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13:15- The distance between the two points can be measured using the Distance Formula which is given by: Distance Formula = √ [(x₂ - x₁)2 + (y₂ - y₁)2] Let the points be A(0, 0) and B(36, 15) Hence, x₁ = 0, y₁ = 0, x₂ = 36, y₂ = 15 We know that the distance between the two points is given by the Distance Formula, = √ [(x₂ - x₁)2 + (y₂ - y₁)2]....(1) = √ (36 - 0)2 + 15 - 0)2 = √ [(1296) + (225)] = √1521 = 39 Yes, it is possible to find the distance between the given towns A and B. The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between town A and B will be 39 km. 38:57 - ii) Let A (- 3, 5), B (3, 1), C (0, 3), and D (- 1, - 4) be the four points of the quadrilateral. We know that the distance between any two points is given by the distance formula = √(x₁ - x₂)² + (y₁ - y₂)² To find AB, that is, the distance between points A (- 3, 5) and B (3, 1) by using the distance formula, AB = √(3 + 3)² + (1 - 5)² = √(6)² + (- 4)² = √36 + 16 = √52 = 2√13 units To find BC, that is, distance between points B (3, 1) and C (0, 3) by using the distance formula, BC = √(0 - 3)² + (3 - 1)² = √ (-3)² + (2)² = √9 + 4 = √13 units To find CD, that is, distance between Points C (0, 3), and D (- 1, - 4) by using the distance formula, CD = √(- 1 - 0)² + (- 4 - 3)² = √ (- 1)² + (- 7)² = √1 + 49 = √50 = 5√2 units To find AD, that is, distance between Points A (- 3, 5) and D (- 1, - 4) using distance formula, AD = √(-1 + 3)² + (- 4 - 5)² = √ (2)² + (- 9)² = √4 + 81 = √85 units Since, AB ≠ BC ≠ CD ≠ AD, therefore, no special quadrilateral can be formed from the given vertices. iii) Let A (4, 5), B (7, 6), C (4, 3) and D (1, 2) be the four points of the quadrilateral. We know that the distance between any two points is given by the Distance Formula, Distance Formula = √ (x₁ - x₂)² + (y₁ - y₂)² To find AB, that is, distance between points A (4, 5) and B (7, 6), by using the distance formula, AB = √(7 - 4)² + (6 - 5)² = √3² + 1² = √9 + 1 = √10 units To find BC, that is, distance between points B (7, 6) and C (4, 3) by using the distance formula, BC = √ (4 - 7 )² + (3 - 6)² = √ (- 3)² + 3² = √9 + 9 = √18 units To find CD, that is, distance between points C (4, 3) and D (1, 2) by using the distance formula, CD = √(1 - 4)² + (2 - 3)² = √ (- 3)² + (- 1)² = √9 + 1 = √10 units To find AD i.e. Distance between points A (4, 5) and D (1, 2) using distance formula, AD = √( 1 - 4 )² + ( 2 - 5)² = √ (- 3)² + (- 3)² = √ 9 + 9 = √18 units To find AC, the distance between points A (4, 5) and C (4, 3), we have Diagonal AC = √( 4 - 4 )² + ( 3 - 5)² = √( 0 )² + ( - 2)² = 2 units To find BD, distance between points B (7, 6) and D (1, 2), we have Diagonal BD = √(1 - 7)² + (2 - 6)² = √ ( - 6 )² + ( - 4 )² = √ 36 + 16 = √52 units Since AB = CD and BC = AD, but the diagonals AC ≠ BD, thus the quadrilateral is a parallellogram. 1:21:32 - P, Q, R divides the line segment A (- 2, 2) and B (2, 8) into four equal parts. Point P divides the line segment AQ into two equal parts. Therefore, AP : PB is 1 : 3 Using section formula which is given by P (x, y) = [(mx₂ + nx₁) / m + n , (my₂ + ny₁) / m + n] Hence, coordinates of P = [(1 × 2 + 3 × (- 2)) / (3 + 1), (1 × 8 + 3 × 2) / (3 + 1)] = (- 1, 7/2) Point Q divides the line segment AB into two equal parts Using mid point formula, Q = [(2 + (- 2)) / 2, (2 + 8) / 2] = (0, 5) Point R divides the line segment BQ into two equal parts Coordinates of R = [(2 + 0) / 2, (8 + 5) / 2] = (1, 13/2) 1:58:24- A rhombus has all sides of equal length and opposite sides are parallel. Let A(3, 0), B(4, 5), C(- 1, 4) and D(- 2, - 1) be the vertices of a rhombus ABCD. Also, Area of a rhombus =1/2 × (product of its diagonals) Hence we will calculate the values of the diagonals AC and BD. We know that the distance between the two points is given by the distance formula, Distance formula = √( x₂ - x₁ )2 + (y₂ - y₁)2 Therefore, distance between A (3, 0) and C (- 1, 4) is given by Length of diagonal AC =√ [3 - (-1)]2 + [0 - 4]2 = √(16 + 16) = 4√2 The distance between B (4, 5) and D (- 2, - 1) is given by Length of diagonal BD = √[4 - (-2)]2 + [5 - (-1)]2 = √(36 + 36) = 6√2 Area of the rhombus ABCD = 1/2 × (Product of lengths of diagonals) = 1/2 × AC × BD Therefore, the area of the rhombus ABCD = 1/2 × 4√2 × 6√2 square units = 24 square units
video's timeline: * 00:00 - 00:15: Introduction * 00:15 - 01:15: Explanation of x and y coordinates * 01:15 - 02:15: Distance formula explanation * 02:15 - 03:15: Example 1: Calculating distance between two points * 03:15 - 04:15: Example 2: Identifying the type of quadrilateral * 04:15 - 05:15: Section formula explanation * 05:15 - 06:15: Example 3: Finding the coordinates of a point dividing a line segment in a given ratio * 06:15 - 07:15: Example 4: Finding the coordinates of a point dividing a line segment in a given ratio * 07:15 - 08:15: Midpoint formula explanation * 08:15 - 09:15: Example 5: Finding the coordinates of the midpoint of a line segment * 09:15 - 10:15: Example 6: Finding the coordinates of the midpoint of a line segment * 10:15 - 11:15: Example 7: Finding the coordinates of the midpoint of a line segment * 11:15 - 12:15: Example 8: Finding the coordinates of the midpoint of a line segment * 12:15 - 13:15: Example 9: Finding the coordinates of the midpoint of a line segment * 13:15 - 14:15: Example 10: Finding the coordinates of the midpoint of a line segment * 14:15 - 15:15: Example 11: Finding the coordinates of the midpoint of a line segment * 15:15 - 16:15: Example 12: Finding the coordinates of the midpoint of a line segment * 16:15 - 17:15: Example 13: Finding the coordinates of the midpoint of a line segment * 17:15 - 18:15: Example 14: Finding the coordinates of the midpoint of a line segment * 18:15 - 19:15: Example 15: Finding the coordinates of the midpoint of a line segment * 19:15 - 20:15: Example 16: Finding the coordinates of the midpoint of a line segment * 20:15 - 21:15: Example 17: Finding the coordinates of the midpoint of a line segment * 21:15 - 22:15: Example 18: Finding the coordinates of the midpoint of a line segment * 22:15 - 23:15: Example 19: Finding the coordinates of the midpoint of a line segment * 23:15 - 24:15: Example 20: Finding the coordinates of the midpoint of a line segment * 24:15 - 25:15: Example 21: Finding the coordinates of the midpoint of a line segment * 25:15 - 