Solve Sqroot of x + square root (x+15)= 5/(sqroot of x)

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  • Опубліковано 11 січ 2025

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  • @tomergngn
    @tomergngn 15 годин тому

    My thought process on how I solved this:
    Since Kaiju wants a nice solution, I'll try sqrt(x) natural and sqrt(x + 15) natural: we get x = 1.
    Plugging that in, we get a correct solution.
    Since the left side is monotonically increasing and the right side is monotonically decreasing, that must be the only solution.

    • @KaijuMathematics12
      @KaijuMathematics12  9 годин тому

      Interesting! Didn’t think about the increasing or decreasing.

  • @killer-1869
    @killer-1869 2 дні тому

    How I solved it (without watching the video first, of course):
    √x + √(x+15) = 5/√x | - √x
    √(x+15) = 5/√x - √x
    √(x+15) = 5/√x - x/√x
    √(x+15) = (5-x)/√x | * √x
    √(x+15) * √x = 5-x | ()²
    (x+15) * x = (5-x)²
    x² + 15x = 25 - 10x + x² | - x²
    15x = 25 - 10x | + 10x
    25x = 25 | * (1/25)
    x = 1

  • @mathmachine4266
    @mathmachine4266 День тому

    x+√(x)√(x+15)=5 and x≠0
    5-x=√(x)√(x+15)
    25-10x+x²=x²+15x
    25-25x=0
    x=1
    1+√16=5/√1, this is indeed true.
    x=1.