00:00 Introduction 02:02 - Types of chemical reaction 03:43 - Concept of equilibrium 05:51 - Physical and Chemical Equilibrium 18:54 - Equilibrium constant 23:00 - Applications of equilibrium constant 26:47 - Factors affecting equilibrium 37:28 - Vapour density and degree of dissociation
18:21 Sir i have a doubt you said that Kç is not defined for pure solid and pute liquid then how is Kç possible for fourth reaction in homogeneous equilibrium
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Ek or chiz
Kp= kc (RT)^n wale relation m
Agr n=0 hoga to kp=kc
n>0 kp> kc
n
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And also if t=12 celcius rt=1 and kp=kc
00:00 Introduction
02:02 - Types of chemical reaction
03:43 - Concept of equilibrium
05:51 - Physical and Chemical Equilibrium
18:54 - Equilibrium constant
23:00 - Applications of equilibrium constant
26:47 - Factors affecting equilibrium
37:28 - Vapour density and degree of dissociation
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18:21 Sir i have a doubt you said that Kç is not defined for pure solid and pute liquid then how is Kç possible for fourth reaction in homogeneous equilibrium
Because H2O is present in gaseous state not in liquid
Active mass of H2O(liquid) is 1 therefore we don't consider it in Kc equation
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I have a doubt,sir degree of dissociation is defined only for dissociation reaction,then How 4th example is true 40:01
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40:13 waha par sir last example to degree of dissociation ka rxn to ha hea nhi
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