CS601 Midterm Preparation 2024 | "Midterm Ready in Minutes! |More VU

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  • Опубліковано 16 гру 2024

КОМЕНТАРІ • 45

  • @razarajpoot9811
    @razarajpoot9811 17 хвилин тому

    Mashaallah Great.

  • @ripboss7681
    @ripboss7681 3 дні тому +1

    23:08 both amplitude and phase is the correct option

  • @Mani-f3m
    @Mani-f3m 3 дні тому

    World of education ki BAAT kr rhi thi thank you batany k liye 😊

  • @Abdulwahab012
    @Abdulwahab012 3 дні тому +1

    15:40 N-1

  • @HayyamHaider
    @HayyamHaider День тому +2

    true and fined answers

    • @MoreVU-o3y
      @MoreVU-o3y  День тому +1

      @@HayyamHaider Thank you Means A lot ❤️Your Name is very nice I see first time 🎉

  • @ZahraMalik-w6n
    @ZahraMalik-w6n 3 дні тому +1

    6 mcqs: right option is 2 not 1. unipolar encoding uses 2 voltage level

    • @MoreVU-o3y
      @MoreVU-o3y  3 дні тому

      @@ZahraMalik-w6n Dear! The unipolar encoding scheme uses 1 voltage level.
      In unipolar encoding, the voltage is either present (a positive voltage for a binary "1") or absent (zero voltage for a binary "0").

  • @zaidjaved4501
    @zaidjaved4501 5 днів тому +1

    keep uploding study related material, Inshallah your channel will grow fast

    • @MoreVU-o3y
      @MoreVU-o3y  5 днів тому +1

      @@zaidjaved4501 i just started recently and your words means a lot❤️

  • @JehadUlhaq-j7h
    @JehadUlhaq-j7h День тому

    Thank you so much

  • @Black_Rose_Echo
    @Black_Rose_Echo 4 дні тому

    MCQ 44 answer is frequency. In FSK frequency remains constant whereas phase and amplitude vary.

    • @MoreVU-o3y
      @MoreVU-o3y  4 дні тому

      Dear In Frequency Shift Keying (FSK), **amplitude** remains constant.
      FSK modulates the **frequency** of the carrier signal to represent data, while the **amplitude** and **phase** remain unchanged.

    • @Black_Rose_Echo
      @Black_Rose_Echo 4 дні тому

      @@MoreVU-o3y Oh sorry I mixed up🙃

    • @MoreVU-o3y
      @MoreVU-o3y  4 дні тому +1

      @Black_Rose_Echo don't worry🥰

  • @exampractice-c5u
    @exampractice-c5u 7 днів тому

    Thank you so much for providing this wonderful video.❣ Question number 61's correct answer is FSK because FSK is a type of digital modulation that uses different frequencies to represent different bits. 😊

    • @MoreVU-o3y
      @MoreVU-o3y  7 днів тому

      In PSK (Phase Shift Keying), the bandwidth required is not always proportional to the signal rate. PSK is a type of digital modulation that changes the phase of the carrier signal to represent digital data. SO CRRECT ANSWER IS PSK because
      ASK: Bandwidth is proportional to the signal rate as the amplitude changes.
      FSK: Bandwidth is also proportional to the signal rate because different frequencies are used.

    • @exampractice-c5u
      @exampractice-c5u 7 днів тому

      @@MoreVU-o3y FSK is a type of digital modulation that uses different frequencies to represent different bits. This means that the bandwidth required to transmit FSK signals is proportional to the data rate. In contrast, the bandwidth required to transmit PSK signals is not always proportional to the data rate, especially in higher-order PSK schemes.

    • @MoreVU-o3y
      @MoreVU-o3y  7 днів тому

      @@exampractice-c5u Please read the question carefully in question they use word ' except'

    • @exampractice-c5u
      @exampractice-c5u 7 днів тому

      @@MoreVU-o3y Ma'am, I am very confused about this question. Thank you for clarifying my confusion❤, and I have a question. Please, we need a teacher like you for MTH 301 as my exam is in a few days.

    • @Mariapdev
      @Mariapdev 4 дні тому

      is video se paper me aya?

  • @Mhasnain000
    @Mhasnain000 5 днів тому +1

    Thank you so much. Main ny khud preparation videos watch ki hain dosry channel ki lakin abhi pta chala k maximum answers correct nhi thy. Achha hy apki video mil gayi werna mera paper to aj fail tha.

    • @MoreVU-o3y
      @MoreVU-o3y  5 днів тому +2

      @@Mhasnain000 Thank you for your feedback ❤️I don't make a video until I am confident that the answers are 100 percent correct.

    • @Mhasnain000
      @Mhasnain000 5 днів тому

      @MoreVU-o3y
      We highly appreciate your effort.

    • @Mariapdev
      @Mariapdev 4 дні тому

      konsi video se short long ques aye thy and mcqs pz reply jazakAllah

    • @MoreVU-o3y
      @MoreVU-o3y  4 дні тому

      @Mariapdev There isn't a only one video You Have to watch this Video your concept Will clear and read Handout for excellent result
      May Allah pak help you ❤️

    • @Mariapdev
      @Mariapdev 4 дні тому

      @@MoreVU-o3y JazakAllah.. is video se mcqs and short question etc aye thy?

  • @Yours31st
    @Yours31st 4 дні тому

    thank youu so much means alot Allah bless you

    • @MoreVU-o3y
      @MoreVU-o3y  4 дні тому +1

      @Yours31st
      Your kind words mean a lot to me. May Allah bless you abundantly as well!"

  • @awaisyousaf-qp7pj
    @awaisyousaf-qp7pj 2 дні тому

    mcqs 24 ka correct option n(n-1) ha
    15:50

    • @MoreVU-o3y
      @MoreVU-o3y  2 дні тому

      @@awaisyousaf-qp7pj "I had already informed earlier and also apologized."

  • @AseerZadii
    @AseerZadii 4 дні тому +1

    Where can I find this file?

    • @MoreVU-o3y
      @MoreVU-o3y  4 дні тому +1

      @@AseerZadii it's very early morning I add link in description about 9 to 10am.

    • @MoreVU-o3y
      @MoreVU-o3y  4 дні тому +1

      @@AseerZadii I have added the file in description; check and let me know if you receive it or not?

    • @AseerZadii
      @AseerZadii 4 дні тому

      @@MoreVU-o3y recieved dear. JazakAllah

  • @exampractice-c5u
    @exampractice-c5u 7 днів тому

    I'm having trouble understanding this question. Could you please explain it to me?
    --- is correct formula to determine the total number of ports needed for one system connected in a mesh network.
    Select the correct option
    N*N
    N+1
    N-1
    N(N+1)
    but why?

    • @MoreVU-o3y
      @MoreVU-o3y  7 днів тому

      Apologies for the wrong answer.
      The correct formula to determine the total number of ports needed for one system connected in a mesh network is:
      N-1
      For example, if there are 5 systems:
      Each system will have 4 ports to connect to the other systems (5 - 1 = 4).
      This ensures a direct link between every pair of systems.

    • @exampractice-c5u
      @exampractice-c5u 7 днів тому

      @@MoreVU-o3y no problem yours all concept is very amazing

  • @awaisyousaf-qp7pj
    @awaisyousaf-qp7pj 2 дні тому

    2 min phle dusron ki buraiyan ki hain phir video start ki.
    is trha ap ke views ziada ni kam hon ge bro

    • @MoreVU-o3y
      @MoreVU-o3y  2 дні тому

      @@awaisyousaf-qp7pj "I didn't say anything bad about anyone; I just said not to watch that one video so that your time wouldn't be wasted."