+himanshu Kumar Hi Himanshu.... Glad to know that you have benefited from my videos.... All the best and do let your friends know about this channel so that they can also benefit.....
Hello sir, this is me Jaideep from Gujarat. I have learn engineering drawing from your channel and recently I am learning applied mechanics from your channel. And completed till this in engg drawing. I recently made a comment on applied mechanics' video, thanks for the reply and I'm pretty sure that you will get students'support for this great work. And this is my actual account. And again a great thanks to you.
Sir can u please make a video on how to know whether a line is visible or invisible . Especially in cones and other prisms it becomes very difficult to know that. thank you.
Hi Shreyash............ Well Thanks for appreciating my work... All the best in life And if you wanna support my channel visit this link: manaspatnaik.in/?page_id=401 Small contributions can make a Big Difference
Thanks sir for your amazing lecture ever I have seen. Sir, there should be given in question whether apex is away or near the v.p with reespect to base so as we get more clarity. Actually sir i first solve your question in the mind and then see your video so on that time i confused where apex should be as it is not given in question.
Could we have measured 45° clockwise? Because even then the axis would be inclined at 45°. Also, is this where the terms 'apex is nearer to observer or far from observer' used? I seem to miss the difference between apex is nearer to observer or far from observer. Thanks😊
If the axis is inclined to one of the reference plane then we have to make axis perpendicular to that plane,isn't it?But what about if the axis is given inclined to both the reference planes?What should be assumption?
+hema lakshmi i am surely gonna start making tutorials on isometric views. And hema some other students also have requested the same....do subscribe to be informed.......
A right circular cone, 40 mm base diameter and 60 mm long axis is resting on Hp on one point of base circle such that its axis makes 45° inclination with Hp and 40°
Sir, what is the difference between phi and beta angles in the projection of solids.How do they differ?Please create a video for comparison of real and apparent angles in solid projections.
a cone 40 mm diameter and 50 mm axis is resting on one of its corner on v.p. the axis in the front view makes 30° inclinations with hp. draw its projections
+tejaswanth mucheli Hi Tejaswanth.... Thanks for appreciating the content.... All the best and do let your friends know about this channel so that they can also benefit...
hey bro !!. its given that beta =45 ..since top view angle is given(which is obviosly the apparent angle).., what we will be seeing is the top view length right (i mean the apparent length) and not the real length..so basically what i am asking is "dont we need to find out the apparent length of the the axis and then proceed? ". but here what you have done is you just carried the whole procedure with the true length of the axis.. (and also i dont know what i am talking is right )
Anand....Let me try to put things in the right perspective..... Step 3: Here the Top view from step 2 has been recreated making sure that the axis (TV) is kept at 45 degree (Beta) Thats all i can say.... If u still have confusion, then we can have a chat on Facebook messenger..... Hope this helps........
A pentagonal pyramid base 25 mm and height 65 mm stands with its base on hp and edge of the base parallel to vp and nearer to it.Asection plane cuts the pyramid at 30 degree inclind to hp and [passes through the a point on the axis at a distance of 20 mm from the apex. Draw the isometric view of the truncated pyramid
sir i have a question plzz solve it i need it right now a request sir ...A right circular cone diameter of base 40mm and height 52mm is held on its base rim on ground such that its axis is inclined at 45degree to Vp and is parallel to Hp ...draw its projections when its axis is turned away from the Vp
Hi Vanishka.... Thanks for appreciating the content Do watch all the videos on drawing and mechanics...... And also let your your friends know about this Channel so that they can also benefit.......
Dear Sir, Happy New year. Will you please publish a video on solving a problem.i.e. to draw a cone of base 40 mm diameter and axis 60mm long rests on HP on a point in the circumference of the base with one of it's slant generator perpendicular to HP and parallel to VP.
If you can adjust the darkness and thickness levels by the pencil tip manually then that's great. But everybody cannot do the same stuff, that's why different sets of pencils are recommended. I hope you get my point.
