To calculate the output capacitor, it should be considered that how many cycles it takes for the voltage to stabilize when the output load changes. And normally this should take at least ten cycles. This means that the calculated capacitor should be at least 2000 microfarads. Due to this issue, the capacitor of the flyback converter is more than the calculated value.
The output of the fullwave bridge rectifier frequency is 100 Hz .So the time of 1cycle is 1/100= 10 msec. So the capacitor has to supply power during that time. So if we take during that time the voltage if the capacitor is reduced to 1/ 1000= 120×1/1000= .12volt will be reduced during each cycle
@@prasanthr3875 Hi, thanks for the reply, is it always the case where it will be reduced to 1/1000? Is there a reference where you can guide me to on this? :)
Nice video .
To calculate the output capacitor, it should be considered that how many cycles it takes for the voltage to stabilize when the output load changes. And normally this should take at least ten cycles. This means that the calculated capacitor should be at least 2000 microfarads. Due to this issue, the capacitor of the flyback converter is more than the calculated value.
Hi at 8:03, can you please explain why 1/1000 x 120V?
Like why is 1000 used. :)
The output of the fullwave bridge rectifier frequency is 100 Hz .So the time of 1cycle is 1/100= 10 msec. So the capacitor has to supply power during that time. So if we take during that time the voltage if the capacitor is reduced to 1/ 1000= 120×1/1000= .12volt will be reduced during each cycle
@@prasanthr3875 Hi, thanks for the reply, is it always the case where it will be reduced to 1/1000? Is there a reference where you can guide me to on this? :)
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