A few people are confused about the conversion of.......1/D nm-1 into 1/r. You need to divide the 1/D values by 2. The formula for the conversion is 1/r = 1/D × (L / λ) / 2. Where: 1/D is the reciprocal space measurement in the SAED pattern. L is the camera length of the TEM. λ is the wavelength of the electron beam. The reason for dividing by 2 is that the diffraction spots in a SAED pattern correspond to the scattering vector, which is defined as: q = 2π / d. Where d is the real-space interplanar spacing. Thank you in advance
Thank you for making this very informative video. I would like to thank you from the bottom of my heart. and one request is to please, kindly make one video on monocrystalline TEM SAED pattern analysis and spacing.
1/r = 2(1/2r) Therefore, when calculating (1/r), you should have multiplied (1/2r) x 2, but I noticed that you are dividing by 2. Can you explain that please?
You are right, But his is not the mistake. The actual mistake is, I measured 2R but mistakenly labeled it as 1/2R in the first place and then use R instead of I/R. However, the method and calculation is accurate. But you need just to consider the 1/2R as 2R, 1/R as R.
Can I know why the biggest radius on the small circle or inside circle. Instead of outer circle? Suppose (200) should be place at outer circle. I am new to this can you clarify.
Thank you for the tutorial, the math for converting 1/2r into 1/r may not be right. I think you are supposed to multiply not divide by 2. i.e 1/2r is a smaller value than 1/r. please check, thank you for the information
Excellent video, covered every aspect. I have one question kindly respond to clarify concept of the community. Right from the start, obtaining 1/2r, till matching d spacing you video is very coherent. However, to obtain 1/r (2nd column of the table) from 1/2r, instead of dividing it by 2 (which you did), should we not do the multiplication? i.e. 1/2r * 2 = 1/r
While indexing Miller indices in Microsoft paint, you have indexed the plane corresponding to the least r-value to the outermost circle. I am confused at this point.
Sir.. please help me to analyse .. I calculated the d spacing but due to lack of jcpds card, I couldn't do it.. will you please provide your email address?
Thank you very much Sir. Please do make more videos on Characterization to help people like us. You are a very good teacher.
Really Very helpful videos.........
Clearly explained all things that we have to do
A few people are confused about the conversion of.......1/D nm-1 into 1/r. You need to divide the 1/D values by 2. The formula for the conversion is 1/r = 1/D × (L / λ) / 2. Where: 1/D is the reciprocal space measurement in the SAED pattern. L is the camera length of the TEM. λ is the wavelength of the electron beam. The reason for dividing by 2 is that the diffraction spots in a SAED pattern correspond to the scattering vector, which is defined as: q = 2π / d. Where d is the real-space interplanar spacing. Thank you in advance
Thank you for making this very informative video. I would like to thank you from the bottom of my heart. and one request is to please, kindly make one video on monocrystalline TEM SAED pattern analysis and spacing.
Noted
Very Informative video. Sir please put this type of analysis for all characterization methods
1/r = 2(1/2r) Therefore, when calculating (1/r), you should have multiplied (1/2r) x 2, but I noticed that you are dividing by 2. Can you explain that please?
Yes. I also noticed this.
Why you divide 1/2r values to find 1/r values ?
It should be multiplied by 2 not divide
from C column to D column , it should be 1/2r *2 = 1/r
You are right,
But his is not the mistake. The actual mistake is, I measured 2R but mistakenly labeled it as 1/2R in the first place and then use R instead of I/R.
However, the method and calculation is accurate. But you need just to consider the 1/2R as 2R, 1/R as R.
@@nanoworld6122 yes.. i was wondering the same thing
How pair hkls, When more than one hkl for a calculated d spacing?
If the d spacing lower than 1A
How to identify the hkl?
Thank you very much for the tutorial. Please make a video about the SAED pattern of LRTEM. There is no scale in the SAED pattern
Please make a video on Single-crystal SAED pattern as well!
Noted
Waiting
Could you please also make a video on how to index spot diffraction pattern? Really appreciate it.
hello there, do you know how to index spot diffraction pattern?
thank you for the useful and complete information.
Many thanks. Please make a video on the Single crystal SAED pattern .
Thank you for the informative video.
Why didn't you use the formula L•lambda=R•d to find d - spacing?
Is this that you are mentioning the bragg equation?
Hello sir, will you plzz make a vedio on the wemple -Didomenico for determining the non- linear refractive index
Can I know why the biggest radius on the small circle or inside circle. Instead of outer circle? Suppose (200) should be place at outer circle. I am new to this can you clarify.
no tienes el word editable ?
Nano world plz make such more videos
Thank you for the tutorial, the math for converting 1/2r into 1/r may not be right. I think you are supposed to multiply not divide by 2. i.e 1/2r is a smaller value than 1/r. please check, thank you for the information
I think you are right, if 1/2r=n; then 1/r=2n.
