Hey man I just want to let you know that ALL of your E and M videos have been EXTREMELY helpful and relevant to me and I just want to thank you for making this knowledge freely available. You are an icon.
My physics prof at uni tends to skip a lot of steps in solving the problem because it's "intuitive" even when it's not, which presents a problem for something like biot-savart... these sets of videos are the first time I understand this concept, which is having me feel #blessed because I have an exam tomorrow. Nice job, super appreciated
Man u r learning this in which uni and year. I have this concept in my senior year. Our part one of physics textbook is full of electricity and magnetism.
Loved your channel but you have very few videos, want to see alot of videos from your side on subjects like Classical Mechanics, Introductory Electronics, MMP etc. Man, your teaching style is too awesome. To the point discussion, simple derivations with understandable diagrams, no useless and lengthy discussions and easy problem solving techniques. Wonderful! Keep the good work up.
@@wealthy_concept1313 No, it's not straight to the point. You will need to do further hardwork. You are missing to quote alot of Important concepts. Think of every level of student.
You sir are absolutely amazing, although I feel rather ridiculous for having an issue setting up these problems. Not anymore thanks to you! This was the only issue I was having and now that I have it down I'm about to ace this exam!
Thank you very much for clarifying |dl x r|. This 10 minute video made things so much more simpler in comparison to sitting through three confusing lectures by my professor.
total regrets of not watching your videos before taking my quizzes :'( final exams coming up, thanks for all the video tutorials, I understand what I'm learning much much better now :')
@emily: 'r' is d distance from d element to the point which is outside. Biot savart's law states dat, 'dB' is inversely prop to d square of the distance. Thus comes 'r^2'
Hi, could you please explain in detail how the formula should be modified in the event a current flows through a conductor with a non-negligible volume? Thank you very much.
W.L. uses (dl x (the vector r))/r^3 this video uses (dl x (unit vector r)/r^2. These are identical because the unit vector r has a magnitude of 1. So why do we bother multiplying by 1? Because the unit vector will also provide a direction.
For some reason I always thought the north end of a magnetic source was the end the magnetic arrows come out of. Certainly this is how magnets are conventionally labeled, for example on the Wikipedia page on Magnet, and in the discussion thread there. This suggest that if a compass were placed in the field of such a magnet, the red "north" arrow of the compass would point backwards compared to the direction of the magnetic arrows, not in the same direction as the arrows showing the magnetic field. Of course the south end of the compass is the end labelled with the red arrow....
The compass points in the direction of the magnetic field. When placed near the end of bar magnet, a compass will point away from the north pole of a bar magnet and at the other end the compass will point toward the south pole of a bar magnet. A compass is a tiny magnet, its north pole is attracted to a bar magnet's south pole (opposite poles attract, like poles repel). The compass' north pole is repelled by the bar magnet's north pole. So then why does a compass' north pole point toward the earth's North geographic pole (almost- a little off due to declination)?This is because the earth's north geographic pole is actually the earth's south magnetic pole.
@@lasseviren1 Thank you, you clarified a misconception I am embarrassed to say I have had for many decades! I always thought my compass was labeled backwards to properly indicate the north pole of our planet. Actually our planet is mislabeled, ha ha. By the way, I'm slowly working through your video set, these videos are clear thinking and well presented.
Hello, I have a question about the integral. What if we integrate it by tiny angles? I mean y=rcos(theta), dy=-rsin(theta)dtheta and the boundry is 0 to pi.
It would be better if you choose theta as the variable instead of y , then the integration would be a lot easier bounded between pi/2 and -pi/2 with cos(theta) to integrate
Easier to see intuitively, if the integral is in terms of the angle, not distance. The limits, then, are the right angles, and you obtain the answer without a complicated trig sub.
what does the angle represent? is it always the "inside angle"? also, do you have a video about this thing but instead of it being a line, it's a circle? like a ring. and in my notes there is this thing about B= (u0)I/4piR * (cos x-cosy) . what the heck is that? because they didn't choose dl, they just took a section of the line... i dont get it :(
Sir you are like Patrickjmt but for physics, and I'm loving it :)
+Al Cope or....it could be the other way around. :) I agree, they are very similar - very organic presentation.
+Agent Smith
Lol that's a good comparison actually.
+boanice223 only two people that I can understand so clearly lol
Oh spot on,need to appreciate ur skills of comparison,so as mine..😝
12 years .. and this is the first time for me to understand this concept since the beginning of the term .. thanks💗
great explanation. You are saving lifes out here in the "battle field"
that reminds me, i should take a break from studying and join the field of xbox.
Ten and a half years later and this video just taught me more in 10 minutes than I learned in a whole class. I wish you were my physics professor.