A cone resting on its generators on hp and axis inclined to vp where the condition is apex should be near to vp what would be it's projection?Can u please tell me sir..
Sir.. You are drawing front view from XY line itself... But some people leave some space above XY line.. And they start drawing from there... Which is correct
Sir if a cone is rests on the ground on a point of its base circle what would be the 1st and 2nd steps sir plz help me with ur answer sir could u plz tell what is the difference between resting and standing could it workout to all solids?
U said that if axis makes angle with V.P. then first thing that is drawn is front view to see true shape of object... But here u drew top view.. why so?Iam confused
ques- Draw three view of cone , base 50mm diameter and axis 75mm long, having one of its generators in V.P. and inclined at 30° to H.P. , the apex being in the H.P.
Sir means like this question..... A pentagonal pyramid side of base 25 mm and height 45 mm long is resting on one of its rectangular faces on the hp with its axis parallel to vp? So sir in this question ho we know that the Pentagon's base or tip point will be in left or right side???
+Anurag Mishra ANurag....ye question ek baar check kro.....look if its a pentagonal pyramid then it will rest on one of its triangular face, whereas if its a pentagonal prism then its resting on its rectangular face...... ANyway i am assuming this as a pentagonal pyramid resting on a triangular face on HP... Anurag post your whatsapp number and i will give u a trick as to how u can solve these kind of problems.....
A cone of base 60 mm diameter and axis 80mm long rests on hp with axis inclined 45degrees to it. Draw its projection when the top view of axis is parallel to vp Sir could you please explain this problem
chirag i would advise you not to get into the technicalities of english grammar. The idea is to make sure that the top view of the axis is inclined to VP and then its corresponding final front view is to be constructed....
Uzair Tak thats the auxilliary inclined plane method of solid projection where u dont recreate the solid in the next step, rather u change the position of reference plane..... Take my word this method is very conventional and also popular.... You can draw it by this method.... Your choice Uzair.....
are you talking about that rotation method? no i dont think it is using that.what i meant to say that there are some problems in the book which say that the draw the projection when the object lies in : ground plane as well as horizontal plane...thats what i was confused about
Supriya............Look in step 1 the cone is kept standing on HP. You can also say that it is resting with its base on HP.. Now just think about this...as to from which view u can see the true shape of the base....Allright.....You will realize that the true shape of the base can only be seen from the top, and hence circle in the top view has been constructed initially and then its corresponding front view is gonna be made..... Hope this helps.............
A cone with base 30mm diameter and axis 45mm long lies on a point of its base on VP such that the axis makes an angle 45° with VP. Draw the projections of the cone
That's too much work to do everything on the board..Huge respect..
Dear sir, your videos are very useful for student. I scored 90 marks after watching your videos.
Thank you
+himanshu Kumar
Hi Himanshu....
Glad to know that you have benefited from my videos....
All the best and do let your friends know about this channel so that they can also benefit.....
Excellent free hand drawing... Awesome explanation too.....
Engineering Drawing | Engineering Graphics |: ua-cam.com/play/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS.html
Thank you so much sir your the best teacher in this plateform
Thank you so much
Your all videos are very helpful us ♥🙏
It was simple and briefly explained, because simplicity is the best way in teaching.
Which CLG u teach sir
Hello sir, this is me Jaideep from Gujarat. I have learn engineering drawing from your channel and recently I am learning applied mechanics from your channel.
And completed till this in engg drawing.
I recently made a comment on applied mechanics' video, thanks for the reply and I'm pretty sure that you will get students'support for this great work.
And this is my actual account.
And again a great thanks to you.
Hello jimmy..... Do get in touch with me on FB messenger.....
Ok sir
Sir can u please make a video on how to know whether a line is visible or invisible . Especially in cones and other prisms it becomes very difficult to know that. thank you.
Sir you are my hero. because of you only i scored 98 marks in ed.
