Две параболы пересекаются в четырёх точках. Две из них легко находятся подбором, у остальных a=b - обычное квадратное уравнение через дискриминант. Задача на две минуты максимум.
Presenter, please note that the way UA-cam recommends items means that some of us just recently saw your video on the corresponding case for a & b being 8 & -9. This time you just added the a=b cases, but most of the presentation was naturally just repetition.
a^2-b=b°2-a ; i,e a^2-b^2+a-b=0 ; i,e (a+b)(a-b)+1(a-b)=0 ; (a-b)(a+b+1)=0 : i,e a=b or a+b=--1; when a=b then b^2-b-13=0 : i,e b= [1+√53]/2 or [1-√53]/2 ; so a=[1+√53]/2 or [1-√53]/2 ; when a+b=-1 then a= -1-b ; so, 1+2b+b^2-b-13=0 ; i,e b^2-+b-12=0 ; i,e (b+4)(b-3)=0 i,e b=-4 or b=3 ; when b=-4 then a=3 & when b=3 then a=-4
This is the time of exam when you know the question is of 2 marks but teacher has marked it as a 15 so you do what you can to extend the answer😅😅😅😅😅😅😅😅😅😅😅😅😅
"( )" are parentheses ... "(" open parenthesis, and ")" close parenthesis "[ ]" are brackets ... "[" open bracket, and "]" close bracket Also to avoid confusion when using quadratic formula: use x and y NOT a and b. So use x^2 - y =13 and y^2 - x = 13
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Thank you for the clear and comprehensive explanation!
Две параболы пересекаются в четырёх точках. Две из них легко находятся подбором, у остальных a=b - обычное квадратное уравнение через дискриминант. Задача на две минуты максимум.
Presenter, please note that the way UA-cam recommends items means that some of us just recently saw your video on the corresponding case for a & b being 8 & -9. This time you just added the a=b cases, but most of the presentation was naturally just repetition.
Indian style, make anything simple complicated.
Ha ha
a = - 4 and b = 3 are satisfying values
Fully explained
#essessbiieducation
a^2-b=b°2-a ; i,e a^2-b^2+a-b=0 ; i,e (a+b)(a-b)+1(a-b)=0 ; (a-b)(a+b+1)=0 : i,e a=b or a+b=--1; when a=b then b^2-b-13=0 : i,e b= [1+√53]/2 or [1-√53]/2 ; so a=[1+√53]/2 or [1-√53]/2 ; when a+b=-1 then a= -1-b ; so, 1+2b+b^2-b-13=0 ; i,e b^2-+b-12=0 ; i,e (b+4)(b-3)=0 i,e b=-4 or b=3 ; when b=-4 then a=3 & when b=3 then a=-4
This is the time of exam when you know the question is of 2 marks but teacher has marked it as a 15 so you do what you can to extend the answer😅😅😅😅😅😅😅😅😅😅😅😅😅
AA - B = 13 , BB - A = 13 ; A,B ?
* 13 = 16-3 = 4x4 - 3 = AA- B
* 13 = 9+4 = 3x3 +4 = BB-(-A)
** A = -4 , B = 3 ./.
A=-4,B=3
"( )" are parentheses ... "(" open parenthesis, and ")" close parenthesis
"[ ]" are brackets ... "[" open bracket, and "]" close bracket
Also to avoid confusion when using quadratic formula:
use x and y NOT a and b. So use x^2 - y =13 and y^2 - x = 13
Would you suggest me some books for Algebra?
a=-4,b=3
a=-1/2,b=-1/2
A=-4
B=3
Easy. a = -4, b = 3.
Have to get the a=b case too
3, -4
can't use b to be two different variables at 3:46
3/4
A=minus 4&b=3.
A=-4 & b=3 *?
Lindo