This video got me 10 points on a physics 2 exam...Thank you!
Hey man I just want to let you know that ALL of your E and M videos have been EXTREMELY helpful and relevant to me and I just want to thank you for making this knowledge freely available. You are an icon.
My physics prof at uni tends to skip a lot of steps in solving the problem because it's "intuitive" even when it's not, which presents a problem for something like biot-savart... these sets of videos are the first time I understand this concept, which is having me feel #blessed because I have an exam tomorrow. Nice job, super appreciated
Man u r learning this in which uni and year. I have this concept in my senior year. Our part one of physics textbook is full of electricity and magnetism.
I too have it in test tomorrow
Loved your channel but you have very few videos, want to see alot of videos from your side on subjects like Classical Mechanics, Introductory Electronics, MMP etc.
Man, your teaching style is too awesome. To the point discussion, simple derivations with understandable diagrams, no useless and lengthy discussions and easy problem solving techniques. Wonderful! Keep the good work up.
yeah It's just straight to the point, saves Alot of time
@@wealthy_concept1313 No, it's not straight to the point. You will need to do further hardwork. You are missing to quote alot of Important concepts. Think of every level of student.
@@allrounder2367 agreed.
you sir, are a god. I actually understand this now. My teacher's way was unnecessarily complicated. This makes so much more sense
You're brilliant, you explain all the tiny subtleties about what certain variables that so many lecturers leave out for whatever reason. Thanks!
people like you make the internet great. thanks for teaching us all something!
Sir from the bottom of my heart, I hope you have all the beautiful things in life.
I hope this guy decides to check his email one day for old time sake and hopefully sees what he has done for a lot of us watching.
Kuna shida ama
You are making real lots of people succeed in college exams. I finally understood this physics from several veds of yours. Keep on i subscribed you.
Hey do u mean high school by college
No college. I took it first year in college.. Not sure if other countries take it in high school but i took thiw course in 1st year in college
I have it this year. I am in 12 grade. My test is tomorrow
So u must have graduated by now what work do u do now. Must have been nostalgic to visit this video after 6 years. By the way I am from India
Well that's awkward xD good luck.
Truly amazing and helpful video. Thank you so much. I learned more from this than from my lesson in class!
You sir are absolutely amazing, although I feel rather ridiculous for having an issue setting up these problems. Not anymore thanks to you! This was the only issue I was having and now that I have it down I'm about to ace this exam!
Did u ace the exam
I have mine tomorrow. Magnetism and electricity is a lot harder than Newtonian mechanics and chemical kinetics
This was nicely done and explained very well.
Thanks for being a great teacher and doing this video.
This guy always come reaaally helpful when the book is not enough
i owe all my understanding of physics II to you sir. wish i found your videos sooner, they are all i've used to teach me these concepts
In the denominator you have ((y^2+a^2)^.5)^2 which is r^2 and the sin(theta) turns into a/(y^2+a^2)^.5 . Hope this helps.
Thanks sir great explanation
the most helpful physics video on youtube!
Thank you very much for clarifying |dl x r|. This 10 minute video made things so much more simpler in comparison to sitting through three confusing lectures by my professor.
Thanks for the concepts you have shared here.
I'm really glad you made this video. Thank you!
THANK YOU!! I wish my physics professor would make things this easy to grasp.
I am passing my physics mid because of you! +1 Subscriber
this really helped me alot
all the love from egypt
thanks
Wow sir amazing video. You explain concepts very well. Thank you
He makes this so simple.
simple awesome....awesome....you nailed it. I'm not even studying this subject you made clear from the beginning. Good work!!!
You just taught me something I didn't get in class. Thank you so much
Awesome. Purely awesome. I wish I had you as my teacher.
You're are the best.Thanks for really breaking this down!
Such a great explanation. Thanks.
Thanks from Spain! My teacher is so bad, I pass my exams with your videos
it's too useful sir and thanks a lot for it
You've made the many of the most abstracting problems in Physics College become so simple
total regrets of not watching your videos before taking my quizzes :'( final exams coming up, thanks for all the video tutorials, I understand what I'm learning much much better now :')
thanks for helping me study for exams!
great explanation #loved
thx a lot man, im now in a situation of trying to PASS my emt exam. this video helps a lot. HATE to repeat this crazy subject.
So at 1:10! Ive never seen such a straight line lol.
that is infinitesimally straight.............lol
brain freeze for meh
Y=mx+c
@emily: 'r' is d distance from d element to the point which is outside. Biot savart's law states dat, 'dB' is inversely prop to d square of the distance. Thus comes 'r^2'
Thanks also from Germany... I wish I could give more than just one positive rating! :)
Best explanation ever
Thank you from India 🇮🇳
Thanks man! This really helped me out.
he explain this equation in easy way
thanku sir
You have continuous flow of charge so angle theta is constant, you measure magnetic field strength from let say wire, with from radius zero to r.
