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Exercise: A ramp ADC has a clock running at a frequency of 1MHz. The input voltage ranges from 0 to 40.95V for a 12-bit output. Determine: (i) The resolution of the ADC. (ii) The digital equivalent of 7.828V. (iii) The conversion time for VA = 7.828V . (iv) The maximum conversion time for this converter.
Total steps = 2^12 = 4096 Resolution = 40.95 ÷ (4096-1) = 0.01Volt Digital equivalent of 7.828V = 7.828÷0.01 = 782.8 ~ 783 Conversation time = Approximation for 783 we need 10 bits approximation. And see the video till last so you can better understand everything.
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@@EngineeringFunda You're just precise and that is appreciated 🙏. WISH YOU MORE STUNNING CONCEPT IN ENGINEERING ARENA.HERE, I ANTICIPATE.Provide us solution in my previous comment please Sir
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sir aap aarush ko milne aa jao usne aag laga di exam mei aap ki vajah se. uski mummy boht khush hai. aarush hume party de raha hai, aap bhi invited hai
Your Appreciations, care and share matters a lot to me. #EnginneringLove. All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Question: Let the analogue value of an input signal is 5, for reference value 1 for ADC. Considering that the ADC is 4 bits, write down at least 6 iterations to show the ADC process using successive approximation method (showing update in the binary digits of 4 bit). Please solve
The successive approximation method is an algorithm used by analog-to-digital converters (ADCs) to convert analog signals to digital signals. The process involves comparing the input voltage to a reference voltage, and iteratively adjusting the digital output until it matches the input voltage as closely as possible. For the given input signal of 5 and reference value of 1, the ADC process using the successive approximation method for a 4-bit ADC can be shown as follows: Initial guess: 1000 (8 in decimal) Compare input voltage to the voltage represented by 1000 (8/16 * reference voltage) Input voltage > 8/16, so the first bit is updated to 1 Guess after first bit update: 1100 (12 in decimal) Compare input voltage to the voltage represented by 1100 (12/16 * reference voltage) Input voltage > 12/16, so the second bit is updated to 1 Guess after second bit update: 1110 (14 in decimal) Compare input voltage to the voltage represented by 1110 (14/16 * reference voltage) Input voltage > 14/16, so the third bit is updated to 1 Guess after third bit update: 1111 (15 in decimal) Compare input voltage to the voltage represented by 1111 (15/16 * reference voltage) Input voltage < 15/16, so the fourth bit remains 1 Guess after fourth bit update: 1110 (14 in decimal) Compare input voltage to the voltage represented by 1110 (14/16 * reference voltage) Input voltage < 14/16, so the fourth bit is updated to 0 Guess after fifth bit update: 1100 (12 in decimal) Compare input voltage to the voltage represented by 1100 (12/16 * reference voltage) Input voltage > 12/16, so the fifth bit is updated to 1 After six iterations, the final output of the ADC is 11001 (or 25 in decimal), which is the digital representation of the analog input signal of 5 with a reference value of 1 for a 4-bit ADC using successive approximation method.
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It was clear and meaningful explanation sir. Thankyou very much.
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you killed it sir, Awesome!
Love and happiness of students is my ultimate goal, God bless you 🙏, keep learning and keep progressing.
❤ best teacher for ECE branch
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Awesome video. thanks from BD.. Much Respect and gratitude Sir
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Exercise:
A ramp ADC has a clock running at a frequency of 1MHz. The input voltage ranges from 0
to 40.95V for a 12-bit output. Determine:
(i) The resolution of the ADC.
(ii) The digital equivalent of 7.828V.
(iii) The conversion time for VA = 7.828V .
(iv) The maximum conversion time for this converter.
Total steps = 2^12 = 4096
Resolution = 40.95 ÷ (4096-1) = 0.01Volt
Digital equivalent of 7.828V = 7.828÷0.01 = 782.8 ~ 783
Conversation time = Approximation for 783 we need 10 bits approximation. And see the video till last so you can better understand everything.
