A solution of 1% ( w/v ) starch at ph 6.7 is digested by 15 µg of β -amylase ( mol wt 152,000) .The rate of maltos ?mol wt - 342 ) had a maximal initial velocity of 8.5 mg formed per min. Then what will be the turn over number )
need an urgent help in solving this question, Q. One microgram of pure enzyme (MW = 92000Da) catalyzed a reaction at a rate of 0.50 mu moles/min under optimum conditions. Specific activity of the enzyme in terms of units/mole is a) 4.6 × 10^10 b) 4.6 × 10^9 c) 2.3 × 10^10 d) 2.3 × 10^9
A solution of 1% ( w/v ) starch at ph 6.7 is digested by 15 µg of β -amylase ( mol wt 152,000) .The rate of maltos
?mol wt - 342 ) had a maximal initial velocity of 8.5 mg formed per min. Then what will be the turn over number )
need an urgent help in solving this question,
Q. One microgram of pure enzyme (MW = 92000Da) catalyzed a reaction at a rate of 0.50 mu moles/min under optimum conditions. Specific activity of the enzyme in terms of units/mole is
a) 4.6 × 10^10
b) 4.6 × 10^9
c) 2.3 × 10^10
d) 2.3 × 10^9
What is the answer??......mine is 4•6×10^4
How it turnover number becomes 800 plzz answer me
Final ans after calculation comes to be 80 turnover no.per min.,....is it correct!!!!!
800 is correct
specific activity is μmol min−1mg−1 not mol?
either is ok, as soon as you define it first
Turnover no is 1600
So unclear!!
Writing 😂