Thank you
Sir, u r great u just make the problems so eiseir that we can't understand in regular clasess, glad to find ur channel, your videos are really helpful
Hi Shreyash............
Well Thanks for appreciating my work...
All the best in life
And if you wanna support my channel visit this link: manaspatnaik.in/?page_id=401
Small contributions can make a Big Difference
I've learnt various structures,and I hope this will provide me with a wide range of knowledge in designing.
Ya it will.....
This subjects is like a beginner course in technical drawing and designing...
U really nailed the topic sir huge respect on you sirr
hats off to your work sir...
Thanks sir for your amazing lecture ever I have seen.
Sir, there should be given in question whether apex is away or near the v.p with reespect to base so as we get more clarity.
Actually sir i first solve your question in the mind and then see your video so on that time i confused where apex should be as it is not given in question.
Could we have measured 45° clockwise? Because even then the axis would be inclined at 45°.
Also, is this where the terms 'apex is nearer to observer or far from observer' used?
I seem to miss the difference between apex is nearer to observer or far from observer.
Thanks😊
Did you get the answer for the question? pls reply if you do.
Why did he take the 45 degrees from the right
If the axis is inclined to one of the reference plane then we have to make axis perpendicular to that plane,isn't it?But what about if the axis is given inclined to both the reference planes?What should be assumption?
sir....your tutorial is very useful....but one small request...please upload some videos in isometric projection.
+hema lakshmi i am surely gonna start making tutorials on isometric views. And hema some other students also have requested the same....do subscribe to be informed.......
+Manas Patnaik
The first video on isometric drawing has been uploaded......do watch it and like and comment........
A right circular cone, 40 mm base diameter and 60 mm long axis is resting on Hp on one point of base circle such that its axis makes 45° inclination with Hp and 40°
Sir, what is the difference between phi and beta angles in the projection of solids.How do they differ?Please create a video for comparison of real and apparent angles in solid projections.
a cone 40 mm diameter and 50 mm axis is resting on one of its corner on v.p. the axis in the front view makes 30° inclinations with hp. draw its projections
Hello sir i am poor at drawing but after watching your videos I've got some confidence on drawing exam❤. Thanks a lot
Sir i have a doubt i think u did projection of cone when phi =45 degrees when beta
Is used we need to find the loci and find top view right?
Thanks for ur precious lectures sir!!!
+tejaswanth mucheli
Hi Tejaswanth....
Thanks for appreciating the content....
All the best and do let your friends know about this channel so that they can also benefit...
Manas Patnaik sure sir!!
hey bro !!. its given that beta =45 ..since top view angle is given(which is obviosly the apparent angle).., what we will be seeing is the top view length right (i mean the apparent length) and not the real length..so basically what i am asking is "dont we need to find out the apparent length of the the axis and then proceed? ". but here what you have done is you just carried the whole procedure with the true length of the axis.. (and also i dont know what i am talking is right )
Anand....Let me try to put things in the right perspective.....
Step 3: Here the Top view from step 2 has been recreated making sure that the axis (TV) is kept at 45 degree (Beta)
Thats all i can say....
If u still have confusion, then we can have a chat on Facebook messenger.....
Hope this helps........
In 4th step half of the elipse should to dotted line and another normal line which of the points are dotted line? Whether "c d e f g" or "g h a b c"
A pentagonal pyramid base 25 mm and height 65 mm stands with its base on hp and edge of the base parallel to vp and nearer to it.Asection plane cuts the pyramid at 30 degree inclind to hp and [passes through the a point on the axis at a distance of 20 mm from the apex. Draw the isometric view of the truncated pyramid
Super sir your idea in making arc hatsoff
sir i have a question plzz solve it i need it right now a request sir ...A right circular cone diameter of base 40mm and height 52mm is held on its base rim on ground such that its axis is inclined at 45degree to Vp and is parallel to Hp ...draw its projections when its axis is turned away from the Vp
u are a genius
both english and ED superb :D hopethis year i will clear this exam now :D
Thanks shani for appreciating my work...
