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Time slot 29-30 minutes (4-x) P2=(4-x)! /(2-x)! =(4-x) (4-x-1)(4-x -1-1)!/(2-x)! =(4-x) (3-x) (2-x)! /(2-x)! =(4-x) (3-x) Then (4-x )(3-x) =6=6*1=3*2 4-x =6 or 3 or 2 x = -2 x= 1 x =2 Putting these values we see only if x =1 the equation is satisfied
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Sir 28:20 er example tar answer 1
Sir ekhane akta math bhul hoyeche 28:18 jeta koriyche ota (4-x) (4-x-1) (4-x-2) hobe and the answer is 1
right
x =1 or -2 or 2
Please see my comment
Time slot 29-30 minutes
(4-x) P2=(4-x)! /(2-x)!
=(4-x) (4-x-1)(4-x -1-1)!/(2-x)!
=(4-x) (3-x) (2-x)! /(2-x)!
=(4-x) (3-x)
Then
(4-x )(3-x) =6=6*1=3*2
4-x =6 or 3 or 2
x = -2
x= 1
x =2
Putting these values we see only if x =1 the equation is satisfied
Khub help holo video ta thaka
Time slot 16-46
n! =n(n-1)(n-2)!
U have written
n(n-1)!(n-2)!
which is not correct.
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Time slot 22-23 question may be corrected
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Sir, ami 2023 pass out kintu amr marks khub baje jar jonno ami onek kichu te atke jachhi . Etar jonno ki kono improvement marks ba re examination hoi ?
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18:20