[@danielfranca1939]

Nice

[@Mathprowess]

Thanks my good friend and thanks for watching and dropping this wonderful comment sir.
Love you sir.

[@opulence3222]

Good man.

[@Mathprowess]

Thanks a million sir.
We love you sir ❤️❤️💖💖

[@mouthiknaradas962]

Simple, just do implicit differentiation. Ln both sides, differentiate and make dy/dx the subject.
lny = xlnx
dy/dx (1/y) = lnx + 1
dy/dx = y(lnx +1)
dy/dx = (x^x)(lnx + 1)

[@Mathprowess]

Wow!!! I like this approach sir.
You are good at calculus sir.
You the best boss here my good friend... hahahahaha.
Bravo!!!👍👍
Maximum respect sir 🙏🙏🙏

[@sonyaazra19]

But power law of log is only applied when the power is some real number, not a variable

[@Mathprowess]

Not true sir,
Kindly do your research or findings again.
Thanks so much sir.