Trick for Slater's Rule, calculation of screening constant and effective nuclear charge.
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- Опубліковано 16 вер 2024
- In this video I explained the trick for Slater's Rule, calculations of screening constant and effective nuclear charge.
Correction :for Titanium
Ti (z=22) Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d2 4s2. If we want to calculate the screening constant for one d electron in 3d..(There will be no effect of 4s electrons in screening) Trick is : for electrons in nth shell (screening constant is 0.35) and for electrons in n-1, n-2,n-3 etc (screening constant is 1). Number of electrons in nth shell (3d +3p+3s)=10. Do minus 1. Because we are calculating sigma for that. So 9×0.35 =3.15 and number of electrons in n-1 and n-2 shells (2p+2s+1s)=10. So 10×1=10. Total screening constant is 3.15 +10 = 13.15. Effective nuclear charge = atomic number - screening constant
= 22-13.15 = 8.85.
Thank you all for your support.
came after watching amitabh sir lecture and got confused.. u cleared my confusion.. thanks..
Sameee
Sameee problem
Thank you mam, I do petroleum engineering and u have helped me so much, I also recommend anyone who needs explanation here in university when they come to me,am frm Uganda
Others-studying this in colleauges
Indians- class 11 😅
@@PoojaSharma-rb1ve are u preparing for jee
Insta id?
@@haker57_ I'd:beware of girls
Uganda!!!😳😳
Here we 16 yrs old ppl studying this 💀
mam one great avantage given by you is there are many (i dont know their efficiency) because they teach in hindi which many of south indians dont know and also your explanation is good thank mam
👍👍👍👍nice explanation mam
But using calculator for adding 18+.35
😂😂 maths is too much weak 😂
Mam is for chemistry not for maths🎉😅
I was also thinking 😂 weak maths
God bless you, ma'am for making this so easy for me to understand. The textbook is as well complicated. Stay blessed and God bless you again.
Zion Faye Thanku 😍
My very pleasure! 😄🙏🏿
Thanks mam.
When I saw my notes I didn't get anything but this video helps me a lot because I have exam tomorrow ..thank you man 🙏
Harish barman Thank you and if possible share this video with your friends.
Us bhai😭
l 💕 u mam
Bro years gone 😂, how did your exam go? Do you even remember this day now?
it helped me a lot for JEE preparation.Thank you for explaining clearly mam.
Did you clear JEE??
Amazing explanation mam , new buddies do watch the video she really taught very good 👍🙏🙏
Thank you so much ma'am, I was struggling in this topic since a very long time. You cleared all my doubts.
Madam I had a doubt i.e why you took 1 d electron in Titanium. @ 8:34. please clarify it immediately mam.
I have the same doubt.
Mam. for d orbital we should take electron(n-1) so than 1×0.35 + 18×1=18.45 ....❤
Loved your teaching ! 🤩🤩🤩
Nice explanation mam my university exam had it for 4 mark and I could write because of you ☺️☺️
you calculate zeff for Ti in d orbital so n th position (9*0.35)+(10*1)=13.15 then zeff =22-13.5=8.85
How 9 in( 9×0.35)???
I am also having the same doubt
@@Sudhaaaaa_09hi!
Thank you so much mam.. I have cleared all my doubt related to slater rule and calculation of z-effective.
Mam your video is very beneficial..thankyou so much🙏
Mam can u plz explain y 3d2 contributes only 1 electron
same question
We have to reduce 1 from the outermost electron.... e.g- for 4s2 we take 1 electron
For 2p6 we take 6-1=5 i.e 5 electron
@@mohdamir7704 why bro
@@harshitaupadhyay160 that is the part of rule..!!
@@harshitaupadhyay160 If n e are there only last 1 e is screened by remain (n-1)e,1e excluded.
0.30 from the other electron in 1S orbital if the electron for which S is calculated.
Ma'am you forgot this point to include in this video
Hi mam!!! I'm watching every vedios nd jst ur amazing with ur knowledge.. Thank you so much for ur efforts... 😊..., Mam i have a request, I can't understand this slaters rule tat hw ur neglecting some terms nd there is some confusion. Can u pls clarify with some more info mam?? 🙃
Nice explanation... I am hardly struggle in this type of questions.. thank you MAM😊😊😊😊😊😊😊🎈
Mam but Ti me aap ne Sare ko 18 kyu kr diya 1(0.35) + 8(0.85) + 8 (1) + 2 (1) aata hai na mam because vo (n-1), (n-2) aese aata hai na mam (toh fir ye answer galat hoga na mam)
You're awesome ma'am and your writing is awesome... But why do you use calculator for such small calculations.. 😅🤔
Maths typing 😂 in chemistry 😂
The description is quite contrasting with the table.
