You need to have more views and more followers. Seriously. Your content is amazing. Please dont stop. Keep at it! Congratulations on your future success. I have no doubt your channel will grow. Primo content, great production value, etc.
And to get a maybe better understanding of this formula, image you have 100L tank on 1Bar, in that tank is 79L of N, you want to preserve this amount of gas 100L but in different proportion. You want 68L of N and 32L of O2, to get that you need to decrease pressure for some value X to you will have 68L of N, and then top with O2 till 100L is full. The question is basically what is the percent that you need to decrease overall pressure to decrease 79L to 68L N, and that is 14%. after that only what is left is to fill that void with O2 and you will have 100L where 68L is N and 32L is O2.
@@DoktorBEN That is correct for the EAN32 calculations, I don't understand the reason, you take the same number (14%) for the trimix 21/35 calculation (0,44/0,78)=0,564 so I add 200x0,56=112,8 bars of Air and the rest (17,2 bars) with pure O2). I dont' know if my calculations are wrong so if you can explain me the 14% in this calculation that would help me a lot. Thank you
@@DoktorBEN the point is, how do you count for 18% of o2. Can you explain? 32% EAN is 14% of pure o2. So how about tx18/30, tx7/72 or tx12/52. I just need to now how do you get 14% of number for mixing 32% EAN. Thank you
In general, the topoff proportion is the ratio of the nitrogen content in the desired to that of the topoff. For example, for a desired 18/30 (nitrogen=52%) and topping off with air (nitrogen=79%), the topoff proportion is T = 52/79 = 66%. In this case with only one source of helium, things are simple: you know the helium added must equal the desired: 30% helium. The oxygen is whatever is left over: with 30% helium and 66% topoff, you need 4% oxygen. In general, though, the required pure gas is the desired fraction minus the topoff*mix. In this case of air topoff (mix=21%), the oxygen proportion is O = 0.18 - 0.66*0.21 = 4% (as we saw before). Similar for helium. (The general approach is needed if you're topping off with trimix. Also, a negative answer means it's impossible with that topoff mix. For example, you can't get 18/30 by topping off with 32%.)
You need to have more views and more followers. Seriously. Your content is amazing. Please dont stop. Keep at it! Congratulations on your future success. I have no doubt your channel will grow. Primo content, great production value, etc.
Thank you very much! It’s good to hear that you like my videos. There’s more to come in the future
Wow. This is really useful information. THANK YOU!!
You’re welcome!
brilliant! thanks for sharing
How did you arrive at 14? This doesn't really seem to work on anything other than 32%.
from where does this 14% comes from (both in ENX32 and 21/35 calculations)? I'm scratching my head ... any pointer?
1 - 0.68 / 0.79
So nitrogen content of EAN32/Nitrogen content of air
And to get a maybe better understanding of this formula, image you have 100L tank on 1Bar, in that tank is 79L of N, you want to preserve this amount of gas 100L but in different proportion. You want 68L of N and 32L of O2, to get that you need to decrease pressure for some value X to you will have 68L of N, and then top with O2 till 100L is full. The question is basically what is the percent that you need to decrease overall pressure to decrease 79L to 68L N, and that is 14%. after that only what is left is to fill that void with O2 and you will have 100L where 68L is N and 32L is O2.
I like the explanation!
[1-(0.68/0.79)]x100
@@DoktorBEN That is correct for the EAN32 calculations, I don't understand the reason, you take the same number (14%) for the trimix 21/35 calculation (0,44/0,78)=0,564 so I add 200x0,56=112,8 bars of Air and the rest (17,2 bars) with pure O2). I dont' know if my calculations are wrong so if you can explain me the 14% in this calculation that would help me a lot. Thank you
How about the blend 18/30
Why would you want to blend 18/30?
@@DoktorBEN its for my bottom gas.
@@DoktorBEN the point is, how do you count for 18% of o2. Can you explain?
32% EAN is 14% of pure o2. So how about tx18/30, tx7/72 or tx12/52. I just need to now how do you get 14% of number for mixing 32% EAN. Thank you
In general, the topoff proportion is the ratio of the nitrogen content in the desired to that of the topoff. For example, for a desired 18/30 (nitrogen=52%) and topping off with air (nitrogen=79%), the topoff proportion is T = 52/79 = 66%.
In this case with only one source of helium, things are simple: you know the helium added must equal the desired: 30% helium. The oxygen is whatever is left over: with 30% helium and 66% topoff, you need 4% oxygen.
In general, though, the required pure gas is the desired fraction minus the topoff*mix. In this case of air topoff (mix=21%), the oxygen proportion is O = 0.18 - 0.66*0.21 = 4% (as we saw before). Similar for helium.
(The general approach is needed if you're topping off with trimix. Also, a negative answer means it's impossible with that topoff mix. For example, you can't get 18/30 by topping off with 32%.)