ohh I spend so much time thinking the same thing and finally turned to comments to realize I am correct ...ya i feel the same we can't change the assumption in each question ??
Sir , in case of exactly 4 subjects,as you told we will divide total by 4 and then also check whether that no. is greater than the given no. or not. BUT, in the question we have been asked to maximise exactly 4 , so won't we select that comination out of the given combination {5c4} that will let me maximise the total?? For ex, in case of std 6 I take the combination out of eng, hindi, science, ss {17,23,17,20} then why I can't take exactly 4 as 105/4 = [26 as my answer] . Please explain...
Hi sir , how can we assume that each student got a prize in 1st question of the 2nd set , if we don't consider it and maximize no of students who got 5 prizes to get a min of 2-5 the ans is coming as 20.
It is given in the instruction itself. read it carefully
Sir plz upload some videos on collegs as well ,,whihc forms to fill ,whether to go for IMT Ghaziabad or symbossi or both,,aisa kuch related bcoz forma are out aur saare forms bharna muskil hai
sure
38:53 How can 25 students score more than 80 in 4 subjects if the max no.of students scoring more than 80 in English, Science, Hindi and Social is below 25?
there are 5c4 i.e. 5 possible combination of 4 subjects out of 5
1:34:47