Permutations and Combinations Tutorial
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- Опубліковано 9 лют 2017
- This video tutorial focuses on permutations and combinations. It contains a few word problems including one associated with the fundamental counting principle. Permutations are useful to determine the different number of ways to arrange something where as combinations is useful for determining how many ways to combine something when the order does not matter such as selecting members to form a committee. In a permutation, the order matters. Examples include repeated symbols or arranging letters in a word such as alabama or mississippi. This video also discusses the basics of permutations and combinations using letters such as ABCD.
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Intro to Statistics:
• Introduction to Statis...
Probability - Basic Intro:
• Introduction to Probab...
Binomial Theorem:
• Binomial Theorem Expan...
Permutations and Combinations:
• Permutations and Combi...
Factorials Explained!
• Factorials Explained!
__________________________________
Parametric Equations:
• Parametric Equations I...
Ellipses - Conic Sections:
• Writing Equations of E...
Hyperbolas - Conic Sections:
• Hyperbolas - Conic Sec...
Parabolas - Conic Sections:
• Finding The Focus and ...
__________________________________
Arithmetic Sequences:
• Arithmetic Sequences a...
Geometric Sequences:
• Geometric Series and G...
The Fibonacci Sequence:
• Mathematics - Fibonacc...
Mathematical Induction:
• Mathematical Induction...
Induction Divisibility:
• Induction Divisibility
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But us we did permutations with and without repetitions
Why am i only seeing without repetitions
Deeply explain the concept and also simple and easy to understand
2 hours before a test and i always find myself here
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This man just taught me permutations and combinations in 7 minutes when my teacher couldn't do it for an hour.
I would like this comment, but I see it is at 69. Nice.
@@joshr.5199 it's now 169
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@@weyden7590 176
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I'm in grade 9 when I learn this in school, this is not fair
This is not permutation, but variation vs combination. He did not say anything about permutations!
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"0 factorial does not equal 0, 0 factorial equals 1...if you're wondering why.... that's just the way it is. I don't have an answer for you." 10:52 Savage LOL
That was awesome LOL
The reason why 0! Equals 1 is because when you do 0!= 1!/1! (One factorial over one factorial) it just cancels out to 1. It’s the same if you were to do 2!=3!/3!. When you expand the equation, You would cancel out the 3 on the bottom with the three on the top and be left with 2 times 1 which, of course, is 2!
@@prncess1848 u explained it right except that " 2!=3!/3! " should not have factorial in the denominator, thus it would look like " 2!=3!/3 "
standard formula would be
n! = (n+1)! / (n+1)
Just think, how many ways are there to arrange 0 objects, there's one way, just like that...
@@neeraj8278 exactly lol.
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I myself also come to videos like these just to repeat basics. In the end basics can't be mastered too well
This is not permutation, but variation vs combination. He did not say anything about permutations!
Hey, Can you please tell me what topics should i study to become a quant?
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it eezz what it eezz
its kinda hard, because hes just saying the formula, but it would have been nice if he explained why it is that way and how he got there
its better teaching
its because you can arrange the set { 0 } in 1 way
okay so why is 0! = 1?
4! = 4 x 3 x 2 x 1 = 24
3! = 3 x 2 x 1 = 6. We divide 4 from 4!.
2! = 2 x 1 = 2. We divided 3 from 3!.
1! = 1, dividing 2 from 2!
0!???, divide 1 from 1!, its still one
it's means don't ask anymore questions🤣
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I love how he explains the difference between permutation and combination. It took a me a couple example to finally grasp the advantage of using the formula provided. Not only it made bigger equations to solve but instead of drawing them out which could take longer. The recognition of the two different problems is also an important factor because you don't want to end up using the wrong formula
Jamie Toloa
Same ! I didn't know the difference
That's my issue. I understand everything and how to do it. But I don't understand how to know which one to use and to recognize the two types of problem
Same here
I’m now okay
arrange=permutations
4:33 - calculating permutations
6:00 - calculating combinations
7:36 - sample questions + working
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This is the first explanation of permutations and combinations I've seen, that actually explains the difference between both!!!
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If you want some more practice, you might want to check out my latest upload, where I solve such exercises step-by-step:
ua-cam.com/video/siSc7VEfG3c/v-deo.html
:)
I remember my calculus professor proved to us why 0! = 1 and it was mind blowing. Loved that professor.
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This helps! Thank you. I'm struggling in Probability at my university, and I thought the "P" in nPr meant Probability, not Permutation. That explains a lot.
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Thank you so much for this. This summarizes these concepts so much better than reading through broken notes over multiple days. I have an exam on this tomorrow so this is a lifesaver, as permutation and combinations are my weakest units.
How did the exam go?
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Where did he get 4 and 2
i subed to u
For anyone looking for an (in my opinion) an easier way to calculate the r-Permutations:
P(n,r)
For example:
P(4,3)= 4x3x2
p(8,5)= 8x7x6x5x4
So the r is actually just the number of times you need to multiply down. So in the first example, we multiply down 3 times, where as in the second one we multiply 5 times.
An easier way (in my opinion) to do the equation for r-Combination is:
C(n,r) = P(n,r)/r!
For Example:
C(6,3) = P(6,3)/3!
P(6,3) = 120 (6x5x4)
120 / 6 (3! = 3x2x1)
C(6,3) = 120/6 = 20
A second example:
C(7,2) = P(7,2)/2!
P(7,2) = 42 (7x6)
42 / 2 (2! = 2x1)
C(7,2) = 21
A third example:
C(8,3) = P(8,3)/3!
P(8,3) = 336 (8*7*6)
336/6 (3! = 3x2x1)
C(8,3) = 56
Hope this helps.
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This is by far the best permuations and combinations tutorial I have found on this cite. Thank you thank you thank you. Phenomenal work sir please keep putting out this quality content.
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