26:15: Example 22: Finding the coordinates of the midpoint of a line segment * 26:15 - 27:15: Example 23: Finding the coordinates of the midpoint of a line segment * 27:15 - 28:15: Example 24: Finding the coordinates of the midpoint of a line segment * 28:15 - 29:15: Example 25: Finding the coordinates of the midpoint of a line segment * 29:15 - 30:15: Example 26: Finding the coordinates of the midpoint of a line segment * 30:15 - 31:15: Example 27: Finding the coordinates of the midpoint of a line segment * 31:15 - 32:15: Example 28: Finding the coordinates of the midpoint of a line segment * 32:15 - 33:15: Example 29: Finding the coordinates of the midpoint of a line segment * 33:15 - 34:15: Example 30: Finding the coordinates of the midpoint of a line segment * 34:15 - 35:15: Example 31: Finding the coordinates of the midpoint of a line segment * 35:15 - 36:15: Example 32: Finding the coordinates of the midpoint of a line segment * 36:15 - 37:15: Example 33: Finding the coordinates of the midpoint of a line segment * 37:15 - 38:15: Example 34: Finding the coordinates of the midpoint of a line segment * 38:15 - 39:15: Example 35: Finding the coordinates of the midpoint of a line segment * 39:15 - 40:15: Example 36: Finding the coordinates of the midpoint of a line segment * 40:15 - 41:15: Example 37: Finding the coordinates of the midpoint of a line segment * 41:15 - 42:15: Example 38: Finding the coordinates of the midpoint of a line segment * 42:15 - 43:15: Example 39: Finding the coordinates of the midpoint of a line segment * 43:15 - 44:15: Example 40: Finding the coordinates of the midpoint of a line segment * 44:15 - 45:15: Example 41: Finding the coordinates of the midpoint of a line segment * 45:15 - 46:15: Example 42: Finding the coordinates of the midpoint of a line segment * 46:15 - 47:15: Example 43: Finding the coordinates of the midpoint of a line segment * 47:15 - 48:15: Example 44: Finding the coordinates of the midpoint of a line segment * 48:15 - 49:15: Example 45: Finding the coordinates of the midpoint of a line segment * 49:15 - 50:15: Example 46: Finding the coordinates of the midpoint of a line segment * 50:15 - 51:15: Example 47: Finding the coordinates of the midpoint of a line segment * 51:15 - 52:15: Example 48: Finding the coordinates of the midpoint of a line segment * 52:15 - 53:15: Example 49: Finding the coordinates of the midpoint of a line segment * 53:15 - 54:15: Example 50: Finding the coordinates of the midpoint of a line segment * 54:15 - 55:15: Example 51: Finding the coordinates of the midpoint of a line segment * 55:15 - 56:15: Example 52: Finding the coordinates of the midpoint of a line segment * 56:15 - 57:15: Example 53: Finding the coordinates of the midpoint of a line segment * 57:15 - 58:15: Example 54: Finding the coordinates of the midpoint of a line segment * 58:15 - 59:15: Example 55: Finding the coordinates of the midpoint of a line segment * 59:15 - 1:00:00: Example 56: Finding the coordinates of the midpoint of a line segment * 1:00:00 - 1:01:00: Example 57: Finding the coordinates of the midpoint of a line segment * 1:01:00 - 1:02:00: Example 58: Finding the coordinates of the midpoint of a line segment * 1:02:00 - 1:03:00: Example 59: Finding the coordinates of the midpoint of a line segment * 1:03:00 - 1:04:00: Example 60: Finding the coordinates of the midpoint of a line segment * 1:04:00 - 1:05:00: Example 61: Finding the coordinates of the midpoint of a line segment * 1:05:00 - 1:06:00: Example 62: Finding the coordinates of the midpoint of a line segment *
00:01 Coordinate Geometry and NCERT back exercises discussed in the video 01:57 Coordinate geometry is a scoring chapter with easy concepts but requires careful calculations. 06:20 Understanding coordinate geometry concepts and distance formula 08:29 Summary of Coordinate Geometry concepts and formulas 13:02 Understanding the concept of collinear points 15:03 Coordinate Geometry and Collinearity 20:14 Explaining how to determine if three points are collinear or form an isosceles triangle 22:52 Using operations with coordinate geometry 27:30 Understanding the concept of a square in geometry 29:46 Understanding the concept of squares in coordinate geometry 33:58 Understanding and applying the distance formula 36:07 Understanding coordinate geometry concepts and calculations 40:18 Understanding coordinates and distance from x-axis 42:11 Understanding distance from x and y axis 46:56 Explaining the process of squaring and removing under roots 48:58 Finding a point with equal distance from two given points on the x-axis 53:22 Key points on solving equations in Coordinate Geometry 56:06 Summarizing coordinate geometry concepts for Class 10th Board 1:00:59 Solving equations using coordinate geometry 1:03:32 Understanding section formula for finding coordinates of a point 1:07:53 Section formula helps find coordinates of a point dividing a line segment 1:10:04 Finding coordinates of a point which divides a line segment 1:14:46 Introduction to Coordinate Geometry concepts. 1:16:45 Explaining how to find coordinates using formulas 1:21:19 Understanding the concept of mid point formula 1:23:21 Explaining the section formula and midpoint formula 1:27:57 Understanding and calculating coordinates of flags and distance formula 1:30:36 Understanding coordinates and midpoint in geometry 1:35:06 Understanding the division ratio of a line segment 1:37:19 Understanding the division of line segments on the x-axis 1:41:39 Understanding the concept of Taken in Order 1:43:54 Understanding of midpoints and diagonals in coordinate geometry 1:48:16 Finding the center and coordinates of a circle 1:50:31 Understanding the mid point formula and its application. 1:55:03 Understanding and finding coordinates using ratios 1:57:21 Formula for Area of Rhombus requires halving product of diagonals
I am feeling confident about my maths now..... growing up... I have only heard my mom and dad and everyone that I am not worth anything... I can't do anything in my life.... but now I can see the light of hope
AARE BHAI BOARDS HI SAB KUCH NHI HOTA HAI BHAI JAISA EX LO TUMSE KABHI KISI NA 9TH KA RESULT 8TH KA RESULT POCHA HAI OR POCHA BHI HOGA TO EK YA 2 BARR PHIRR SAB BHUL GYE N BOARD SIRF MANNAT KRNE SIKHATA HAI KI AAGE KUCH KAR PAO OR YE YAAD RKNA ... TUM HO ISS LIYA BOARD HAI BOARD HAI ISS LIYA TUM NHI ....
