Procedurally Modeling an Abstract Container | Houdini 19.5

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  • Опубліковано 30 лис 2024

КОМЕНТАРІ • 7

  • @philippwelsing9108
    @philippwelsing9108 Рік тому

    Amazing, thank you very much! I love modeling in Houdini. Very happy about every modeling tutorial.

  • @daggergblue
    @daggergblue 18 днів тому

    Wouldn't it be wise to delete all the empty groups in the clean node? Or do they come back into play further on down the line?

  • @firdavsavezov9947
    @firdavsavezov9947 Рік тому

    Hi. I dont know why but I dont have the node called Transform from centroid, just the transform itself. is it because I am using the apprectice Houdini?

    • @InsideTheMindSpace
      @InsideTheMindSpace  Рік тому

      I'm not sure but the transform from centroid is just the regular transform node with a preset. You can recreate it by going to the pivot transform setting and setting the pivot translate to centroid(0, D_X) in the x value of the pivot translate. You also need to put that same expression in the y and z values but you change the D_X to D_Y and D_Z respectively

    • @firdavsavezov9947
      @firdavsavezov9947 Рік тому +1

      @@InsideTheMindSpace Yay! It worked! Thank you very much)

  • @ahmedalnaseri7
    @ahmedalnaseri7 Рік тому

    nice tutorial man , so quadremesher need a License to use it correct ? if so i think its price is just too much for one function if i understand it well

    • @InsideTheMindSpace
      @InsideTheMindSpace  Рік тому

      It does require a license but the license is perpetual or was when I got my license. The results of the remesh operation are far better than anything else I have used as far as automatic retopology tools go. It has saved me countless hours over the years. It is personal opinion though whether you think it's worth it and Houdini does have its own remesh node so you don't need it if you are ok with the results that the remesh node offers.