For s and p , (n-1) -> 0.85 and (n-2) -> 1.00 but it's written 1.00 for both n-1 and n-2
Look nicely bro
I dont know how to thank u mam ... love from tamil nadu kanyakumari ❤
How simply you explained it!!!!! Terrific and very loving voice with respect to students you have mam 😃 Thanks Thank you so much!!!!!😇🤓😻👼
Edu-rich personality ..God bless you..study well..
Komali M mam I am the aspirant for coming NEET. I have complications in my mind about solving the MCQ's of stereo & optical isomerism please if you have any trick to solve them , please provide such supporting videos soon thanks mam 😃 Thanks Your wishes are like God gift for me ...........🙃😃😇👼
I forgot to mention that isomerism in co-ordination compounds , not the instead others.....👼
Thank you mam I am.doingmedical doctor your video help me so much I will recommend this to all
Thank you so much mam. It helps a lot. Your video make me understand the EAN. I am so happy.😊
Awesome trick mam...
Ur all videos has unique style with awesome trick...
Thankyousomuch...
Alwz Keep us helping from ur fantastic way of teaching
Thank you very much ,mam
Now my doubt about 4s orbital electrons is cleared🤗😇😊
Madam Slater rule I have doubt about lithium 1s2 you had taken n-1 but boron you had taken n for 1s2 why ? Please clarify
Yes l have also problem that think ........
Yes mujhe bhi ye dought h
@@Anxietyless easy h
@@ankushsinghsaini181😅
I think it depends on question in lithium we find for 2s1 e- so we take (n-1) and in boron we find for 2p1 so we leave it and take whole 2s1 and put values
Thank you mam you cleared my doubts every time I watch ur videos if I get doubt
Thank you mam your video is so useful for me
Keep going we will support you
You are an amazing teacher....
Very helpful for b.tech cse also✌️✌️
Ha
But how could we just add up all the remaining electrons and just multiply them with 1? I didn't get it
best way to teaching ..nice tricks and at last tanku so much mam for this video
Honestly I had some confusion....🥺
we r not different sis😪⚡
Same...... which electron to take and which not to.... caused confusion
Thanku maam for clearing my doubts regarding this rule
Mam,how to find effective nuclear charge by a 3d electron in bromine atom ?
Ur explanation is so beautiful....Thank u .....komali gaaru
I was so nervous but you made it easy.
Thank you 🤗
ur most welcome mam
Ma'am really thanks a lot..
Nice teaching
Mam your handwriting is so good even if you write with your left hand
Thnku so much ma'am...it's really helpful 👍
In Ti n=3 for d u took 0.35 but y for 3p and 3s u took 1
Same doubt
Because it is a d-block element...only the outermost shell contains 0.35 value and all the innermost shell contains..the value 1..
Hi
@@madugulajoshi5050 hi
@@selvamselvam1190 hi
It's very useful. Thanks Alot Mam 🙏🏼☺️
Maam, y does the last orbital not contribute?I didn't understand can u plz explain
I have a doubt regarding Titanium's case. Basically since we're considering the d electron, so n =3. But when we reach the 3s3p part, how did you take the contribution as 1, and not 0.35 or 0.85?
Same doubt 😐
formula of d will involve
Titanium is Expectation
I have no any confusion mam all are clear... Thanks
Mam literally when my sir explained this topic I was thinking where did that value has gone why im getting the different answer im just blank when explained this topic im all clear
THANK YOU SO MUCH MA'AM 😊
Loved it mam lots of ❤️ you are great ❤️
Thai video Helps me a lot
Thank you very much mam. Our system confused me but you made it clear for me
So helpful ...ur voice nd writing both r so clear nd beautiful
Your handwriting and explanation is so good mam
Very very bst explanation
But 2s1 contributes 0.35 why u said it has no contribution
The teaching is crystal clear
Even a no brainy guy can understand this in a jiffy
Thanx mam
why did you say you did woring in the decription
according to J.D.Lee book for chemistry jee which i have what you did in the video was absolutely correct
Thankyou mam it helps mi a lot💯😊😊😊😊😊😊😊😊🥰😍🤩😊😘😚😙
what is the trick here
you did the original method
Mam in case of Ti you have multiplied
3s² and 3p⁶ with 1 but they have same n (i e 3) as of 3d²....plss explain
Because the values for s,p orbitals are different and d orbitals are different
Thanku mam best explaination simpe h and easy 😊😊
Thank you mam so nicely explained
Excuse me mam, I have a question? In the Titanium one, is the 3d orbital together with 3s and 3p because in my book it says they are not together so if it was like that then the electron of 3d that remains is n, then 3s3p is n-1, which is a 0.85 and then the others are 1. I'm not sure, I have seen the correction below but it still confuses me because my book divides d and f orbitals from the p and s orbitals even if they have the same general quantic number (in the Ti case is 3) Could you please help? Thank you!
