Dropping a Ball from 2.0 Meters - An Introductory Free-Fall Acceleration Problem

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  • Опубліковано 11 січ 2025

КОМЕНТАРІ • 69

  • @creumakuzola4227
    @creumakuzola4227 4 роки тому +6

    So clear, and funny at the same time. I really didn't felt the 12 minutes passing away . This is an excellent video. Thank u, so much.

  • @Ray-mz4hd
    @Ray-mz4hd Рік тому +3

    god i wish you were my professor. I know these videos are old but they're quite honestly saving my grade in physics

    • @FlippingPhysics
      @FlippingPhysics  Рік тому +2

      Glad to help. FYI: This physics hasn't changed in the last 10 years and, I'm pretty sure on this one, won't change for the next 10 either!

  • @clchristian1
    @clchristian1 9 років тому +12

    Excellent video Flipping Physics! Thank you so much for not only going through how to do it step-by-styp, but also explaining the common mistakes that students make-- that part was the most valuable for me. Thanks for your clear and humorous help!

    • @FlippingPhysics
      @FlippingPhysics  9 років тому +4

      +christian lin "clear and humorous help" is exactly what I am going for. You are welcome!

  • @arsenal78910
    @arsenal78910 6 років тому +4

    Love it when you drop these big SAT vocab words in your lectures. I keep googling what they mean!

    • @FlippingPhysics
      @FlippingPhysics  6 років тому +1

      I totally forgot I used to do that! I need to do that more often now.
      Thanks for the reminder!

    • @arsenal78910
      @arsenal78910 6 років тому

      For sure. Looking forward to it. Thanks for your hard work!

  • @sombojoe
    @sombojoe 5 років тому +2

    Love the parallax reference... The only time outside of firearm optics that I’ve ever heard this term used. :)

  • @andresdelaraza
    @andresdelaraza 9 років тому +1

    Bobby's face at 9:00. This is entertaining, and informative.

  • @michaeljohnhigh8298
    @michaeljohnhigh8298 8 років тому +8

    8:28 that guy is a human calculator, that's why he doesnt have one.. lol

    • @BingBangBrine
      @BingBangBrine 4 роки тому +1

      human is better than a calculator you know

  • @iresharachchige9134
    @iresharachchige9134 9 років тому +2

    as always tanx for teaching

    • @FlippingPhysics
      @FlippingPhysics  9 років тому

      +iresh arachchige I am glad you appreciate it.

  • @MortalH
    @MortalH 2 роки тому

    Being perspicacious, you missed a phrase at 7:46 " Actually, now that we know four of our UAM equations there are three equations we could use, right?"

    • @FlippingPhysics
      @FlippingPhysics  2 роки тому

      I do not know what this means. Enlighten me?

    • @MortalH
      @MortalH 2 роки тому

      @@FlippingPhysics Oh, I was just trying to apply some of the vocab you put in the video; I apologize for not being clear. In other words, I believe that it should say that there are 4 known UAM variables so we can use 3 UAM equations rather than the initial statement: 4 known equations allows 3 equations to be used.

  • @owaisahmedkhan8293
    @owaisahmedkhan8293 8 місяців тому

    Are the variables in uniformly accelerated motion equations scalars or vectors? Wherever I see the equations, there is no arrow on top of the variables but they seem to be a vector. Can you clarify what are they?

    • @FlippingPhysics
      @FlippingPhysics  8 місяців тому

      With the exception of time, the other four variables are vectors. Not writing them with vector symbols is often done to save time, however, they are vectors.

  • @xXWhatever13Xx
    @xXWhatever13Xx 4 роки тому

    Came to learn how to solve a simple ball dropping problem and left learning the whole concept and a new word: "eschew" XD
    Also, I am immediately a fan and LOVE that you have different tie dye on in every video for both you and "Bo". Have you ever tried ice dye? :) That's the method I use for all of my tie dye I sell.

    • @FlippingPhysics
      @FlippingPhysics  4 роки тому

      I have tried ice dye, however, I have not been very happy with the results. Do you have a particular method you like which you can point me towards?

