A Nostalgic Problem Revisited With Sound 😁
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- Опубліковано 5 жов 2024
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I chose 1 by observation
Really like the emphasis on the graphs.
Glad to hear that!
8:28
intervals should be [-1,0] and [0,1]
I think, you should put
y² instead of 1-x²
y² + 5²∧y = 1
lim ₓ→₀( f ) and lim ₓ→-∞( f )
first one is ok then y² =0
so that x =1 also
It (exponentialize) will, more likely, show up in the dictionary on Friday. Remember, the different departments it has to pass through?
epic video! Would you tell me what application you use for making these? I recently got a drawing tablet and want to imitate you in a mirror lol
Thanks! I use Notability on iPad
@@SyberMath ah :) i'm too poor for that right now but i'll keep it in mind :))))
x = cosu => x² = cos²u
1 - x² = sin²u => √(1 - x²) = sinu
5^sinu = cosu
=> 0 < cosu 0 1
The first method is definitely more elegant!
Glad you think so!
1 is an obvious solution, and a graph sketch confirms it's the only one, since sqrt(1 - x^2) would have a upper semicircular graph, and exponentiating preserves order, so the graph shape would still be "up then down", enough to ensure 1 is the only solution. Though and algebraic approach escapes me, so ... time to watch.
If p is prime, when is 7^(3p) - 2^(3p) a multiple of p?
WOW! Domain! Domain!!
😊😊😊👍👍👍
8:26 You have made a little mistake in the domain in the table of variations of f. It's ]-1;1[ not IR
ooopsies
too easy, solved with halfcircle in 1 minute
I want to point out that critical points are not just were the function has a zero slope but rather where the slope is also undefined and that can happen at points of discontinuity, a sharp cusp or a vertical tangent.
Sooo, does the inverse function have a critical point at 0, or this point doesn't count because it's not in the domain?
@@UA-cam_username_not_found what are you talking about which function? Log_5(x) has an inverse but 5^(sqrt(1-x^2)) does not.
@@moeberry8226 Excuse me. I meant the reciprocal function.
The function f such that f(x) = 1/x
@@UA-cam_username_not_found that has nothing to do with my comment or any function related to the video.
x = 1