almost exactly same condition with my parents as well. I remember ive been hearing such words like my memory is weak, that i mug up everything and do not understand a single thing in my textbooks, from age 5 onwards. The effect of hearing things like that constantly, is that, even though i am in 10th now, i still have low self esteem, i am now shy to participate in a competion, i am under confident and cant make rapid decisions as i always end up doubting myselt due to my parents. Lets be strong for ourselves.
Love u sir. Aankhe dard ho gayi. 4 hours tak continuousely aapke saath solve karke chapter khatam kar diya. Finally SATISFIED. Abki bar 95 percent paar.
The distance between the two points can be measured using the Distance Formula which is given by: Distance Formula = √ [(x₂ - x₁)2 + (y₂ - y₁)2] Let the points be A(0, 0) and B(36, 15) Hence, x₁ = 0, y₁ = 0, x₂ = 36, y₂ = 15 We know that the distance between the two points is given by the Distance Formula, = √ [(x₂ - x₁)2 + (y₂ - y₁)2]....(1) = √ (36 - 0)2 + 15 - 0)2 = √ [(1296) + (225)] = √1521 = 39 Yes, it is possible to find the distance between the given towns A and B. The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between town A and B will be 39 km. 38:57 - ii) Let A (- 3, 5), B (3, 1), C (0, 3), and D (- 1, - 4) be the four points of the quadrilateral. We know that the distance between any two points is given by the distance formula = √(x₁ - x₂)² + (y₁ - y₂)² To find AB, that is, the distance between points A (- 3, 5) and B (3, 1) by using the distance formula, AB = √(3 + 3)² + (1 - 5)² = √(6)² + (- 4)² = √36 + 16 = √52 = 2√13 units To find BC, that is, distance between points B (3, 1) and C (0, 3) by using the distance formula, BC = √(0 - 3)² + (3 - 1)² = √ (-3)² + (2)² = √9 + 4 = √13 units To find CD, that is, distance between Points C (0, 3), and D (- 1, - 4) by using the distance formula, CD = √(- 1 - 0)² + (- 4 - 3)² = √ (- 1)² + (- 7)² = √1 + 49 = √50 = 5√2 units To find AD, that is, distance between Points A (- 3, 5) and D (- 1, - 4) using distance formula, AD = √(-1 + 3)² + (- 4 - 5)² = √ (2)² + (- 9)² = √4 + 81 = √85 units Since, AB ≠ BC ≠ CD ≠ AD, therefore, no special quadrilateral can be formed from the given vertices. iii) Let A (4, 5), B (7, 6), C (4, 3) and D (1, 2) be the four points of the quadrilateral. We know that the distance between any two points is given by the Distance Formula, Distance Formula = √ (x₁ - x₂)² + (y₁ - y₂)² To find AB, that is, distance between points A (4, 5) and B (7, 6), by using the distance formula, AB = √(7 - 4)² + (6 - 5)² = √3² + 1² = √9 + 1 = √10 units To find BC, that is, distance between points B (7, 6) and C (4, 3) by using the distance formula, BC = √ (4 - 7 )² + (3 - 6)² = √ (- 3)² + 3² = √9 + 9 = √18 units To find CD, that is, distance between points C (4, 3) and D (1, 2) by using the distance formula, CD = √(1 - 4)² + (2 - 3)² = √ (- 3)² + (- 1)² = √9 + 1 = √10 units To find AD i.e. Distance between points A (4, 5) and D (1, 2) using distance formula, AD = √( 1 - 4 )² + ( 2 - 5)² = √ (- 3)² + (- 3)² = √ 9 + 9 = √18 units To find AC, the distance between points A (4, 5) and C (4, 3), we have Diagonal AC = √( 4 - 4 )² + ( 3 - 5)² = √( 0 )² + ( - 2)² = 2 units To find BD, distance between points B (7, 6) and D (1, 2), we have Diagonal BD = √(1 - 7)² + (2 - 6)² = √ ( - 6 )² + ( - 4 )² = √ 36 + 16 = √52 units Since AB = CD and BC = AD, but the diagonals AC ≠ BD, thus the quadrilateral is a parallellogram. 1:21:32 - P, Q, R divides the line segment A (- 2, 2) and B (2, 8) into four equal parts. Point P divides the line segment AQ into two equal parts. Therefore, AP : PB is 1 : 3 Using section formula which is given by P (x, y) = [(mx₂ + nx₁) / m + n , (my₂ + ny₁) / m + n] Hence, coordinates of P = [(1 × 2 + 3 × (- 2)) / (3 + 1), (1 × 8 + 3 × 2) / (3 + 1)] = (- 1, 7/2) Point Q divides the line segment AB into two equal parts Using mid point formula, Q = [(2 + (- 2)) / 2, (2 + 8) / 2] = (0, 5) Point R divides the line segment BQ into two equal parts Coordinates of R = [(2 + 0) / 2, (8 + 5) / 2] = (1, 13/2) 1:58:24- A rhombus has all sides of equal length and opposite sides are parallel. Let A(3, 0), B(4, 5), C(- 1, 4) and D(- 2, - 1) be the vertices of a rhombus ABCD. Also, Area of a rhombus =1/2 × (product of its diagonals) Hence we will calculate the values of the diagonals AC and BD. We know that the distance between the two points is given by the distance formula, Distance formula = √( x₂ - x₁ )2 + (y₂ - y₁)2 Therefore, distance between A (3, 0) and C (- 1, 4) is given by Length of diagonal AC =√ [3 - (-1)]2 + [0 - 4]2 = √(16 + 16) = 4√2 The distance between B (4, 5) and D (- 2, - 1) is given by Length of diagonal BD = √[4 - (-2)]2 + [5 - (-1)]2 = √(36 + 36) = 6√2 Area of the rhombus ABCD = 1/2 × (Product of lengths of diagonals) = 1/2 × AC × BD Therefore, the area of the rhombus ABCD = 1/2 × 4√2 × 6√2 square units = 24 square units
Sir mera kl exam hai and now 1:01 AM This is the third chapter after areas related to circle and statistics. 😂😂 Whose exam is tomorrow and watching this
@@priyanshipiyush high weightage vale chapter padh and half yearly ke NCERT pura kr ke jao. Usse at least concept clear ho jayega. And try your best 💪 and don't worry agr nhi hua toh yeh half yearly hi h boards mai achha perform krna baki all the best 😊😀
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13:15-
The distance between the two points can be measured using the Distance Formula which is given by: Distance Formula = √ [(x₂ - x₁)2 + (y₂ - y₁)2]
Let the points be A(0, 0) and B(36, 15)
Hence, x₁ = 0, y₁ = 0, x₂ = 36, y₂ = 15
We know that the distance between the two points is given by the Distance Formula,
= √ [(x₂ - x₁)2 + (y₂ - y₁)2]....(1)
= √ (36 - 0)2 + 15 - 0)2
= √ [(1296) + (225)]
= √1521
= 39
Yes, it is possible to find the distance between the given towns A and B.
