When balancing the oxygen (for example in combustion) do you have to do it as top heavy fraction or would i still get the marks by multiplying everything out by 2 to use whole numbers to balance.. thanks!
When forming haloalkanes by substitution are the products the haloalkane, NaHSO4 and water? In another video it said a haloalkane and NaOH. In a textbook it said a haloalkane, Na+ and water. Please can you explain which one it is? Thanks
It would be the NaOH, this is because the alcohol (OH) is being substituted for a halogen and would result in the hydroxide being a product with the sodium
Thank you sooooo much from Hong Kong.
this explained it so much more better!
Thanks for that 🙏
When balancing the oxygen (for example in combustion) do you have to do it as top heavy fraction or would i still get the marks by multiplying everything out by 2 to use whole numbers to balance.. thanks!
Totally fine to do it either way, unless it’s an enthalpy change of combustion reaction then you must have one mole of the substance
Thanks for this video! Very easy summary to understand for revision👍
さばくのあや Great to hear, thanks! That’s the whole point of these videos 😊
When dehydrating alcohols, why do we remove the hydrogen from the adjacent carbon instead of the same carbon which had the -OH?
A double bond needs to form
thank u!!
When forming haloalkanes by substitution are the products the haloalkane, NaHSO4 and water? In another video it said a haloalkane and NaOH. In a textbook it said a haloalkane, Na+ and water. Please can you explain which one it is? Thanks
It would be the NaOH, this is because the alcohol (OH) is being substituted for a halogen and would result in the hydroxide being a product with the sodium