i could never figure out how constants from the integration worked, but for some reason when you said it, it all made sense. go figure I had to go watch a lord jeff video
HELP LOL! I wanted to try work Section 2 from the left just to see and I get M=-4x*2+96x-576. I know that can't be correct since at x=0, I should get an internal moment of -432 to counter the reaction moment of +432. I've gone over my result several times and can't see where I went wrong. Really appreciate if someone had a look. Thank you in advance :)
Your equation for the moment is correct. Remember, the domain for this moment isn’t for the whole length of the beam. Only for the second half where the distributed load acts (6
You sir belong in the hall of fame of professors 🔥
I love your videos! You make hard concept easy to understand, I don’t think I can be an engineer without your videos.
Solids final tomorrow and you saved my grade!
Thank you Professor Hanson! Your videos are always excellent and illustrate these engineering concepts clearly.
i could never figure out how constants from the integration worked, but for some reason when you said it, it all made sense. go figure I had to go watch a lord jeff video
I have my intro to structural engineering exam 2 this Friday and this will definitely help
thank you so much sir,, for those awesome explanation!!!
Is this a discontinuous function please? Our professor has mentioned something about macaulay's method. Thank you so much for another great video
I miss classes to work but overnight prof Jeff sums all keep up sir🔥
Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))
LEGEND
when taking the moment about c for the second cut, why do you divide the distance by 2?
The resultant force of the distributed load is located at half of the distance of X2
Thanks !
Proff Jeff how about cliperyon theorem please 🙏
How do you draw the shear moment for this???
i dont understand how 8KN/m turned to be negative? thank you for sharing
I can't find lesson 64 on mechanics of materials.
I have solid test on wednesday..,wish me luck
Damn that was good!
why is it 48*9 if 48kn/m was distributed amongs 6 meters, and not 3?
Distributed load acts on half the length
goat
I didn't see lesson 64
Okayyy lesss goo (MEME)
HELP LOL! I wanted to try work Section 2 from the left just to see and I get M=-4x*2+96x-576. I know that can't be correct since at x=0, I should get an internal moment of -432 to counter the reaction moment of +432. I've gone over my result several times and can't see where I went wrong. Really appreciate if someone had a look. Thank you in advance :)
Your equation for the moment is correct. Remember, the domain for this moment isn’t for the whole length of the beam. Only for the second half where the distributed load acts (6
@@judeugwu4987 Ahhhh...ok, I'll take a look, thank you for looking at it.
First!