FIT3.2.1. Cyclotomic Polynomials

Поділитися
Вставка
  • Опубліковано 21 гру 2024

КОМЕНТАРІ • 18

  • @ebachura
    @ebachura 6 років тому +4

    This is still a SUPERB video. Great explanations, great breakdown!

  • @integralmath
    @integralmath 12 років тому

    Glad you're recovered; I'm still working on getting all of the lung leftovers up and out.
    It's a miracle then! (I prayed very carefully for you after I left that comment and it worked! You're healed! lol)

  • @kilogods
    @kilogods 8 років тому +1

    Nice video! Lot of useful information compiled very neatly. Thanks.

  • @MathDoctorBob
    @MathDoctorBob  12 років тому +1

    This video is advanced material, usually for grad school. For some reason, cyclotomic polynomial show up in the Math Olympiads though.

    • @codegeek98
      @codegeek98 3 роки тому

      It may see a resurgence in popularity soon, as quantum computing breaks RSA, EC, and D-Log; it looks like Kyber is favored to win the NIST Post-Quantum competition, and its specification relies centrally on this concept...

  • @MathDoctorBob
    @MathDoctorBob  12 років тому

    Past tense! What a relief! I was feeling fine here, just a little raw.

  • @dasdos002
    @dasdos002 12 років тому

    At 8:45 Number 1 last line should read phi(alpha*beta) = phi(alpha)*phi(beta)

  • @paul1964uk
    @paul1964uk 12 років тому

    7:35 You said "phi" is minimal over Q You meant to say "alpha is minimal over Q (I think)

  • @abdonecbishop
    @abdonecbishop 10 місяців тому

    excellent

  • @integralmath
    @integralmath 12 років тому

    Someone has a cold!

  • @paul1964uk
    @paul1964uk 12 років тому

    Opps "algebraic" over Q with minimal polynomial (I should have said there!)

  • @MathDoctorBob
    @MathDoctorBob  12 років тому

    Thanks! Annotated.

  • @MathDoctorBob
    @MathDoctorBob  12 років тому

    Thanks! Annotated. (At least it's true.)

  • @dasdos002
    @dasdos002 12 років тому

    lol

  • @solemngravisyre
    @solemngravisyre 12 років тому

    Man.... I am so far off.

  • @MathDoctorBob
    @MathDoctorBob  12 років тому

    Thanks! Annotated.