trick to remember min no. of nand gates reqd for different gates; N1 A2 B2 O3 N4 X4 X5 remember the letters NABONXX. assign nos from 1 to 5 .. repeat even no.s twice. N=NOT A=AND B=BUFFER O=OR N=NAND X=XOR X=XNOR
Can't we give same input to two nand and then apply nand of the outputs. It will finally give expression like (A'.B')' and It can be written as (A')' + (B') '
at 4:30 the expression (AB + A'B')' would always give zero according to complement law ( if we consider AB as q then A'B' is q' and we know that (q+q' =1)) isn't this going wrong?? please help
sorry sir, i don't know why you drew the necessary gates before the expression. i myself from the expression A'B+AB' got that it's equal ((A'B)'.(AB')')' and for that i needed 5 nand gates...should i memorize the circuit and then find the expression from that????
Sir please do the videos of digital electronics practicals which would be more helpful.. cos your explanation is very good and useful
its been 6 yrs, are you doing job
Wow, this was very helpful
Thanks Neso ♥
Your explanation is too good and helpful for all computer science students....Thank you
Tussi grt ho sirji!!!
very nice explaination.....helped a lot...i am gonna subscribe
trick to remember min no. of nand gates reqd for different gates;
N1
A2
B2
O3
N4
X4
X5
remember the letters NABONXX. assign nos from 1 to 5 .. repeat even no.s twice.
N=NOT
A=AND
B=BUFFER
O=OR
N=NAND
X=XOR
X=XNOR
After 6 years this is using for me tq so much bro I am from banglore tq
thank you very much
very nicely explained..
Thanks a lot
Simply the best
Can't we give same input to two nand and then apply nand of the outputs. It will finally give expression like (A'.B')' and It can be written as (A')' + (B') '
what the symbol for the XNOR expression shown at 4:21???
Nipple
Can i get any suggestions for
Online Boolean Expression calculator
Hello sir how could u draw the circuit before simplifying the expression
lovely
Mn to kr rha h college ki fees thi de dun pr abba nhi manege😂
who else thought of applying to intel or AMD after watching all the digital electronics play list :)
hahahahaha i have that feeling bro
may Allah see us through this journey
@@hamzah4792 bhai log abhi kya kar rahe aap sab
at 4:30 the expression (AB + A'B')' would always give zero according to complement law ( if we consider AB as q then A'B' is q' and we know that (q+q' =1)) isn't this going wrong??
please help
Your assumption is wrong. If AB = q, then A'B' ≠ q'. But, q' = A'+B'.
Yes, if q=AB then q'=(AB)'=(A'+B')
I didn't get it😢
sorry sir, i don't know why you drew the necessary gates before the expression. i myself from the expression A'B+AB' got that it's equal ((A'B)'.(AB')')' and for that i needed 5 nand gates...should i memorize the circuit and then find the expression from that????
Watch the previous lecture in which he implemented EXOR gate using NAND gates
link to previous video plz
Why is it called 'Realizing'?🤔
I know distributive law
But
I can't understand this exprseion
[(A'+A.B)(B'+A.B)]'
Change to (A'B'+A.B)'
Could anyone help to solve this?
distributive law(A'+AB=A+B)
[(A'+B)(B'+A)]'
A'B' +A'A +BB' + BA
(A'B' + AB)'
@@vamshishette4148 tnhks
can we do it in different way?.at first draw sum and carry with AND OR then just replace this gate with NAND gate..check the ansr is same..reply me
I think usse nhi ho payega
@@sanjaypareek9486 it will be...but there will huge amount of nand gate...that will very uncomputable
@@sanjaypareek9486 kyun nhi hoga? You're replacing gates with their nand equivalent
jhakasss explained
Sir, half adder can be implemented using XOR gate and AND gates, so why is there a need for NAND gate, if we already have XOR and AND gates?
JUST TO DECREASE THE NUMBER OF GATES FOR IMPLEMENTING HALF ADDER WE USE NAND INSTEAD OF XOR AND "AND" .
"100Thanks"
Sir ji
This is wrong process.
This is diagram of XOR gate by NAND gate only.
means you did not finish watching the video. after 4:45 it is about the Carry
Sir help me
ok
POO IN LOO