Do encourage your friends also to subscribe and learn from this channel.....
All the best in life....
All video is very awesome . thankyou so much sir
Hi Vanishka....
Thanks for appreciating the content
Do watch all the videos on drawing and mechanics......
And also let your your friends know about this Channel so that they can also benefit.......
Excellent drawing
Your videos are very useful sir, thank you
Enjoy and all the best.....
Dear Sir, Happy New year. Will you please publish a video on solving a problem.i.e. to draw a cone of base 40 mm diameter and axis 60mm long rests on HP on a point in the circumference of the base with one of it's slant generator perpendicular to HP and parallel to VP.
Can you upload it in animation, sir.
So that it will be easily visible the point and all..
Need ur help sir in CAD also.
Sir it is necessary necessary to follow HB,h,2h pencils or we can draw with only one pencil
If you can adjust the darkness and thickness levels by the pencil tip manually then that's great. But everybody cannot do the same stuff, that's why different sets of pencils are recommended.
I hope you get my point.
I usually go for H pencil and I am able to draw thick as well as thin lines with ease.
sir thanks for all this video this are very useful
+Rohan Singh thanks bro
i want to know how identify the shape of hexagonal or Pentagon accordingly questions
A cone resting on its generators on hp and axis inclined to vp where the condition is apex should be near to vp what would be it's projection?Can u please tell me sir..
pranali suryawanshi I think it would be given in question
Sir.. You are drawing front view from XY line itself... But some people leave some space above XY line.. And they start drawing from there... Which is correct
Both are fine.,...
Doesn't matter as in both the cases base will be parallel to HP
Sir nice teaching
Sir if a cone is rests on the ground on a point of its base circle what would be the 1st and 2nd steps sir plz help me with ur answer sir could u plz tell what is the difference between resting and standing could it workout to all solids?
Sir ,great piece of work
U said that if axis makes angle with V.P. then first thing that is drawn is front view to see true shape of object... But here u drew top view.. why so?Iam confused
ques- Draw three view of cone , base 50mm diameter and axis 75mm long, having one of its generators in V.P. and inclined at 30° to H.P. , the apex being in the H.P.
Yr videos are super best and ossum
Excellent explanation sir
Thanks pratyush and keep working hard
Sir will you put videos from projection of solids without the angle
Legend
How can u draw such straight lines without a scale
Sir can we do this problem in 2 steps.
Step 1 : directly keeping on HP with axis perpendicular to VP .
Step 2 : tilt the axis.
Excuse me ,sir
generator on the ground or generator on the HP. these both condtions are same or different.ans me sir?.
Apex should be near to the observer so the angle should be from left side 45degree
Sir if base edge is parrallel to vp or hp... I'm confused in this.. How to draw the hexagon
sir will there be a difference if instead of cone it is asked right cicular cone
Thankyou very much ,it helped me a lot.... sir ..
Sir that 45degree line can I draw it from left to right as you have drawn it right to left. Are both right sir
Yes narsimha..... U can do that
Thank you sir
Sir one help plz... Sir i am very much confused in solid i dont know where to put tip point of pentagon to left right so plss give suggestions
+Anurag Mishra
ANurag it would be better if u can write the description of that problem...
Sir means like this question..... A pentagonal pyramid side of base 25 mm and height 45 mm long is resting on one of its rectangular faces on the hp with its axis parallel to vp? So sir in this question ho we know that the Pentagon's base or tip point will be in left or right side???
+Anurag Mishra
ANurag....ye question ek baar check kro.....look if its a pentagonal pyramid then it will rest on one of its triangular face, whereas if its a pentagonal prism then its resting on its rectangular face......
ANyway i am assuming this as a pentagonal pyramid resting on a triangular face on HP...
Anurag post your whatsapp number and i will give u a trick as to how u can solve these kind of problems.....
