Flex Sensor - Introduction and Use

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  • Опубліковано 12 лис 2024

КОМЕНТАРІ • 25

  • @HarshPatel-dv3hm
    @HarshPatel-dv3hm 5 років тому +5

    Your Pen or whatever it is...
    It is simply amazing...

  • @jamesbrosnahan3422
    @jamesbrosnahan3422 9 років тому +2

    Patrick- Excellent video . I suggest googling 'wheatstone bridge' + 'strain guage' and also using a microcontroller with two A2D input pins that can be set to DIFFERENTIAL mode. Your results should improve.
    Good luck. I enjoy your videos. I'm subscribed. - Jim

  • @haljohnson6947
    @haljohnson6947 3 роки тому +1

    you forgot to tell me to subscribe and smash the like button

  • @huntermalone6899
    @huntermalone6899 4 роки тому +1

    Will adding a potentiometer require a resistor in the circuit still?

  • @BrandonBaunach
    @BrandonBaunach 3 роки тому +2

    Does the sensing quality degrade over time as you bend it over and over for years?

    • @PatrickHoodDaniel
      @PatrickHoodDaniel  3 роки тому

      I have not tested this item. The manufacturer should have that information in the datasheet for the product.

  • @jermainepop
    @jermainepop 8 років тому +2

    what type of pen pencil is that?

  • @shaider1982
    @shaider1982 9 років тому +2

    hi there. i tried to use this to control a servomotor. i can command the motor as if i am using a potentiometer but if i am not flexing the sensor, the motor trembles. i wonder if it really does this or did i break the sensor. could i filter out the.tremors? thanks

    • @Synergy7Studios
      @Synergy7Studios 7 років тому

      shaider1982 no, you didn't break it. That's just normal noise. You'd get that from any sensor like a flex sensor. You will need to smooth it out in software (maybe take 5 readings and average them). A capacitor in parallel might also smooth it out..

  • @danaishrathore2659
    @danaishrathore2659 4 роки тому +1

    Hi, can you share the link of Flex sensor, I want to buy it.

    • @PatrickHoodDaniel
      @PatrickHoodDaniel  4 роки тому

      Here you go: www.newbiehack.com/categories/newbiehack-sensors-flex-sensor-spectra-symbol#prettyPhoto

    • @danaishrathore2659
      @danaishrathore2659 4 роки тому +1

      @@PatrickHoodDaniel Thanks

  • @ZA-fo2rn
    @ZA-fo2rn 5 років тому +2

    I am distracted by the pen
    or just the way u write

  • @eddivanhallen
    @eddivanhallen 8 років тому +1

    Where is possible to buy a flex sensor?

  • @GouthamKolluru
    @GouthamKolluru 9 років тому +2

    Vout = Vin (R2 / R1+R2 ) right ?

    • @PatrickHoodDaniel
      @PatrickHoodDaniel  9 років тому

      Vout = Vin * ( R1 / (R1+R2) ) I add the parenthesis to show order of operation.

    • @GouthamKolluru
      @GouthamKolluru 9 років тому +3

      Patrick Hood-Daniel No, I mean at @2:57 Vout is equal to the voltage drop on R2 ,If you are measuring the drop across flex sensor directly then Vout should be Vin - Vin * ( R1 / (R1+R2) ) because the reference was GND, As far as I understand, the supply voltage is divided into voltage across flex sensor and resistor R2 and by measuring voltage across R2 we determine the range of voltages that flex sensor outputs for various bending positions. To transform the voltage to our desired range we use potentiometers, op amps etc etc.Is my understanding correct ?

    • @H2CO3Szifon
      @H2CO3Szifon 9 років тому

      Goutham Kolluru yeah, that's it. The formula in the video is wrong as-is.

    • @PatrickHoodDaniel
      @PatrickHoodDaniel  9 років тому

      Árpád Goretity You are all correct. I will correct the video. I used the formula from the datasheet for this flex sensor. Silly me.

    • @H2CO3Szifon
      @H2CO3Szifon 9 років тому

      No problem, thanks for the video anyway!

  • @sabahoudini
    @sabahoudini 4 роки тому

    God damn youtube commercials are getting out of hand. There is to many.