    • @xXWhatever13Xx
      @xXWhatever13Xx 4 роки тому

      @@FlippingPhysics I don't want to share all my secrets since I sell tie dye shirts as well, but I can suggest a few tips. If you don't already, try soaking the shirts in soda ash (Sodium Carbonate) before doing any dyeing. I'd recommend starting with a classic spiral (since they are the easiest to work with) and leave the rubber bands off.
      Put a "fence" of cardboard around the shirt and choose how loose or how tight your want your fence around the shirt to be. This will determine how much dye will soak through to the other side which will determine how much white your shirt will have between folds. Put the dye on as a powder, put on the ice, and wait until the next day to rinse :) I'd recommend using color schemes that blend well since the colors will blend more.
      If you'd like more tips or would like to see how my process works out, check out my portfolio on Instagram : @thedyeintist . There you can see examples of how they turn out for me, which could maybe give you an end concept to work towards.

    • @FlippingPhysics
      @FlippingPhysics  4 роки тому +1

      Thanks for the tips. The "fence" things was the only part of that I was not doing. I'll give it a try next time.

    • @xXWhatever13Xx
      @xXWhatever13Xx 4 роки тому

      @@FlippingPhysics Hope it helps and works out for you. I'd love to know how it works out.

  • @nikhilsingh5863
    @nikhilsingh5863 9 років тому +1

    Great video as usual, but i was wondering, since we are finding the final velocity before the medicine ball hit the ground, isn't 2.0 meters the wrong displacement?

    • @FlippingPhysics
      @FlippingPhysics  9 років тому

      ***** Interesting. Do you mean the displacement in the y direction should _not_ be negative 2.0 meters? What would the correct displacement be then, if not negative 2.0 meters?

    • @nikhilsingh5863
      @nikhilsingh5863 9 років тому

      WOuldn't it be a little less because we are measuring the final velocity before it hits the ground?

    • @FlippingPhysics
      @FlippingPhysics  9 років тому +1

      ***** The key phrase here is "right before it hits the ground". Therefore, the magnitude of the displacement in the y-direction is _infinitesimally_ smaller than 2.0 meters and therefore is 2.0 meters. :)

    • @nikhilsingh5863
      @nikhilsingh5863 9 років тому

      So we assume it is 2.0 meters due to the difference being too small to matter? That cleared a lot up; thanks so much for all your videos. They are really helping me prepare for physics 1 next year

    • @FlippingPhysics
      @FlippingPhysics  9 років тому +2

      ***** Yes, 2.0 meters - an infinitesimally small number = 2.0 meters. Good luck in AP Physics 1 next year, it's a fun class!

  • @HardikPatel-kx3re
    @HardikPatel-kx3re 4 роки тому

    Thanks for this video. When we try same experiment at home with dropping golf ball from 4 meter, our time is less compared (.8) with above formulas (.9 sec). Does weight of free falling object mater?

    • @FlippingPhysics
      @FlippingPhysics  4 роки тому

      I am guessing the issue is with the precision of your timing mechanism. The mass does not affect an object in free fall like this.

  • @thisexists6588
    @thisexists6588 24 дні тому

    I keep getting frustrated bc I spend like 10 minutes trying to rationalize how this works for my notes bc I’m homeschooled so there’s no teacher (aside from this video : D ) telling me what I’m supposed to do. Just for 5m later to get told it was a mistake and I have to go undo all my notes and rewrite my mental path. Great material, just wish that one thing was different 😅

    • @FlippingPhysics
      @FlippingPhysics  24 дні тому

      Learning what happens when you make mistakes is crucial for understanding physics. That's why I put them in here. Also, you should always be thinking through everything and doing your best to find the mistakes before I point them out. Best of luck with the homeschool physics learning!

    • @thisexists6588
      @thisexists6588 23 дні тому

      @@FlippingPhysics I find them almost every time but end up gaslighting myself out of it and trying to come up with creating a complex reason why it would be that way. I try my best not too but for me personally I just second guess myself too much for it to be useful 😅. But these are the best high-school level physics videos I’ve found! The descriptions are clear and to the point.

  • @بوزيدأمينأستاذالعلومالفيزياء

    Thank you so much , God bless you

  • @Devanshgupta
    @Devanshgupta 6 років тому +1

    Sir, can I take 'down' as positive?

