Scroll through my playlist ua-cam.com/play/PL0NPansZqR_b0aUQvYlgfedyEO28oiGX9.html&si=5lXX5aPGaqWofHYQ for a comprehensive (growing) series of mini lectures and tutorials on calculus! 😊 Please don’t forget to like and subscribe for lots more infinite free accessible math content that you will love watching! 🎉
I recently started to relearn Cal 1 & 2 and eventually will get to differential calculus. This was quite informative. When I first learnt it, I feel like I was just learning to do it just to get it done.
Hi @SCKentrol thank you so much for your comment and for sharing! 😊I am so happy that you found the video informative! I've got lots of mini-lectures/tutorials/problem solving for calculus on my channel and it's organized in a (growing) playlist too ua-cam.com/play/PL0NPansZqR_b0aUQvYlgfedyEO28oiGX9.html I hope you have an amazing day/evening/night! 😊
Hi @jlmassir thank you so much for your comment! 😊 Of course, yes, you are right! 😊 The points x = -2 and x = 1 are not in the domain of f(x) and so cannot be discontinuities under the rigorous definition of "discontinuity" (for anyone else reading this: a point where the function is defined, but the limit of the function at the point does not equal to the function value at the point). In this video, I am using the word "discontinuities" more liberally to refer to holes, jumps, vertical asymptotes etc. where "the graph of the function breaks". Aside from this technicality, the video classifies the behaviour of the function at x = -2 and x = 1, which is the main conceptual point, although you are right (and it is important) to point out that technically these aren't "discontinuities". I just use the word for lack of a better term and it is sometimes common to do so in calculus problem solving, but I should have addressed this in the video. I hope you have an amazing day/evening/night! 😊
Scroll through my playlist ua-cam.com/play/PL0NPansZqR_b0aUQvYlgfedyEO28oiGX9.html&si=5lXX5aPGaqWofHYQ for a comprehensive (growing) series of mini lectures and tutorials on calculus! 😊 Please don’t forget to like and subscribe for lots more infinite free accessible math content that you will love watching! 🎉
I recently started to relearn Cal 1 & 2 and eventually will get to differential calculus. This was quite informative. When I first learnt it, I feel like I was just learning to do it just to get it done.
Hi @SCKentrol thank you so much for your comment and for sharing! 😊I am so happy that you found the video informative! I've got lots of mini-lectures/tutorials/problem solving for calculus on my channel and it's organized in a (growing) playlist too ua-cam.com/play/PL0NPansZqR_b0aUQvYlgfedyEO28oiGX9.html I hope you have an amazing day/evening/night! 😊
It has no discontinuities. It is not defined at -2 and 1.
Hi @jlmassir thank you so much for your comment! 😊 Of course, yes, you are right! 😊 The points x = -2 and x = 1 are not in the domain of f(x) and so cannot be discontinuities under the rigorous definition of "discontinuity" (for anyone else reading this: a point where the function is defined, but the limit of the function at the point does not equal to the function value at the point).
In this video, I am using the word "discontinuities" more liberally to refer to holes, jumps, vertical asymptotes etc. where "the graph of the function breaks". Aside from this technicality, the video classifies the behaviour of the function at x = -2 and x = 1, which is the main conceptual point, although you are right (and it is important) to point out that technically these aren't "discontinuities". I just use the word for lack of a better term and it is sometimes common to do so in calculus problem solving, but I should have addressed this in the video. I hope you have an amazing day/evening/night! 😊
@@MathMasterywithAmitesh Thank you for responding, my friend. Keep up the very good work!