you are superb , but are the the second and third methods rectangular techniques and could we do it using a fourth method spherical method. Go on man you are doing all in one ........ big sales new follower from Saudi Arabia
For a 1d object (eg: rod) you would integrate over the length, for a 2d object you need to integrate over the entire Area and for 3D over the entire volume.
this is a very useful video that answers all the questions while you explains the details ; thank you
Without loss of generality, assign R=1, then scale it back when you're done.
Very helpful video! Thank you!
Actually I don't understand, but I have copied your formula on my paper, THANKSS SENSEI!!
you are superb , but are the the second and third methods rectangular techniques and could we do it using a fourth method spherical method. Go on man you are doing all in one ........ big sales
new follower
from Saudi Arabia
i was searching an answer for 3rd method in whole internet and finally found the hidden gem.
hi, super video! just have a little question: how do you determine dA?
It seems like dA (the area) is the thickness (dX )times the height (y). So dA=y * dX. He explains around 13:15
❤❤❤❤ شکراً
Thnx a lot bro
Why double integral of dm divided by total mass gives you center of the mass?
For a 1d object (eg: rod) you would integrate over the length, for a 2d object you need to integrate over the entire Area and for 3D over the entire volume.
@@PhysicsNinja Thank you! This makes sense.
very very simple man
Yo apply wrong formula of dA in method 1 the correct formula is 1/2×r²theta
First comment
The correct answer is 2R/π.
Nope
That's the center of mass of half of a ring not a semi circle