Check description
You are correct
d seperate and rest others have 1
First video Jo complete dekhi Maine...awesome and thanks mam...but one question please 😕
Thanks bro
Got it
Sooooooooooooooooooo thank you mam .With this trick I got excellent marks
Mam really awesome 💯 im really confused about it but now im clear. Tysm
Thank u a lot mam
Thank you so much mam ....I had a great confusion on this topic now I got clarity on it
Fabolous explanation thanks for the concept
11 th or 12
Thank you mam for clearing my doubts ❤️❤️
Thanks a bunch mam ❣️🙏🙏🙏🙏
For your effort 🙏
mam i am from bihar your explanation is good ,,,,hope it will help in my JEE exam
Mam, thank's it's a very easy one, but I have not understand in class room. But by watching your video I am able to do this type of questions......
Ok...i see , so my teacher taught me this in class😅
Thank you so much mam😊
Your teaching is very nice
mam check it ....the ans 3.65is correct ...not 8.85 mam......we not consider shell.. we want to consider the grp(s ele and P ele,) only like that (1s2)=n-3,(2s2 2p6)=n-2,(3s2 3p6)n=1,(3d2)n=1
Got answer 3.65 only.
nice explanation Mam ,Thanks a lot.
Awesome video. Very nice explanation with examples. Must watch to clear any doubt in your mind.
? for s,p (n-1)the value is 0.85 not 1.00, and for n-2, the value is 1.00, is it not? Not 1.00 for both n-1 and n-2? :)
I too have doubt in that #plsclarifydoubt
Thank you mam...it helps for me to study neet....I shared this videos with my friends
Mam your explanation is good.,from which state d you belong?I am from Himachal Pradesh.
The explanation was so good. The electron table on top was very helpful.
And in your video, for Ti, when you find no. of electroms in nth shell, Why should you do minus one. Please explain it madam. I can't find the reason.
Ya I also have have doubt
You minus it because.. for one electron in d we are calculating, it has two electrons, one we take and remove coz for that electron we are calculating the nuclear-charge....the other d electron contributes to its nuclear charge...in small the electron u r calculating nu. Charge can't contribute to itself...
Minus one coz u r actually calculating nuclear charge on that electron.....
Electron itsels can not screen itself
Because it is the test electron which is affected by the screening ...an electron never shields itself
May God continue to bless you with lots of peace, love joy and happiness in your life!!♥️ My wish for you is for God to uplift you more and bless you with everything that you desire in your life the most. May God bless🥰...work hard... Stay lively as alwz.. ♥️...follow urr heart... Make everyone proud.... Loads of love nd everlasting joy nd happiness... 🥰
Mam
w
Why u taken 1 electron in last example for d ?
i had a dought at 8:34 i.e why mam took 3d orbital as only 1 electron
Same doubt..
@Abcdef Ijkl tq
Thanks you mam very much please give like this short video and tips and tricks 😃😄 plzz
Thanks a lot mam for this easy explanation ❤😊
Wonderfull great explanation mam
Komali mam your video is very helpful
Mam your teaching is good ❤but to be honest i didn't understand some concept
Wow ma'am great explanation 👍
i had a dought at 8:34 i.e why mam took 3d orbital as only 1 electron
Bcoz always we have to take 1 electron less than the electrons present in the orbital....Hope u understood
@@anjanirawat107 BUT MAM took all electrons in previous questions i.e 2*0.85+2*0.35 plz respond...
@@gyana_marg for s or p orbitals, pairing does,so it's impossible to break,that y ,I think
Thanku so much for explaining chemistry in a simple way☺️
Hmm
Mam the way you teach is awesome 😊😊
Helpful lec mam
Mam Thank you for the explanation!
Mam why we are taking 3s 3p 3d together in case of scandium