Thanks for the video! In the first example, would the last term of heaviside functions (u3-u4) be subtracted instead of added onto the equation since it is dropping at t=3?
@@ericcytrynbaum Thank you, I would like to create an Heaviside H(x) function that creates an increasing ramp whenever another function f(x) composed by irregular impulses is = 0. This is for tracking the timing between the impulses (the maximum of the ramp=time between the two specific impulses). However, I'm struggling in trying to make the ramp starting from 0, because the easiest way is to make the Heaviside = x whenever f(x) is equal 0, but in this case, the ramp starts from the actual value of x and not from 0. I would have to subtract something but I don't know what, because this is not known in advance, and if I would already know the spacing between the impulses, I wouldn't need the ramp ...
@@ericcytrynbaum Thank you very much. It seems this fits well for regular impulses. But if the impulses are not regular, I'm trying to find a rule to make the ramp starting from 0 whenever f(x)=0 like H(x)=[f(x)
great explanation
Thanks for the video! In the first example, would the last term of heaviside functions (u3-u4) be subtracted instead of added onto the equation since it is dropping at t=3?
I included the minus sign in the function (4-t) so your suggestion would be correct if you changed that to (t-4).
I can't get the slopes part & substracting part
great explanation, thanks!
Nice explanation
Is it possible to write a ramp than increases from 0 whenever f(x) it's 0?
I’m not sure what you mean.
@@ericcytrynbaum Thank you, I would like to create an Heaviside H(x) function that creates an increasing ramp whenever another function f(x) composed by irregular impulses is = 0. This is for tracking the timing between the impulses (the maximum of the ramp=time between the two specific impulses). However, I'm struggling in trying to make the ramp starting from 0, because the easiest way is to make the Heaviside = x whenever f(x) is equal 0, but in this case, the ramp starts from the actual value of x and not from 0. I would have to subtract something but I don't know what, because this is not known in advance, and if I would already know the spacing between the impulses, I wouldn't need the ramp ...
@@gradozero8140 If the impulses are at times t_i, then maybe you want something like this: g(t) = sum over i of (H(t-t_i)-H(t-t_{i+1}))(t-t_i) ?
@@ericcytrynbaum Thank you very much. It seems this fits well for regular impulses. But if the impulses are not regular, I'm trying to find a rule to make the ramp starting from 0 whenever f(x)=0 like H(x)=[f(x)
Well done, I like the explanation!
there were no laplace transforms in this video. thanks by the way
Good point. The title is a bit misleading, I guess.
Gracias
H(1-|t|) explanation please
This didn't appear in the video but it's just a slick way of writing a function that is 1 for -1
The title sucks, indeed. but the content is great, thanks!
Good point. Changed.
unfortunetly, you havent taught us really.and you have done it probably intentioanally.
he made this Video not for u , so be nice if u dont unterstood what he did