8357084691
Manas Patnaik sir.. Pls tell its urgent
A cone of base 60 mm diameter and axis 80mm long rests on hp with axis inclined 45degrees to it. Draw its projection when the top view of axis is parallel to vp
Sir could you please explain this problem
Nice explanation
Keep watching
Sir How to incline a solid in vp in which angle forms towards vp or away from vp
Hello Sir....How to find beta.....if the angle is not given...
Sir please post videos of apparent and true lengths and freely suspended prism also
Even i was thinking of making a video on freely suspended objects...
Your request has been noted....
It shall be done asap....
Interesting class
Really usefull sir thankyou
Thank you sir apne mera ek confusion dur kar diya
All the best.
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sir inlined to vp or inclined from vp id diffrence ryt ??/
chirag i would advise you not to get into the technicalities of english grammar. The idea is to make sure that the top view of the axis is inclined to VP and then its corresponding final front view is to be constructed....
Sir where r u outside or inside so much of sound by vehicles so see once
Tq so much sir u made my day👌👌
Very helpful sir
Wow
Great sir
Sir 45 degree inclination jo aapne kiya right side se wo left se kr skte h
Shahid.......bilkul kar sakte hai...
Thank you very much sir , your video is useful for us and your teaching style is amazing
Nice Video 😊👍🏼🙏🏻
But my book (PS gill) shows that whenever a solid lies on ground that means Auxilllary horizontal plane
Uzair Tak
thats the auxilliary inclined plane method of solid projection where u dont recreate the solid in the next step, rather u change the position of reference plane.....
Take my word this method is very conventional and also popular....
You can draw it by this method....
Your choice Uzair.....
are you talking about that rotation method?
no i dont think it is using that.what i meant to say that there are some problems in the book which say that the draw the projection when the object lies in : ground plane as well as horizontal plane...thats what i was confused about
+Uzair Tak
Uzair its best to post the problem description in this comments section.....
Can you tell the Reference book ???
Thank you❤❤❤❤❤❤❤
Sir what will be the step if VP and HP in this problem gets reverse
Draw the projections of a cone, base 75 mm diameter and axis 100mm long lying on the hp on one of its generators with the axis parallel to the vp
sir,if possible keep the question below throughout the video,as we have to remember the question ..
could u pls exaplain this problem in auxiliary method
thank you sir
in step 3 on which side we must we take angle
you are doing really good man but one thing which is annoying is too many ads i wasted too much time watching ads 😑
Great videos Sir!!!
Sir,what if the generator of the cone is on VP??
Sir why did uhh place the circle in first step in top view??
Supriya............Look in step 1 the cone is kept standing on HP.
You can also say that it is resting with its base on HP..
Now just think about this...as to from which view u can see the true shape of the base....Allright.....You will realize that the true shape of the base can only be seen from the top, and hence circle in the top view has been constructed initially and then its corresponding front view is gonna be made.....
Hope this helps.............
Got it sir.THANKYOU
Sir, if it's axis is parallel to VP than how it can be drawn?? Please help??
Then the solution will be only first two steps....
Thank u very much sir!
Nice sir
lol my sir also learns the topic from here ,,,,,coz he is #guruji
Thank you so much sir
Super sir
Very good
Sir 80 degree with the HP and passing through the apex I'd type ka question bnao na sir
Take a bow sir!!!
I want vedios on isometric and perspective projection. Can u plz upload it on ur channel
It's already there search by perspective projection Manas Patnaik
Also search for isometric drawings Manas Patnaik
All the best.
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thanks
Thanks sir
Sir wo fig phle SE hi kyu Bana rakha hai
Thank you.
+hema lakshmi I forgot to say....Wish u a very happy diwali.....
sir you r toooooooooooooooooooooooooooooo gooooooooooooodddd .....reallyyyy thanxxxxx alot!!! :)
thanks sir ji , pass kra diya apne
You are welcome Neelansh.....
And all the best
A cone with base 30mm diameter and axis 45mm long lies on a point of its base on
VP such that the axis makes an angle 45° with VP. Draw the projections of the cone