But then why it seems to be right when compared with the standard values in the card?
Going from 1/2r to 1/r, you should have multiplied 2 not divided 2. I do not know how you got the right answer?
Thanks a lot, very well explained.! Regards from Mexico
I do not have any access to the JCPDS card for my use !! Is there any public domain from where I can access the JCPDS file ?
Very helpful session
How to get the jcpds card can you provide the link of your video in comment box?
i need setup of xprethigh schor e may you provide me??
Why did you divide 1/2r to find 1/r?????
Sir, 1/r = 2 times of 1/2r . Then How you did the half of 1/2r for 1/r ???
Sir pls upload more tutorials. Pls upload Vesta software tutorial.
Excellent video, covered every aspect. I have one question kindly respond to clarify concept of the community. Right from the start, obtaining 1/2r, till matching d spacing you video is very coherent. However, to obtain 1/r (2nd column of the table) from 1/2r, instead of dividing it by 2 (which you did), should we not do the multiplication? i.e. 1/2r * 2 = 1/r
Kindly provide the JCPDS No for MXene..wonderful video
You are doing really nice work.
Thank you! Cheers!
How can we interpret the HRTEM images of nanoparticles and quantum dots..? Can u explain it in hindi..?
Great explanation, Can I have JCPDS file for Bi2O3
While indexing Miller indices in Microsoft paint, you have indexed the plane corresponding to the least r-value to the outermost circle. I am confused at this point.
Hi can u pls provide jcpdf of 15-0087.
Nicely explained work . Thanks 🎉🎉
Thanks and welcome
Thank for your tutorial, it was very helpfull!
You are welcome!
Sir wht ll b d next video. Pls upload next one.
Please do a vdo on ac conductivity fitting and how to calculate the atomic positions of a sample for rietveld refinement. Pls. suggest the site.
Noted
Hi, could you please share me the terbium JCPDS data?
Very brilliant video. But I am wondering if I am wrong about the 1/2r and 1/r in relative values, if anyone can tell.
I am also think that, 1/2r=a => r= 1/2a, but in this case r is calculated reversely
1/2r is not a 1÷ (2r) its 2r in reciprocal plane
please gave information that my XRD data match with which number JCPDS FILE NUMBER
Thank you very much for the video sir
Hello sir can you provide jcpds card
Respected sir can you please provide me this standard values card ..???
Thankyou sir your vdieo help me alot❤
Very useful videos, go ahead.
Many many thanks
JCPDS 44-0141 ?? can u pls share the jcpds file of alpha- MnO2
Please upload the videos on d spacing calculation from HRTEM image and XPS convolution and deconvolution
Thank very much for your usefull video
Thank you for this video. Can I have JCPDS file for Mn2o3 and MnO
Thank you!! God bless you!
Excellent! Thank you
You are welcome!
Why d=1/R ?? I only know that d.R=L.landa
Could you tell my why L.landa=1 ?
Plz make more videos.Very less videos on this channel are.
Could you please provide jcpds file of reduced graphene oxide and graphitic carbon nitride
Thank a lot sir
Thank you. awesome!
Glad you liked it!
When saed scale is 10 1/nm then what will be the calculations and to decide that?
just in the Image-J, Analysis>set Scale change 2 to 10. the rest of the process remains the same
Thank you so much your video is wonderful.
Great job sir
Thanks
Required JCPDS Card.
Thank you for this tutorial. Kindly give me all values for PCMO , jcpds no. is 89-795. Also for BCMO Jcpds no. is 57- 767.
Awesome..Really helpful...
Glad to hear that
Glad to hear that
Please make video for how to index spot pattern for HRTEM
Thank you for this video
Thank u so much for your guide sir. Sir, do you have JCPDS card no. 52-0875 for Ti3AlC2?
email respomded
@@nanoworld6122 Thank u so much sir, This really helped my research
Please provide data for JCPDS file No. 290914
Thank you soo muchh sir...can you please provide jCPDS card of Ceo2
no
How to index saed of crystalline materials
This video was for polycrystalline SAED pattern. However, I will upload soon a video on the interpretation of single crystalline SAED pattern.
@@nanoworld6122 Thanks a lot! I am looking forward to watching your new video.
Thank you sir. We are eagerly waiting for this.
Thank you.
Thank you sir
Thanku sir very informative video. Sir please send me the JCPDS File for ZnO
Thank you!!
Welcome!
Analyse single crystal SAED pattern!!
I will upload soon
Plz prof, could you send me a JCPD card of graphene oxide?
Thanks for the tutorial, it was helpful. Can you please help me in my SAED pattern through mail, I have some specific questions about it.
thats great
jcpds card no- 411445 for sno2
Sir.. please help me to analyse .. I calculated the d spacing but due to lack of jcpds card, I couldn't do it.. will you please provide your email address?
email address is available at the end of video.
@@nanoworld6122 got it sir❤️🔥
What is your email ID?