This helped so freaking much dude,ty
Hope I get a Biot-Savart question tomorrow on my exam!
oh my god... you helped me a lot.. realy! Thank you..
Was having trouble comprehending |dl x r|, but this made sense, thank you!
Hi, could you please explain in detail how the formula should be modified in the event a current flows through a conductor with a non-negligible volume? Thank you very much.
Integrate it I guess
Excellently simplified..
"the segment will be infinitesimally small"
"i drew it big so you could see it"
haha hilarious
awesome video with great explanaitions
great...I really like your explanation sir
W.L. uses (dl x (the vector r))/r^3 this video uses (dl x (unit vector r)/r^2. These are identical because the unit vector r has a magnitude of 1. So why do we bother multiplying by 1? Because the unit vector will also provide a direction.
For some reason I always thought the north end of a magnetic source was the end the magnetic arrows come out of. Certainly this is how magnets are conventionally labeled, for example on the Wikipedia page on Magnet, and in the discussion thread there. This suggest that if a compass were placed in the field of such a magnet, the red "north" arrow of the compass would point backwards compared to the direction of the magnetic arrows, not in the same direction as the arrows showing the magnetic field. Of course the south end of the compass is the end labelled with the red arrow....
The compass points in the direction of the magnetic field. When placed near the end of bar magnet, a compass will point away from the north pole of a bar magnet and at the other end the compass will point toward the south pole of a bar magnet. A compass is a tiny magnet, its north pole is attracted to a bar magnet's south pole (opposite poles attract, like poles repel). The compass' north pole is repelled by the bar magnet's north pole. So then why does a compass' north pole point toward the earth's North geographic pole (almost- a little off due to declination)?This is because the earth's north geographic pole is actually the earth's south magnetic pole.
@@lasseviren1 Thank you, you clarified a misconception I am embarrassed to say I have had for many decades! I always thought my compass was labeled backwards to properly indicate the north pole of our planet. Actually our planet is mislabeled, ha ha. By the way, I'm slowly working through your video set, these videos are clear thinking and well presented.
helpful video! thank you.
Adamsın adam
You are a life saver homie, thank you
Hello, I have a question about the integral. What if we integrate it by tiny angles? I mean y=rcos(theta), dy=-rsin(theta)dtheta and the boundry is 0 to pi.
Amazing explanation
awesome explanation .
really good explanation. Thanks a lot.
It would be better if you choose theta as the variable instead of y , then the integration would be a lot easier bounded between pi/2 and -pi/2 with cos(theta) to integrate
Easier to see intuitively, if the integral is in terms of the angle, not distance. The limits, then, are the right angles, and you obtain the answer without a complicated trig sub.
Good explanation !
You definitely a life saver !!!!!!
1:20, didn't understand that use of the right hand rule. Wouldn't the field be heading out of the page towards you at the point?
well done, great video
Thx.
Another great video!
just a simple question instead of converting entire thing in terms of y can we convert it in terms of theta
Yea, I just checked my textbook the r in the bottom is r^2 regardless if it is dL x r or dLsin(theta)
sir, why do we consider a vector not just a point like in electrostatics??
Thanks for you good advices !
Where's the next video? I didn't see it. Is there even a second video?
can you say why here sin angle is used? instant of cos... opp side by hypo concept? it's confusing for May theory sir
thank you so much, you are a godsend
Very helpful video
u r very good at explaining....but can u explain why they write sin(theta) in the equation....its a little confusing for me
Thank you very much!
you are best sir
.?? I watched Walter Lewis videos but he says that the equation for dL x r still gives you r^3 in the denominator? Which one is correct?
ربي يحفظك ويوفقك 😍😍😘😘😘
Thank you
what does the angle represent? is it always the "inside angle"?
also, do you have a video about this thing but instead of it being a line, it's a circle? like a ring.
and in my notes there is this thing about B= (u0)I/4piR * (cos x-cosy) . what the heck is that? because they didn't choose dl, they just took a section of the line... i dont get it :(
Wow that was great. That totally make sense. Thanks you.
Thank you so much for this vid!!!!!!
@lasseviren1 Oh ok, so the difference is that some uses the unit vector? Had some typos in my previous comments.
means 2 types of derivations on different situations
could you have used tan as a/y instead of sin for a/(a^2+y^2)^1/2?
you are making things clear =D, see you in next video !
Very helpful
Thank you men...
Thank You man
Thank you so much!!!
Why i used to put 1/2 after the (y^2+a^2) ?