The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between town A and B will be 39 km.
38:57 -
ii) Let A (- 3, 5), B (3, 1), C (0, 3), and D (- 1, - 4) be the four points of the quadrilateral.
We know that the distance between any two points is given by the distance formula = √(x₁ - x₂)² + (y₁ - y₂)²
To find AB, that is, the distance between points A (- 3, 5) and B (3, 1) by using the distance formula,
AB = √(3 + 3)² + (1 - 5)²
= √(6)² + (- 4)²
= √36 + 16
= √52
= 2√13 units
To find BC, that is, distance between points B (3, 1) and C (0, 3) by using the distance formula,
BC = √(0 - 3)² + (3 - 1)²
= √ (-3)² + (2)²
= √9 + 4
= √13 units
To find CD, that is, distance between Points C (0, 3), and D (- 1, - 4) by using the distance formula,
CD = √(- 1 - 0)² + (- 4 - 3)²
= √ (- 1)² + (- 7)²
= √1 + 49
= √50
= 5√2 units
To find AD, that is, distance between Points A (- 3, 5) and D (- 1, - 4) using distance formula,
AD = √(-1 + 3)² + (- 4 - 5)²
= √ (2)² + (- 9)²
= √4 + 81
= √85 units
Since, AB ≠ BC ≠ CD ≠ AD, therefore, no special quadrilateral can be formed from the given vertices.
iii) Let A (4, 5), B (7, 6), C (4, 3) and D (1, 2) be the four points of the quadrilateral.
We know that the distance between any two points is given by the Distance Formula,
Distance Formula = √ (x₁ - x₂)² + (y₁ - y₂)²
To find AB, that is, distance between points A (4, 5) and B (7, 6), by using the distance formula,
AB = √(7 - 4)² + (6 - 5)²
= √3² + 1²
= √9 + 1
= √10 units
To find BC, that is, distance between points B (7, 6) and C (4, 3) by using the distance formula,
BC = √ (4 - 7 )² + (3 - 6)²
= √ (- 3)² + 3²
= √9 + 9
= √18 units
To find CD, that is, distance between points C (4, 3) and D (1, 2) by using the distance formula,
CD = √(1 - 4)² + (2 - 3)²
= √ (- 3)² + (- 1)²
= √9 + 1
= √10 units
To find AD i.e. Distance between points A (4, 5) and D (1, 2) using distance formula,
AD = √( 1 - 4 )² + ( 2 - 5)²
= √ (- 3)² + (- 3)²
= √ 9 + 9
= √18 units
To find AC, the distance between points A (4, 5) and C (4, 3), we have
Diagonal AC = √( 4 - 4 )² + ( 3 - 5)²
= √( 0 )² + ( - 2)²
= 2 units
To find BD, distance between points B (7, 6) and D (1, 2), we have
Diagonal BD = √(1 - 7)² + (2 - 6)²
= √ ( - 6 )² + ( - 4 )²
= √ 36 + 16
= √52 units
Since AB = CD and BC = AD, but the diagonals AC ≠ BD, thus the quadrilateral is a parallellogram.
1:21:32 -
P, Q, R divides the line segment A (- 2, 2) and B (2, 8) into four equal parts.
Point P divides the line segment AQ into two equal parts.
Therefore, AP : PB is 1 : 3
Using section formula which is given by P (x, y) = [(mx₂ + nx₁) / m + n , (my₂ + ny₁) / m + n]
Hence, coordinates of P = [(1 × 2 + 3 × (- 2)) / (3 + 1), (1 × 8 + 3 × 2) / (3 + 1)] = (- 1, 7/2)
Point Q divides the line segment AB into two equal parts
Using mid point formula,
Q = [(2 + (- 2)) / 2, (2 + 8) / 2] = (0, 5)
Point R divides the line segment BQ into two equal parts
Coordinates of R = [(2 + 0) / 2, (8 + 5) / 2] = (1, 13/2)
1:58:24-
A rhombus has all sides of equal length and opposite sides are parallel.
Let A(3, 0), B(4, 5), C(- 1, 4) and D(- 2, - 1) be the vertices of a rhombus ABCD.
Also, Area of a rhombus =1/2 × (product of its diagonals)
Hence we will calculate the values of the diagonals AC and BD.
