Paul, I wanted to also say thanks. Your concise and factual videos are really appreciated. It's like having an on-demand course in RF engineering! Well done. 73 Lynn NG9D
thanks for the very good educative video. what happens if we have the maximum frequency very high so that the curve hit resistive line several times. if we do calculations for the second hit to the resistive line is it wrong? can you please elaborate? thank you.
Paul, I wanted to also say thanks. Your concise and factual videos are really appreciated. It's like having an on-demand course in RF engineering! Well done. 73 Lynn NG9D
Thanks! Education and training are very important to us here at Rohde & Schwarz. Really appreciate the feedback! 73, Paul, KO4LZ
That was excellent, thank you very much.
Thanks for the feedback!
Thank you for such useful video!
Thanks for the support!
thanks for the very good educative video. what happens if we have the maximum frequency very high so that the curve hit resistive line several times. if we do calculations for the second hit to the resistive line is it wrong? can you please elaborate? thank you.
HOW TO LAOD CABLE WITH 50 OHAM AS , I M NOT HAVING ELECTRONIC BACKGROUND KINDLY EXPLAIN
Just put 50 ohm terminator on the end of the cable.
300/4=75 ... but, c in copper is 200 (instead of 300), right? so, the formula should be 200/4=50 ... am i wrong ?