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The name plate of 3phase induction motor reads as V =400v ,hp =5, f = 60 , I = 15A, Connection delta , N = 540rpm The no.of poles for which stator winding wound = ? Sir ,iska answer btaiye with explanation
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Synchronous speed =Ns=120f/P
F=50 then voltage =4.44fTph*flux
Induced voltage = 4.44*f*Turns per phase*flux
Induced voltage=222V
Option D.
Induced voltage for the generator will be
d) 222V
by formula e=4.44fn φ
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D=222
E=4.44 *50*200*5*0.003
First find Freq. Then
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The name plate of 3phase induction motor reads as
V =400v ,hp =5, f = 60 , I = 15A, Connection delta , N = 540rpm
The no.of poles for which stator winding wound = ?
Sir ,iska answer btaiye with explanation
E=4.44×flux×f×N
E=4.44×(5×10^-3)×50×200
E=222V
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Thank you sir
Option D is correct ans 222v
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Option d) 222V
D is Right
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Option D induced vtg=222 v
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Answer is 222V.
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Ans- Option D 222V
OPTION D 222V IS CORRECT
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Option d
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E= 222v
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D
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222volts
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