We know that the distance between the two points is given by the distance formula,
Distance formula = √( x₂ - x₁ )2 + (y₂ - y₁)2
Therefore, distance between A (3, 0) and C (- 1, 4) is given by
Length of diagonal AC =√ [3 - (-1)]2 + [0 - 4]2
= √(16 + 16)
= 4√2
The distance between B (4, 5) and D (- 2, - 1) is given by
Length of diagonal BD = √[4 - (-2)]2 + [5 - (-1)]2
= √(36 + 36)
= 6√2
Area of the rhombus ABCD = 1/2 × (Product of lengths of diagonals) = 1/2 × AC × BD
Therefore, the area of the rhombus ABCD = 1/2 × 4√2 × 6√2 square units
= 24 square units
Itna shukriya ki bol bhi na para
Prr igni jarrurat bhi thi nhi vaise
Chat gpt ka kamaal
Last wala √36+36=6√2 kaise aaya
❤❤❤❤❤🎉🎉🎉🎉
Abe kseab solution se copy kar daley hai😂
Vote for goal 98% 🔥❤
Why not 💯 bro...😅
90 me bhi kam chala lunga😮😂
Hi
I'm your 200 liker
No bro its 99.83
video's timeline:
* 00:00 - 00:15: Introduction
* 00:15 - 01:15: Explanation of x and y coordinates
* 01:15 - 02:15: Distance formula explanation
* 02:15 - 03:15: Example 1: Calculating distance between two points
* 03:15 - 04:15: Example 2: Identifying the type of quadrilateral
* 04:15 - 05:15: Section formula explanation
* 05:15 - 06:15: Example 3: Finding the coordinates of a point dividing a line segment in a given ratio
* 06:15 - 07:15: Example 4: Finding the coordinates of a point dividing a line segment in a given ratio
* 07:15 - 08:15: Midpoint formula explanation
* 08:15 - 09:15: Example 5: Finding the coordinates of the midpoint of a line segment
* 09:15 - 10:15: Example 6: Finding the coordinates of the midpoint of a line segment
* 10:15 - 11:15: Example 7: Finding the coordinates of the midpoint of a line segment
* 11:15 - 12:15: Example 8: Finding the coordinates of the midpoint of a line segment
* 12:15 - 13:15: Example 9: Finding the coordinates of the midpoint of a line segment
* 13:15 - 14:15: Example 10: Finding the coordinates of the midpoint of a line segment
* 14:15 - 15:15: Example 11: Finding the coordinates of the midpoint of a line segment
* 15:15 - 16:15: Example 12: Finding the coordinates of the midpoint of a line segment
* 16:15 - 17:15: Example 13: Finding the coordinates of the midpoint of a line segment
* 17:15 - 18:15: Example 14: Finding the coordinates of the midpoint of a line segment
* 18:15 - 19:15: Example 15: Finding the coordinates of the midpoint of a line segment
* 19:15 - 20:15: Example 16: Finding the coordinates of the midpoint of a line segment
* 20:15 - 21:15: Example 17: Finding the coordinates of the midpoint of a line segment
* 21:15 - 22:15: Example 18: Finding the coordinates of the midpoint of a line segment
* 22:15 - 23:15: Example 19: Finding the coordinates of the midpoint of a line segment
* 23:15 - 24:15: Example 20: Finding the coordinates of the midpoint of a line segment
* 24:15 - 25:15: Example 21: Finding the coordinates of the midpoint of a line segment
* 25:15 - 26:15: Example 22: Finding the coordinates of the midpoint of a line segment
* 26:15 - 27:15: Example 23: Finding the coordinates of the midpoint of a line segment
* 27:15 - 28:15: Example 24: Finding the coordinates of the midpoint of a line segment
* 28:15 - 29:15: Example 25: Finding the coordinates of the midpoint of a line segment
* 29:15 - 30:15: Example 26: Finding the coordinates of the midpoint of a line segment
* 30:15 - 31:15: Example 27: Finding the coordinates of the midpoint of a line segment
* 31:15 - 32:15: Example 28: Finding the coordinates of the midpoint of a line segment
* 32:15 - 33:15: Example 29: Finding the coordinates of the midpoint of a line segment
* 33:15 - 34:15: Example 30: Finding the coordinates of the midpoint of a line segment
* 34:15 - 35:15: Example 31: Finding the coordinates of the midpoint of a line segment
* 35:15 - 36:15: Example 32: Finding the coordinates of the midpoint of a line segment
* 36:15 - 37:15: Example 33: Finding the coordinates of the midpoint of a line segment
* 37:15 - 38:15: Example 34: Finding the coordinates of the midpoint of a line segment
* 38:15 - 39:15: Example 35: Finding the coordinates of the midpoint of a line segment
* 39:15 - 40:15: Example 36: Finding the coordinates of the midpoint of a line segment
* 40:15 - 41:15: Example 37: Finding the coordinates of the midpoint of a line segment
* 41:15 - 42:15: Example 38: Finding the coordinates of the midpoint of a line segment
* 42:15 - 43:15: Example 39: Finding the coordinates of the midpoint of a line segment
* 43:15 - 44:15: Example 40: Finding the coordinates of the midpoint of a line segment
* 44:15 - 45:15: Example 41: Finding the coordinates of the midpoint of a line segment
* 45:15 - 46:15: Example 42: Finding the coordinates of the midpoint of a line segment
* 46:15 - 47:15: Example 43: Finding the coordinates of the midpoint of a line segment
* 47:15 - 48:15: Example 44: Finding the coordinates of the midpoint of a line segment
* 48:15 - 49:15: Example 45: Finding the coordinates of the midpoint of a line segment
* 49:15 - 50:15: Example 46: Finding the coordinates of the midpoint of a line segment
* 50:15 - 51:15: Example 47: Finding the coordinates of the midpoint of a line segment
* 51:15 - 52:15: Example 48: Finding the coordinates of the midpoint of a line segment
* 52:15 - 53:15: Example 49: Finding the coordinates of the midpoint of a line segment
* 53:15 - 54:15: Example 50: Finding the coordinates of the midpoint of a line segment
* 54:15 - 55:15: Example 51: Finding the coordinates of the midpoint of a line segment
* 55:15 - 56:15: Example 52: Finding the coordinates of the midpoint of a line segment
* 56:15 - 57:15: Example 53: Finding the coordinates of the midpoint of a line segment
* 57:15 - 58:15: Example 54: Finding the coordinates of the midpoint of a line segment
* 58:15 - 59:15: Example 55: Finding the coordinates of the midpoint of a line segment
* 59:15 - 1:00:00: Example 56: Finding the coordinates of the midpoint of a line segment
* 1:00:00 - 1:01:00: Example 57: Finding the coordinates of the midpoint of a line segment
* 1:01:00 - 1:02:00: Example 58: Finding the coordinates of the midpoint of a line segment
* 1:02:00 - 1:03:00: Example 59: Finding the coordinates of the midpoint of a line segment
* 1:03:00 - 1:04:00: Example 60: Finding the coordinates of the midpoint of a line segment
* 1:04:00 - 1:05:00: Example 61: Finding the coordinates of the midpoint of a line segment
* 1:05:00 - 1:06:00: Example 62: Finding the coordinates of the midpoint of a line segment
*
I hope everyone will get 100/100 in maths boards including me. 🎓💫✨
✨
Thank you
❤
🎉❤🎉❤
🫶🏼🫶🏼🫶🏼
parallelogram ❌lologram✅
Yeah
Hatttttttttttt AIR 247
😂
Lulligram
Air 247 🚫 bakcho*✅@@AnimefanboyNAHIBTFANBOYBOLTE
Don't fear about exam guys just give your 💯 % without knowing your results....it enough to give you 💯😊
Words like buddha 😊
😇Thanks for the motivation
Thanks dost for motivation❤ because tomorrow is my pre board of maths and it is standard 😢
00:01 Coordinate Geometry and NCERT back exercises discussed in the video
01:57 Coordinate geometry is a scoring chapter with easy concepts but requires careful calculations.
