Common Emitter Amplifier - Part Selection - Simply Put

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  • @stringlesswonder
    @stringlesswonder 3 роки тому +6

    I have been watching videos about biasing simple bjt transistors and choosing the values of the components around them for several years, and never really understanding what I was doing. After watching these three videos, and wondering if he really was going to say everything 47 times, I realize I am much closer to really getting this. Not just being able to do it, but getting it. I figure another 3-4 watches (3+4/2=3.5x47=164.5 times) and I will have it. Thank You! Looking forward to what else you might get through my thick skull.

  • @malcolmhodgson7540
    @malcolmhodgson7540 2 роки тому +2

    At long last someone bothered to explain the load resistor and that makes the rest of the design crystal clear. I literally want to shake your hand right now, but please take a heart felt thank you from me for such a brilliant tutorial. I’m off to burn out some 2N2222s tomorrow just to proveI now understand where the various voltages and currents come from! You feel free to have a virtual beer from me! Now I shall hit the subscribe button and the thumbs up. Can’t wait to work through your other tutorials, you teach so practically.

  • @TheNaboen
    @TheNaboen 2 роки тому +3

    What an educational achievement! I have never learned so much in such a short time. And I have a brain that is not really wired for this type of knowledge

  • @JDPavon
    @JDPavon 5 років тому +1

    I have seen many videos and I have tried to do the same things, but without results. until I've studied the three videos on common emitter amplifier. It has become clear to me the reason and the reason for the different components in this type of circuits. Many thanks.

  • @generalleigh7387
    @generalleigh7387 Рік тому

    I appreciate your humor, thank you so much for taking the time through this. The comments show that this video is a bit an oasis, thanks!

  • @pikor69
    @pikor69 Рік тому

    Finally something what works for me. Thanks!

  • @warplanner8852
    @warplanner8852 Рік тому

    Was hanging on by my fingernails (but hanging on) and then came your blessed summary!
    Yowzah!
    A keeper! You are terrific!

  • @leeaudio027
    @leeaudio027 3 роки тому

    Love your explanations man great job.super awesome

  • @user-ob3fx5lp6u
    @user-ob3fx5lp6u 2 роки тому

    I feel blessed to find your channel!

  • @simonlinser8286
    @simonlinser8286 Рік тому

    this guy is like a professor great stuff

  • @gloubiboulgazeblob
    @gloubiboulgazeblob Рік тому

    10µF indeed provides a better sound with less distortion, I've tried the same circuit (except for the transistor which is a BC547) and it works quite well actually ! Thanks man !
    I wish there was much more on this, to make a real amp, but hey, that's cool man !

  • @geodome99
    @geodome99 Рік тому

    Better late than never.
    Thank You

  • @DashkaMilashka015
    @DashkaMilashka015 Рік тому

    wow. you're so good at this. can it even get any better..?

  • @shvideo1
    @shvideo1 3 роки тому +1

    An awesome video. Really enjoyed it. My understanding is that the VCE voltage is about 0.3 V and even much higher for power transistors. Why don't you consider this voltage? It's somewhat significant, and is certainly not zero. It should not be forgotten or left out. I would appreciate a response to clarify this for me. Thank you for all your efforts. Love your stuff.

  • @profrobinson
    @profrobinson Рік тому

    Good course! How we do calculate on + and - power supply?

  • @michaelrobertson575
    @michaelrobertson575 3 роки тому

    Well done!
    It's very clear.
    Your Volume Control seems a little strange as most folk would ground one end of the Potentiometer Track so that it can be turned all the way down.
    Also an Eight Ohm Loudspeaker seems rather too heavy a load for this circuit although it would probably work to some degree.

  • @fredflickinger643
    @fredflickinger643 Рік тому

    Consider the venerable 2N2222A Small−Signal Current Gain
    (IC = 1.0 mAdc, VCE = 10 Vdc, f = 1.0 kHz) (IC = 10 mAdc, VCE = 10 Vdc, f = 1.0 kHz)
    hfe
    50-75 (Min)
    300-375
    (Max)

  • @deepakjanardhanan7394
    @deepakjanardhanan7394 Рік тому

    Hi it has been two years sir. No new uploads?

  • @harshgandhi100
    @harshgandhi100 2 роки тому

    But what about input impedances? Is it Line level? It does seem like a line level. Either you are pretty lucky to choose this load or you just tested a lot.

  • @JDPavon
    @JDPavon 5 років тому

    Hi, I get loss in the 17:54 minute,
    did you say that 1.7v divided by (10 times 85u Ibq) is equal to 1990Ohms..?

    • @simplyput2796
      @simplyput2796  5 років тому +1

      85 microamps was rounded a little for clarity. The actual exact resistance was 1997 ohms. The reason I used 1800 ohms for the actual resistor was that I wasn't using a trimpot to get an exact resistance: I was using just a standard box of resistors, and 1800 was the closest one that was no higher. The resistors R1 and R2 form the bias part of the amplifier, and they have to supply a minimum amount of current to the transistor's base, which means it is perfectly fine for them to be lower than needed (excess current), but it is not fine for them to be higher than needed (not enough current available), so I went down to the closest available discrete resistor value available to me.

    • @JDPavon
      @JDPavon 5 років тому

      @@simplyput2796
      Thanks for answering me.
      I'm doing and studying the same circuit and learning a lot.
      Thank you. By the way ... could you explain how to do an amplification but with
      an operational amplifier. I understand that it's simpler, but I like the way you explain every detail.
      As always many Thanks.

    • @simplyput2796
      @simplyput2796  5 років тому

      Yep, op-amps are coming! I have several other types of amplifiers to work my way through first, but they're in the pipeline.

    • @JDPavon
      @JDPavon 5 років тому

      @@simplyput2796 Goooood

  • @ruben.9903
    @ruben.9903 4 роки тому

    I don't understand why you say that the speaker uses 0.25 watt (or close to that) with your 470 ohm resistor. Because, when I use a simple voltage divider formula then I come to a total of only 0.0028 watt for the speaker.
    I did this:
    Voltage supplied to speaker = (8/478)*9v = 0.15v
    Total current draw = 9v/478 = 0.0188 Ampere
    Power used by speaker = 0.15*0.0188 = 0.0028 Watt
    What am i doing wrong in this calculation?

    • @simplyput2796
      @simplyput2796  4 роки тому +1

      At that point in the video, I'm talking about the total power going through both the load path and the transistor path, not just the load. I was talking about how I wanted to be careful because I was designing a power-hungry amplifier with weak and cheap parts, and if I were doing it "for real", I'd use actual power resistors and transistors that could handle the load the speaker actually wants.

    • @ruben.9903
      @ruben.9903 4 роки тому

      @@simplyput2796Ow okay, then I missed that detail. Thanks for your answer