Calculate the Intensity When dB (Decibel) Value is Given

[@joho-z]

Thank you! Even after 3 years, people are benefitting from this video.

[@Eduardo-tq5sk]

Thank you Doctor!

[@yassaashraf04]

These type of vids are life savers especially that j have finally coming up today

[@heavymetal3rocks]

Thanks! That was a great help. The teacher didn't show the steps of his working and I was confused about how the log disappeared.

[@snort455]

Great presentation. Im used to seeing instructor write each step toward the solution. Your method makes it much clearer.

[@denissemedina4619]

Simple and straight to the point. Thank you!

[@charweezyy]

thank u for this, i was struggling with a question similar to this. also i love your astronomy website !!!

[@naders.]

Thank you professor that really helped me out!

[@rabiaswati4068]

Thank you sir .lots of love and respect for you .I was really confused that how to solve it .Your video helped me . Again thanks sir

[@tillers1239]

Thank you Dr Clements!

[@steelriverr]

clutched heavy, glooks greg Clements, thank you for the vid!!

[@theoriginals9197]

This is very helpful thank you sir

[@amandaarmstrong1212]

GOD BLESS finally a solid answer!!!!

[@Eduardo-tq5sk]

Thank you professor!

[@hannamonique853]

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[@brightofhope7726]

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[@mochinyu8578]

TYSM YOU SAVED ME THANKS!!!

[@salleyne1112]

Thanks very much!

[@somapatra5522]

Thanks sir.....it's really helpfulll

[@collegebiology7446]

very simple and easy thanks

[@saktepakmu4551]

Thanks sir

[@lpspinkfoxes]

Thank you! This was very helpful

[@flake2190]

Thank you for this!

[@alliahboyne7138]

Thank you so much!!😭

[@qalidaxmad8716]

Bro thank you so very much 🙈🙈❤❤❤❤

[@subheemkumar2037]

Thank you 🙂

[@lyrajaro6997]

Thank you..

[@mjohnmoros]

What concepts can you guide me to learn, so that I can understand this?

[@GregClementsScience]

The main concept for this decibel problem is that the unknown, I, intensity, is under the control of the log function. Please read until the end of this paragraph. Then if this explanation isn't clear look up "functions and inverse functions" in a PreCalculus textbook, or look at the Khan academy video on inverse functions. The effect of a function can be canceled by applying its inverse function to the function. e.g. Suppose some function is acting on, or in control of, the number 7. If you apply the inverse of the function to the function acting on 7, the result is 7. In order to remove I, intensity, from the control of the log function we must apply the inverse function of the log function, which is 10 raised to a power. e.g. 10^( log(7) ) evaluates to 7. Note that the inverse function must be applied to both sides of the equation. In this problem, both sides of the decibel formula become the power of the base 10.

[@IHappyChicken]

Thank you!!!

[@jacobstubler7966]

Very helpful! Thanks

[@erandiesayumika1813]

Thanks 😍

[@shaynemaratas9055]

THANKYOUUUUUUU

[@khumbanibudha3773]

Tysm

[@corinth2782]

Thanks !

[@soyMultifandom-x4k]

ahora si es verdad que no entendi nada del video ni siquiera lo que dijo .___.

[@MalihehNilghaz-tv6xi]

👍👍👍👍

[@zumranacademy9262]

Maqsad app gives wrong answer

[@humakhan7982]

how 10 power -3.8 convert to 1.5 10 power 4

[@GregClementsScience]

Use a calculator that has a 10^x function key. Use -3.8 for the x value and the calculator will give a result of 1.585 x 10^-4. Or, Change 10^(-3.8) to 10(+0.2) times 10^(-4). Use a calculator to evaluate 10 (+0.2) which yields 1.585. Now you have 1.585 times 10^(-4).

[@albertianjavier2646]

currentdB is 20log (Io/Ii) ; powerdB is 10log(Po/Pi)

[@harsh.sharma]

Sounds like Donald Trump. 😅

[@everestchannel1320]

He is the one 😂

[@tanvirahmed1406]

thanks sir

[@zumranacademy9262]

Maqsad app gives wrong answer