06:20 Understanding coordinate geometry concepts and distance formula
08:29 Summary of Coordinate Geometry concepts and formulas
13:02 Understanding the concept of collinear points
15:03 Coordinate Geometry and Collinearity
20:14 Explaining how to determine if three points are collinear or form an isosceles triangle
22:52 Using operations with coordinate geometry
27:30 Understanding the concept of a square in geometry
29:46 Understanding the concept of squares in coordinate geometry
33:58 Understanding and applying the distance formula
36:07 Understanding coordinate geometry concepts and calculations
40:18 Understanding coordinates and distance from x-axis
42:11 Understanding distance from x and y axis
46:56 Explaining the process of squaring and removing under roots
48:58 Finding a point with equal distance from two given points on the x-axis
53:22 Key points on solving equations in Coordinate Geometry
56:06 Summarizing coordinate geometry concepts for Class 10th Board
1:00:59 Solving equations using coordinate geometry
1:03:32 Understanding section formula for finding coordinates of a point
1:07:53 Section formula helps find coordinates of a point dividing a line segment
1:10:04 Finding coordinates of a point which divides a line segment
1:14:46 Introduction to Coordinate Geometry concepts.
1:16:45 Explaining how to find coordinates using formulas
1:21:19 Understanding the concept of mid point formula
1:23:21 Explaining the section formula and midpoint formula
1:27:57 Understanding and calculating coordinates of flags and distance formula
1:30:36 Understanding coordinates and midpoint in geometry
1:35:06 Understanding the division ratio of a line segment
1:37:19 Understanding the division of line segments on the x-axis
1:41:39 Understanding the concept of Taken in Order
1:43:54 Understanding of midpoints and diagonals in coordinate geometry
1:48:16 Finding the center and coordinates of a circle
1:50:31 Understanding the mid point formula and its application.
1:55:03 Understanding and finding coordinates using ratios
1:57:21 Formula for Area of Rhombus requires halving product of diagonals
💀🙏🏼👍🏻
Parallelogram ❌lologram✅
😂@@Sumaiya-ls3zo
14 January ko kon kon dekh rha hai aur kl pre board kis kis ka hai
Class 10 2024 -2025 attendence lago👍👍📒📓📔📖
Bahi roll no baj do❤❤
Girls first
@@Sidhu_X_Subh112 ..
,
Master bn rha h toh pdhne kyu aaya idr😂
Basic wale. Like kere 😮
I am feeling confident about my maths now..... growing up... I have only heard my mom and dad and everyone that I am not worth anything... I can't do anything in my life.... but now I can see the light of hope
AARE BHAI BOARDS HI SAB KUCH NHI HOTA HAI BHAI JAISA EX LO TUMSE KABHI KISI NA 9TH KA RESULT 8TH KA RESULT POCHA HAI OR POCHA BHI HOGA TO EK YA 2 BARR PHIRR SAB BHUL GYE N BOARD SIRF MANNAT KRNE SIKHATA HAI KI AAGE KUCH KAR PAO
OR YE YAAD RKNA ...
TUM HO ISS LIYA BOARD HAI
BOARD HAI ISS LIYA TUM NHI ....
almost exactly same condition with my parents as well. I remember ive been hearing such words like my memory is weak, that i mug up everything and do not understand a single thing in my textbooks, from age 5 onwards. The effect of hearing things like that constantly, is that, even though i am in 10th now, i still have low self esteem, i am now shy to participate in a competion, i am under confident and cant make rapid decisions as i always end up doubting myselt due to my parents. Lets be strong for ourselves.
@@Maahiee we can only hope for our conditions to get better....
Bhiya results kaise aaye please tips dedo stream wagera bhi bata dena :)
😂😂waaah taliyan@@existingmaker
Ritik sir respect Button 🙏 ----------->
Report button 😂
@@UwU.slayerYor p___y button 🗿
00:00 - Introduction
02:38 - Exercise - 7.1
01:05:05 - Exercise - 7.2
01:59:13 - Thank You !
Bhai boards ke liye ab dar lag rhe hai 😂
Who is watching in January 😅😅
Me bhai 😅😅😅😅
🖐️
1:21:26
Point (p) coordinates
(-1,7/2)
Point Q coordinates
(0,5)
And point R coordinates
(1,13/2)
🎉🎉same
Sir you are a great sir ab ap ho isliye muje kam dar lag rha hai 😢
Dont fear when pw is here gyzzzzz😊 i m waiting for boards 😌😌
Just backbencher things 😅 watching before 37 days of board exam 😜 "yes, we are backbenchers but we score marks like toppers " 😌🥂
Besttttt teacher❤❤of maths
Kon kon january 2025 mai dekh raha hai ... ? ....apko boards ki ksm sach sach batana kis kis ka syllabus complete hogya hai ....😊❤..
2024 nhi 2025 re fagunnia 😅
Thoda baacha h aabhi 😅😅
Thnx bro 😊 @@ankitkushwaha2569
Mera to complete ho gaya
Caution: Not bhai
Hindu for a reason
29:01 ve kmleyaa 😌😌😌🫠🫠🫠🫠🫠🫠🫠🫡🫡🫡🫡🫡☺️☺️☺️🙂
Yeah I'm searching for that.... 29:02
Love u sir. Aankhe dard ho gayi. 4 hours tak continuousely aapke saath solve karke chapter khatam kar diya. Finally SATISFIED. Abki bar 95 percent paar.
