How to Prove a Function is Surjective | Logic and Proofs

Поділитися
Вставка
  • Опубліковано 23 січ 2025

КОМЕНТАРІ • 11

  • @titan1235813
    @titan1235813 Рік тому +4

    Man, I had to stop at 2:38 because I needed to subscribe, and this is the very first video of yours that I've ever seen. Okay, I'll keep watching until the end. 👏🏻👏🏻👏🏻

    • @WrathofMath
      @WrathofMath  Рік тому +1

      Thank you! I'm trying to make the most excellent videos I can on every topic. Let me know if you have any questions!

  • @punditgi
    @punditgi Рік тому +5

    Looks like you are really onto something with surjections! 😊

    • @WrathofMath
      @WrathofMath  Рік тому +4

      Certainly - on the map of mathematical topics, this is well inside of my conquered domain, and here I function effectively as power surj-es through me!

    • @tjn7682
      @tjn7682 7 місяців тому +1

      @@WrathofMath the math dad jokes 🤣😭

  • @Sarah._.s889
    @Sarah._.s889 7 місяців тому

    Please do make a video for bijective🙏

  • @AD-wg8ik
    @AD-wg8ik 4 місяці тому

    Thank you

    • @WrathofMath
      @WrathofMath  4 місяці тому

      Glad to help, thanks for watching!

  • @muhammadsaif4849
    @muhammadsaif4849 Рік тому +1

    Write a surjective function f:z×z>R

    • @WrathofMath
      @WrathofMath  Рік тому +2

      This is not possible because ZxZ is a countable set. The Cartesian product of any countable set with itself is also countable, so one will not be able to map it onto the reals.

  • @sounbframe3602
    @sounbframe3602 Рік тому

    997 views, 😬😬😬😬