Higher Order Functions in Swift : iOS Interview Series#03

[@anweshannu2518]

Thanks for the video expecting many more

[@SandeepSingh-lg7bq]

Thanks Mayank for a very nice & precise explanation

[@iosmayank]

Glad that you liked it :)

[@SandeepSingh-lg7bq]

@@iosmayank Plz post some more Interview question videos, thanks in advance

[@iosmayank]

@@SandeepSingh-lg7bq Sure, stay tuned :)

[@bharadwajmanchalla2370]

Nice video, was helpful thanks Mayank!

[@iosmayank]

Thanks :)

[@ashikashettyheradi9213]

Quick and helpful.Thanks!

[@iosmayank]

Glad that you liked it :)

[@ubelakroft9469]

This is clutch because its short and concise. Thanks!

[@iosmayank]

Thanks @Ubela Kroft :)

[@MandeepSingh-ly3jj]

Bro its awesome explanation about Higher order function , I am all clear about it :))

[@iosmayank]

Hi Mandeep, I'm glad that you liked the video :) Stay tuned.

[@harshkumarraj6896]

let numbers : [Int] = [0,2,8,5,3]
(a,b) -> Bool in
print("a = \(a)")
print("b = \(b)")
print(a>b)
return a>b
}
print(descOrder)
}
Why a[0] is showing 2 and a[1] shows 0 while using Bool in. Pls eloborate closure once. Thanks