Admit card bhi aa chuka hai, padhai abhi tak suru bhi nahi kari hai 😢😢😢😢
Same bro
Mera nhi deya abhi
Like kro nhi to fail ho jaoge
Mc
Bkl
Bkl
😂😂
Fail hona manjoor hai pr like krna nhi
Kl maths ka paper hai 😗
Haa apka standard hai ya basic
Meera basic@@Angelina-ik3vc
Kal Mera bhi math ka h rbse
Bfkndldncia'smcn ok z'jfbbzse Hindi full idiot Singh idk odik😅😊😂Odin 🎉😅😂
Rbsc bhi hota h 😂@@AnjaliPalawat
3:32 y-coordinate :- perpendicular distance for x-axis ..😊❤
Ritik sir always rock❤
The distance between the two points can be measured using the Distance Formula which is given by: Distance Formula = √ [(x₂ - x₁)2 + (y₂ - y₁)2]
Let the points be A(0, 0) and B(36, 15)
Hence, x₁ = 0, y₁ = 0, x₂ = 36, y₂ = 15
We know that the distance between the two points is given by the Distance Formula,
= √ [(x₂ - x₁)2 + (y₂ - y₁)2]....(1)
= √ (36 - 0)2 + 15 - 0)2
= √ [(1296) + (225)]
= √1521
= 39
Yes, it is possible to find the distance between the given towns A and B.
The positions of towns A & B are given by (0, 0) and (36, 15), hence, as calculated above, the distance between town A and B will be 39 km.
38:57 -
ii) Let A (- 3, 5), B (3, 1), C (0, 3), and D (- 1, - 4) be the four points of the quadrilateral.
We know that the distance between any two points is given by the distance formula = √(x₁ - x₂)² + (y₁ - y₂)²
To find AB, that is, the distance between points A (- 3, 5) and B (3, 1) by using the distance formula,
AB = √(3 + 3)² + (1 - 5)²
= √(6)² + (- 4)²
= √36 + 16
= √52
= 2√13 units
To find BC, that is, distance between points B (3, 1) and C (0, 3) by using the distance formula,
BC = √(0 - 3)² + (3 - 1)²
= √ (-3)² + (2)²
= √9 + 4
= √13 units
To find CD, that is, distance between Points C (0, 3), and D (- 1, - 4) by using the distance formula,
CD = √(- 1 - 0)² + (- 4 - 3)²
= √ (- 1)² + (- 7)²
= √1 + 49
= √50
= 5√2 units
To find AD, that is, distance between Points A (- 3, 5) and D (- 1, - 4) using distance formula,
AD = √(-1 + 3)² + (- 4 - 5)²
= √ (2)² + (- 9)²
= √4 + 81
= √85 units
Since, AB ≠ BC ≠ CD ≠ AD, therefore, no special quadrilateral can be formed from the given vertices.
iii) Let A (4, 5), B (7, 6), C (4, 3) and D (1, 2) be the four points of the quadrilateral.
We know that the distance between any two points is given by the Distance Formula,
Distance Formula = √ (x₁ - x₂)² + (y₁ - y₂)²
To find AB, that is, distance between points A (4, 5) and B (7, 6), by using the distance formula,
AB = √(7 - 4)² + (6 - 5)²
= √3² + 1²
= √9 + 1
= √10 units
To find BC, that is, distance between points B (7, 6) and C (4, 3) by using the distance formula,
BC = √ (4 - 7 )² + (3 - 6)²
= √ (- 3)² + 3²
= √9 + 9
= √18 units
To find CD, that is, distance between points C (4, 3) and D (1, 2) by using the distance formula,
CD = √(1 - 4)² + (2 - 3)²
= √ (- 3)² + (- 1)²
= √9 + 1
= √10 units
To find AD i.e. Distance between points A (4, 5) and D (1, 2) using distance formula,
AD = √( 1 - 4 )² + ( 2 - 5)²
= √ (- 3)² + (- 3)²
= √ 9 + 9
= √18 units
To find AC, the distance between points A (4, 5) and C (4, 3), we have
Diagonal AC = √( 4 - 4 )² + ( 3 - 5)²
= √( 0 )² + ( - 2)²
= 2 units
To find BD, distance between points B (7, 6) and D (1, 2), we have
Diagonal BD = √(1 - 7)² + (2 - 6)²
= √ ( - 6 )² + ( - 4 )²
= √ 36 + 16
= √52 units
Since AB = CD and BC = AD, but the diagonals AC ≠ BD, thus the quadrilateral is a parallellogram.
1:21:32 -
P, Q, R divides the line segment A (- 2, 2) and B (2, 8) into four equal parts.
Point P divides the line segment AQ into two equal parts.
Therefore, AP : PB is 1 : 3
Using section formula which is given by P (x, y) = [(mx₂ + nx₁) / m + n , (my₂ + ny₁) / m + n]
Hence, coordinates of P = [(1 × 2 + 3 × (- 2)) / (3 + 1), (1 × 8 + 3 × 2) / (3 + 1)] = (- 1, 7/2)
Point Q divides the line segment AB into two equal parts
Using mid point formula,
Q = [(2 + (- 2)) / 2, (2 + 8) / 2] = (0, 5)
Point R divides the line segment BQ into two equal parts
Coordinates of R = [(2 + 0) / 2, (8 + 5) / 2] = (1, 13/2)
1:58:24-
A rhombus has all sides of equal length and opposite sides are parallel.
Let A(3, 0), B(4, 5), C(- 1, 4) and D(- 2, - 1) be the vertices of a rhombus ABCD.
Also, Area of a rhombus =1/2 × (product of its diagonals)
Hence we will calculate the values of the diagonals AC and BD.
