got this technique down, really appreciate this video, but seems i need a little help with a case when dividing by a polynomial that has a term cubed or squared ? For example : (x^3-9) / (x^2+1) i would prefer to stick to this method of the division, and don't want to use the commonly known looooong division, please help. hat off for this video! thank you !
thank you, i need to practice this problem more to get it in the end. or at least learn it through visual video such as your channel. You are a blessing in my life. Thank you tecmath.
I have a question about the last problem.. why don't you divide the last answer by 4? If you do you get 1/2, so wouldn't you have a remainder of 1/2 as opposed to a remainder of 2?
What do you do if the divisor has a leading variable raised to an exponent? For example 3x^3-2x^2+7x-4 divided by x^2+1. Can someone work it out plz and tell me????
Maria Recel this is late already but its -6 since both have negative signs so you add, then you follow the sign of the bigger number which is ofc negative
got this technique down, really appreciate this video, but seems i need a little help with a case when dividing by a polynomial that has a term cubed or squared ?
For example : (x^3-9) / (x^2+1) i would prefer to stick to this method of the division, and don't want to use the commonly known looooong division, please help.
hat off for this video! thank you !
I am in love with you; your brilliance is literally mind blowing.
Really nice trick explained in a easy way .Thank you so much for your effort.
Thanks ,now I got it
In Vedic Math, this technique is known as "On the Flag" division. It works equally well for regular division as well as algebraic division.
thank you, i need to practice this problem more to get it in the end. or at least learn it through visual video such as your channel. You are a blessing in my life. Thank you tecmath.
Thanks!!👌👌👍
too confusing to me lool thanks though!
Do we have to divide by 4x instead of dividing by 4 in the last example of the video to find 2nd,3rd ,4th terms of the quotient?
I have a question about the last problem.. why don't you divide the last answer by 4? If you do you get 1/2, so wouldn't you have a remainder of 1/2 as opposed to a remainder of 2?
aryolie He said not to divide the remainders.....
Lol I don't understand this thing at all, but when I saw the long division, I thought it actually easier than this method.
What do you do if the divisor has a leading variable raised to an exponent? For example 3x^3-2x^2+7x-4 divided by x^2+1. Can someone work it out plz and tell me????
I think it's fantastic........ if you can add and subtract algebra in your head. ( Remembering those dumb signs mess me up)
Could simplify and get the same answer for the last question, awesome video!
You are fantastic!!!! Thanks for your vids.
What is this app you use to do this
What if the polynomial is something like 3x²+8x³-10 then how do I use your trick? My math homework is killing me!! X²+XY-2Y²: X²-2xy+3!²
X²+XY-2Y²:X²-2xy+3x²
Hows that brain feelin
3:12 -4x -2x= -6? not 2? this is whats confusing me. adding and subracting positive integers withh negative integers.
Maria Recel this is late already but its -6 since both have negative signs so you add, then you follow the sign of the bigger number which is ofc negative
well, anything that is both positive integers add a positive integer. and anything that adds a negative integer adds up to a negative one. good luck.
volume in this video is too low
what are you using to right this down?
i think it is the mouse on the board or whatever sort of tablet he is using. :D
Really annoying add placements.