import numpy as np a1 = [[1,2,3],[4,5,6]] arr = np.array(a1) if arr.ndim == 0: print(arr) elif arr.ndim == 1: row = 1 col = arr.size for i in range(row): for j in range(col): print(arr[i][j], end = " ") print() else: size = arr.shape row = size[0] col = size[1] for i in range(row): for j in range(col): print(arr[i][j], end = " ") print()
ndim() can be used to find the dimension 1D - list inside a function 2D - list of the list inside a function 3D- list of list of list inside a function, with the addition of each list, comes an extra square bracket
what about geomspace please tell us about geomspace
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How to know 1 d or 2d
by using np.ndim
import numpy as np
a1 = [[1,2,3],[4,5,6]]
arr = np.array(a1)
if arr.ndim == 0:
print(arr)
elif arr.ndim == 1:
row = 1
col = arr.size
for i in range(row):
for j in range(col):
print(arr[i][j], end = " ")
print()
else:
size = arr.shape
row = size[0]
col = size[1]
for i in range(row):
for j in range(col):
print(arr[i][j], end = " ")
print()
Sir still we are not clarity on dimensions
ndim() can be used to find the dimension
1D - list inside a function
2D - list of the list inside a function
3D- list of list of list inside a function,
with the addition of each list, comes an extra square bracket