    • @FlippingPhysics
      @FlippingPhysics  6 років тому +1

      Yes, you _can_ take down as positive.
      However, my suggestion is that you _not_ take down as positive.
      In my experience, keeping the standard up=positive, down=negative, right=positive, left=negative, makes thing less confusing in the long run.
      (When it gets to pulleys, this changes slightly, however, you are not there yet.)

  • @panickmonstar4585
    @panickmonstar4585 5 років тому

    hey sir can you tell me why we use 'u' for initial velocity please.............

    • @FlippingPhysics
      @FlippingPhysics  5 років тому

      Considering I have never used 'u' for initial velocity, I cannot.

    • @panickmonstar4585
      @panickmonstar4585 5 років тому

      @@FlippingPhysics thanks for your feed back

    • @carultch
      @carultch 3 роки тому

      @@panickmonstar4585 The u and v are alphabet neighbors. Some books/instructors opt to use u and v to stand for initial and final velocity respectively, in order to avoid the need for subscripts. Another choice of variable name that is seemingly inconsistent with its concept name, is s for distance/displacement. This is due to the d already having another full time job in calculus, where these equations are derived, so the next consonant in distance/displacement is selected instead.
      If for some reason you prefer a different use of the alphabet than your class uses, start your solution with a few lines to briefly identify your notation. Such as "let u = initial velocity, and let v= final velocity".

  • @yasinozkan
    @yasinozkan 5 років тому

    Is this calculated without air resistance ?

    • @FlippingPhysics
      @FlippingPhysics  5 років тому

      Yes. Air resistance makes things much more complicated. www.flippingphysics.com/the-euler-method.html

  • @uniondude3758
    @uniondude3758 7 років тому

    Can an object in free fall do work & remain @ free fall acceleration?

    • @carultch
      @carultch 3 роки тому

      Free fall is by definition, a condition that lacks all other forces than gravity.
      An object in free fall, can only do work on the gravitational field, and have the gravitational field do work on it. The only energy exchange that can happen during free fall, is the exchange between KE and GPE. Since no other forces act on it, it cannot produce another force that acts on something else in order to do work. It can do work while it comes to a stop upon landing, but then it is no longer in free fall.

    • @uniondude3758
      @uniondude3758 3 роки тому

      @@carultch Thank you for clearing that up.

  • @kylebujinkan
    @kylebujinkan 10 років тому

    hey thanks for the cool vid, please can you explain as to why gravity is -9.81m/s down and not a positive, how would you work out the average acceleration of a ball thrown up and then down again into your hands?

    • @FlippingPhysics
      @FlippingPhysics  10 років тому +1

      A UA-cam comment isn't really the vehicle for answering your questions, however, I have videos that answer them. Here two suggestions:
      1) Introduction to Free-Fall and the Acceleration due to Gravity ua-cam.com/video/vyvDzI22sOE/v-deo.html
      2) Common Free-Fall Pit Falls ua-cam.com/video/GDUdUumkv0o/v-deo.html

  • @oxivonodd6880
    @oxivonodd6880 7 років тому

    thank you!

  • @joanferreira3896
    @joanferreira3896 3 роки тому

    Thank you

  • @sivakumarsiva1743
    @sivakumarsiva1743 6 років тому

    Isn't s = -2 since it is going down

  • @StuartBermingham
    @StuartBermingham 10 років тому +2

    Lol wait a sec you're all the same guy?

    • @FlippingPhysics
      @FlippingPhysics  10 років тому +4

      Wait a sec, are you NOT all the same guy?

  • @MrHugosantos1982
    @MrHugosantos1982 10 років тому +1

    No shoes and funny socks.

  • @retooluvyuhx5569
    @retooluvyuhx5569 7 років тому +1

    THE PHYSICS WORKKS!! AHAA AHAAA
    well I don't think my brain does. I need to replay the video

    • @FlippingPhysics
      @FlippingPhysics  7 років тому +1

      Much easier than trying to replay a lecture.

  • @BingBangBrine
    @BingBangBrine 4 роки тому

    good good good

  • @christianfurness1925
    @christianfurness1925 5 років тому

    This is boring