We need both positive and negative frequencies for a real signal An ideal filter is simply unstable and non causal The piece wise nature of linear phase is important to consider throughout the DSP course Each of his statements are precise and rightly falling wherever needed. Thanks sir
When we talk of db(decibels) we take 10log(P1/P2), but here we are taking amplitudes, hence the formula changes to 20log(M1/M2). Hope this makes sense.
Because, in digital frequency, the range is -pi to +pi. That is why we consider only 0 to pi. Once you know the characteristic of the filter from 0 to pi you can also find out the characteristic form -pi to 0. Because the magnitude characteristic is even and phase is odd. You can watch Lecture number 04. You will get the answer. Also listen these lecture in order. These are awesome lectures on DSP.
These lectures are very useful. Simple intuitive examples make us enjoy DSP.. :) Thanks to the Professor and NPTEL.
We need both positive and negative frequencies for a real signal
An ideal filter is simply unstable and non causal
The piece wise nature of linear phase is important to consider throughout the DSP course
Each of his statements are precise and rightly falling wherever needed. Thanks sir
teaching== simply awesome! :)
true
Really well explained
The practical examples in between are like Easter eggs
When we talk of db(decibels) we take 10log(P1/P2), but here we are taking amplitudes, hence the formula changes to 20log(M1/M2). Hope this makes sense.
Excellent Lecture
He made a mistake....at 50:37 cutt of frequency should be 2 cos^-1(2^-1/2M) ..... the M should be in the denominator of the index not the numerator
incredible teaching !!!
Error at 52:54 it is j e^{jomega/2}
Give some life to the lecturer by increasing speed( 1.75x suggested)
Can someone help. How do you make the phase versus omega graph?
Why we are restricting the range from 0 to pi only?
Because, in digital frequency, the range is -pi to +pi. That is why we consider only 0 to pi. Once you know the characteristic of the filter from 0 to pi you can also find out the characteristic form -pi to 0. Because the magnitude characteristic is even and phase is odd. You can watch Lecture number 04. You will get the answer. Also listen these lecture in order. These are awesome lectures on DSP.
@@dr.krishnamurthyramanujam4128 why digital frequency, the range is -pi to +pi?
34:47 ???? how
out of pure curiosity...did you pass the DSP exam...^0^
Wtf