Thank very much.Prof.Youre swift reply has really motivated me to anticipate relevant content of electronics from you. Be blessed 🙌
@@EngineeringFunda Sir you said Țmax=(2^n -1)Tclk.Is it necessary I say in this type of question for part(iv)?
Thank you so much for your help sir. Your videos are really awesome and gives a clear understanding.
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@@EngineeringFunda You're just precise and that is appreciated 🙏. WISH YOU MORE STUNNING CONCEPT IN ENGINEERING ARENA.HERE, I ANTICIPATE.Provide us solution in my previous comment please Sir
Rumba kumbaaa... very good explanation prof.
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Sir please at the end of each subject make videos on objective questions for practice so that we can prepare for competitive exam
sir aap aarush ko milne aa jao usne aag laga di exam mei aap ki vajah se. uski mummy boht khush hai. aarush hume party de raha hai, aap bhi invited hai
Yes sir, aag laga di. Sir, poore parivar ke sath ana aap. 😊
You are welcome
I think the answer should be [ 1 0 0 1 ] at 8.30
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awesome sir ji
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Best lecture about successive approximation adc,, thanks sir
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Precise and valuable
Your positive comments motivates me, Thanks and welcome 🙏
Question: Let the analogue value of an input signal is 5, for reference value 1 for ADC. Considering that the ADC is 4 bits, write down at least 6 iterations to show the ADC process using successive approximation method (showing update in the binary digits of 4 bit).
Please solve
The successive approximation method is an algorithm used by analog-to-digital converters (ADCs) to convert analog signals to digital signals. The process involves comparing the input voltage to a reference voltage, and iteratively adjusting the digital output until it matches the input voltage as closely as possible.
For the given input signal of 5 and reference value of 1, the ADC process using the successive approximation method for a 4-bit ADC can be shown as follows:
Initial guess: 1000 (8 in decimal)
Compare input voltage to the voltage represented by 1000 (8/16 * reference voltage)
Input voltage > 8/16, so the first bit is updated to 1
Guess after first bit update: 1100 (12 in decimal)
Compare input voltage to the voltage represented by 1100 (12/16 * reference voltage)
Input voltage > 12/16, so the second bit is updated to 1
Guess after second bit update: 1110 (14 in decimal)
Compare input voltage to the voltage represented by 1110 (14/16 * reference voltage)
Input voltage > 14/16, so the third bit is updated to 1
Guess after third bit update: 1111 (15 in decimal)
Compare input voltage to the voltage represented by 1111 (15/16 * reference voltage)
Input voltage < 15/16, so the fourth bit remains 1
Guess after fourth bit update: 1110 (14 in decimal)
Compare input voltage to the voltage represented by 1110 (14/16 * reference voltage)
Input voltage < 14/16, so the fourth bit is updated to 0
Guess after fifth bit update: 1100 (12 in decimal)
Compare input voltage to the voltage represented by 1100 (12/16 * reference voltage)
Input voltage > 12/16, so the fifth bit is updated to 1
After six iterations, the final output of the ADC is 11001 (or 25 in decimal), which is the digital representation of the analog input signal of 5 with a reference value of 1 for a 4-bit ADC using successive approximation method.
Perfectly explained 🧘♂️
Love and happiness of students is my ultimate goal, God bless you 🙏, keep learning and keep progressing.
Sir, please make videos on filters, specially fractional filters and their simulation through LTSPICE.
Sir it was nice. Can you explain me what will happen when the input analog voltage is 10V exactly.
What exactly is the formula of resolution
v/2^n or V/2^n-1 for ADC ...I am confused 😕
Vin
👏👏
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where can we get the notes for videos 204,205,206,207 and 208 of digital electronics
Sir, at last u have taken example in that why you considered lesser one (1010)10V sir.but why you considered greater one(1100)12V here...?
See the video again
Keep going sir your teching is very harmfull in our education keep going super explanation 👌👌
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Definitely I will suggest my friends
Display problem sir...
Too many advertisement sir!
Correct your dialect please.
boring
Bakwaas