We know that the distance between the two points is given by the distance formula,
Distance formula = √( x₂ - x₁ )2 + (y₂ - y₁)2
Therefore, distance between A (3, 0) and C (- 1, 4) is given by
Length of diagonal AC =√ [3 - (-1)]2 + [0 - 4]2
= √(16 + 16)
= 4√2
The distance between B (4, 5) and D (- 2, - 1) is given by
Length of diagonal BD = √[4 - (-2)]2 + [5 - (-1)]2
= √(36 + 36)
= 6√2
Area of the rhombus ABCD = 1/2 × (Product of lengths of diagonals) = 1/2 × AC × BD
Therefore, the area of the rhombus ABCD = 1/2 × 4√2 × 6√2 square units
= 24 square units
bhai
December 2024 me kon dekh rha 😂
Me😊
Mee
Me abhi syllabus start kiya hai
Me😅
Bhai me to January me dekh rha hu 😅😅
Sir mera kl exam hai and now 1:01 AM
This is the third chapter after areas related to circle and statistics. 😂😂
Whose exam is tomorrow and watching this
Mara kl exam hai smj nahi aa raha kesse padhe kaha se start kare
@@priyanshipiyush high weightage vale chapter padh and half yearly ke NCERT pura kr ke jao. Usse at least concept clear ho jayega. And try your best 💪 and don't worry agr nhi hua toh yeh half yearly hi h boards mai achha perform krna baki all the best 😊😀
X coordinate -Perpendicular distance from Y-axis
Y coordinate -Perpendicular distance from X-axis
Mai kya hee bolu eatna aacha koi padha hee nhi sakta ❤❤😊
Kal exam hai aur aaj ye dekh rahe yaarrr🙂🥺
Kr bhi kya skte h 😂
Haa bhai mai ab dekh rha hu
Aaj Puri raat padhna padega syllabus complete krne ke liye brother meri fat chuki hai yrr
Ab kya kru kuch samjh nhi aa rha hai yrr
Toh kaisa hua exam kal to Mera last exam hai
Sir please April se new batch launch kardo jisme aap UA-cam par free main padhoa plz
Anyone come this video in October 😅😅 like nahi kiya toh fail ho gayoege
Anyone September 😅
😅😂
Ha Bro 🤣 only a revision purpose
Yes😅
🗣
21 September par 23 ko math ka exam h half yearly
Good explanation sir Amazing❤
39:31 answer (ii) no quadrilateral (iii) parallelogram
12:25 question 2 ends
13:23 question 3 ends
X cordinate is perpendicular distance from y axis
Y cordinate is perpendicular distance from x axis
Who wants babuaa in 11 class ❤❤
The answer of question 6th of part (ii) is No any quadrilateral and (iii) is Parallelogram.
1:05:04 ek exercise ki samapati hote hue👀👈🏻
Bhai kya hua, section fornula hi toh hai??
Dhanyawad sir ji ❤
29:01 Ve kamleya...😂😅
When is your maths paper in the bord exam ?
DDE5F44FVVRVV
1:21:29 P(-1,7/2)
Q(0,5) & R(1,13/2
Waah sir❤
Phir me a Gaya ❤
Question no 6
2nd one will not form quadrilateral
Reply karna plz
3rd one is a parallelogram
But why the 2nd is not a quadrilateral. May be it is a quadrilateral with unequal sides
sir exercise 7.2 ka Q5 mein section formula ke jagah midpoint formula bhi use kar sakte hain!!!!!!!!!!!!!!!!!!!
Thank u sir but solve all the problems not giving us homework 😅😅
Itna kaafi nhi hai kya ??
Sir you are best teacher in the world❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
You are the best teacher in the world
Haaaaaa
Please for 99.999%ka liya nahi to faul hojo gaya sahi ma ji😅
Like the comment if Ritik sir is the best teachers
👇
Sir you are the only hope for Class 10 students❤❤...just amazing teacher in universe🎉♡♡babua sir op😊
I think i am the only one who has not given the pre board exams. 🤫🤫🤫🥴
Hlo sir aap questions ko itna direct nhi kiya karo sache se samjh nhi aati plz full question karvaya kro ❤❤
Best of luck 🤞 for 11 March 2024
Same to you
U
1:47:37 😅😅 ye lologram kyu bolte ho😅😅❤❤❤❤❤
January mein syllabus kon kon nipta raha hai batch 2024-25
me
Meee
1:09:06
Day_Day_sir ji handsame hota jarha hai😊
Aaaaaaa haaaaaaa😂😂😂😂
Ex 8.3 Q-4 (x) Answer Done
I love you ritik sir ❤❤
You are a great teacher 😊
Chameli ko sab log maro usne ek question badha diya bechari champa ki baat mana karke 😂😂
😂😂😂😂
Anyone from 2024-2025
❤
Yup
Yes bro
Yes
Yes
Time to gear UP dosto⚡⚡
Sir you are best teacher of maths becuse earlier i used to be scared of math but now i don't feel scared at alll 😊😊😊
Kis kis ko ab dar lag raha hai😢
Mujhe 🥲
Mujhe 😢
100 aa rha hai
Bhai mujhe 😢😢😢
Bilkul nhi lag raha kahi mai Boardphilic to nhi 😅
Basic Wale😂 like kro❤
Yaar kuch nhi padha bohot dr lg rha 😢😢
hiiiiiiiiiiiiiii
To padho😢
1 like got in maths 75 plus
Me watching this one day before pre board
Me watching 1hr before pre-boards
*_Thankk youuu sooo much Sir_* 👍🏻✨
J k Bose ka paper kal ha ❤😢😢
AAKHRI DIN MATHS KA😌♥️🥺
Same bhaii 😢
😂
Anyone from October?😂
Yup
Yes brother 😂
@theKalYugBoy1 yup
Me 😂
Haa vo bhi last month
Thanks sir your video is very helpful for me ❤
Thank you sir🙏🙏
1:08:43 😂😂best sir bestt😂😂😂😂
Who like PW more than school Teachers ❤❤
Mujhe
I like my math teacher by pankaj sar❤❤
Thanks so much ❤❤
𝙹𝚔 𝚋𝚘𝚜𝚎 𝚊𝚗𝚢𝚘𝚗𝚎...?
Me I'm from shupiyan ❤️💕💖💖
Sir aap bohot ke atcha padata ho 😊😊
Ritik sir rocked others mathematics teacher socked 😂😂
Dhanyawaad batane ke liye aangrej ki aaulad 😂❤
Kya hoti hai spelling bta bi dete bhaiya
Ok thank you by the way pura sahi likha vo nhi dikha ek spelling mistake ho gayi vo dikhi matlab yeh hai ki log galat chijo ko jayada dekhte hai
B@adityabhadu8249 but thank you and all the best for your board exam 😍🥰
@@priyanshu_rwt 10th m aa gya hai... Itna toh aana chahiye
Sir next level understanding sir apki vjh se hi kl preboards me marks ane wale h 🙏🏻🥲🫂
Basic wala like karo
Do only ncert question bro
Lo.10 rupees 😂😂😂
Tip
Ncert enough hai basic valo kae liye 😢?
😊 39:56 It is a lologram
Like for will be a topper 😂😂😂
Love you sir❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Babua board exam ka dar lagna start hone laga hai😢.
😮
6)i. Square,
Because all sides are equal and diagonals are equal.
1:51:24 A And 'b are gay 😂😂
Aree 😂😂
@@AnimefanboyNAHIBTFANBOYBOLTEhi bro
Hi
Respectively 😂😂
💀💀