Clipper Circuit Explained (with Solved Examples)

In this video, the diode clipper circuit has been explained. And few examples on the clipper circuit has been discussed.
By watching this video, you will learn the following topics.
0:20 What is Clipper Circuit? Applications of Clipper Circuit
1:14 Types of Clipper Circuit
2:00 Parallel Clipper Circuit
4:06 Parallel Clipper Circuit with Biasing Voltage
10:23 Series Clipper Circuit
11:21 Series Clipper Circuit with Biasing Voltage
13:16 Example 1
15:19 Example 2
What is Clipper Circuit?
The Clipper Circuit prevents the output waveform from exceeding the certain level and at the same time, it does not distort the reaming part of the waveform.
Application of Clipper Circuit
The Clipper Circuits are used in the wave-shaping circuit and the voltage protection circuit.
Types of Clipper Circuit
Depending on which portion of the waveform (Positive or Negative) is clipped, the clipper circuit can be classified as
1) Positive Clipper Circuit
2) Negative Clipper Circuit
Further depending on the placement of the diode the clipper circuit can be classified as
1) Series Clipper Circuit
2) Parallel Clipper Circuit
In this video, both series and parallel clipper circuits (with and without biasing voltage) have been discussed and few examples based on the clipper circuit has been solved.
The link for the other useful videos:
1) Voltage Multiplier Circuits
• Voltage Multiplier Cir...
2) Zener Diode
• What is Zener Diode ? ...
3) Half Wave Rectifier
• Half wave Rectifier Ex...
4) Full Wave Rectifier
• Full wave Rectifier Ex...
This video will be helpful to all the students of science and engineering in understanding the clipper circuit.
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Music Credit:
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#ClipperCircuit
#DiodeClipperCircuit
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[@ALLABOUTELECTRONICS]

The Timestamps for the Different Topics Covered in the Video.
0:20 What is Clipper Circuit? Applications of Clipper Circuit
1:14 Types of Clipper Circuit
2:00 Parallel Clipper Circuit
4:06 Parallel Clipper Circuit with Biasing Voltage
10:23 Series Clipper Circuit
11:21 Series Clipper Circuit with Biasing Voltage
13:16 Example 1
15:19 Example 2

[@ngkean9743]

Btw how u know where to put.... The horizontal line V of bias

[@aaryan3461]

studying this one night before the exam lol

[@younothing236]

omg same

[@abdullahalqusis6899]

Same 🤦🏻‍♂️

[@DasCODE]

😑I am here to complete my assignment

[@karunarabha8714]

I am here to complete my mini project.. Lol😆

[@ranakashif2700]

And i am here to prepare shortly only for online class 😁

[@virajgoyanka5150]

Its 8:53AM and My test is at 9:30 AM and I am done with video!! This topic has High weightage..I really studied max topics from ur channel after getting result I will update this comment.!! AMAZING CONTENT!

[@atom8509]

When will u upadate this comment ?!

[@nitishguptarbl]

@@atom8509 🤣🤣🤣🤣

[@aktiwari3379]

@@atom8509 😂😂😂

[@saitamapreetsingh3057]

Bhai kitne number aye ?

[@43nileshmahajan18]

@@saitamapreetsingh3057 i don't think he will reply now🙄😂

[@420ZEO]

perfect video better then my teacher..
thanks alot

[@ryanpwm]

Well this guy certainly knows about clipping. You can hear it in the audio.

[@kunalverma3009]

Lmao 😂

[@visheshverma8065]

i have exam tom and i am laughing everytime he says "it will turn on"

[@joetan7023]

Informative and very straightforward. Keep up the good work!

[@reajis4998]

++

[@sidharthguptax]

I watched many videos of yours, they are awesome. I'll recommend these forever.

[@Kiran..153]

Who all are the night before internals 😂😂😂😅

[@kshitizkaushik1862]

you know you are very underated
today i found your channel and yes subscribed it too.
helped me a lot

[@abdulbaseerabbasi3443]

I may have learned something
But I have learned "during this time" a lot more

[@imugandhar]

Seeing this video on November 10 th the day before my semester examination

[@ardra1219]

Brilliant way of teaching...hats off

[@OneXHacker001]

Mein bas itna kahunga
Charan kahaan hai aapkeeeee ........

[@srujaniam9762]

thanks a lot sir definitely solved a lot of doubts and cleared a lot of misconceptions . keep up the work.

[@milzex2082]

I have been looking for this for so long thanks

[@arpan6246]

I m here after learning that this is in AIIMS mbbs entrance syllabus

[@aaliya9652]

Now it won't , cuz it's combined with neet

[@pranathia4266]

Studying this one night before an interview 😂

[@nerdyboy2443]

Sir, if it is possible for you then please playlist for all the topics. It is hard to search all topics separately. But if you arrange them in a playlist then it would get easy for us access your content.

[@ALLABOUTELECTRONICS]

It is already added in diode and diode circuit playlist. You can check it on the playlist page.

[@siddharthgarg1495]

Very good , calm and full of concepts vedio....excellent work

[@rachitkatiyer2343]

Me who studying it before half hour of exam....... Engineer wali feeling aa rhi h 🤣😂🤣🤣🤣

[@avynkarlespino941]

Thanks a lot... Your the best.

[@brijesh6323]

You are doing well kuch teachers hain even they are highly graduated after that they can't explain simply as like you thanx a lot 🌷

[@THEQueeferSutherland]

I'm getting used to THE.... cadenceoftheseprentations.

[@dudeontheinternet123]

lmfaoooooooo

[@wansegamat3064]

this video very helping for understanding clippers circuit.. many thanks

[@siamhasan288]

love how the audio in this video is also clipping

[@ivandagiant]

lmao fr

[@amajadali187]

today i m just watching this video , tommarow will my end sem exam ......

[@amitghosh1213]

one of the best

[@mohitrawat7762]

Thanks sir it help so much

[@dr.sudharsanaraopotturu1380]

Your video contents are good sir, but beginners will have many questions and doubts while watching your videos. Instead of explaining simply what is given in the textbook like a robot, explain more clearly by adding why this is clipping at this voltage etc.
Explain in detail sir.

[@akshatkotpalliwar3202]

11 hours student like here
Next day you will be passed best of luck

[@baikannikitha1897]

Thanks a lot sir, u r explanation with examples help me a lot

[@machiElectronics]

Thanks sir nice and simple

[@sunandachowdhury1455]

Can someone please explain the last example? I did not get it :((

[@HarshaAbey]

thank you

[@santoshpuhan6896]

Studying one hour before exam🫠

[@AjitKumar-ug5he]

Watching this at night before exam and I got to know that much thing which I couldn't during whole semester..

[@rajneeshpatwa9365]

thanks bro

[@mhusain6185]

very nice

[@learn8614]

Thanks a lot

[@PradeepKumar-bc1ez]

Good explanation

[@somanshukadam1864]

Studying an hour before exam.

[@truealpha8597]

Studying this on the exam day morning 😂

[@recazamgarh3110]

Nice explanation

[@shan_singh]

15:50
Why will it get forward biased?????
It should be reverse biased and should act like an open circuit !!
Please someone explain!!

[@ALLABOUTELECTRONICS]

The input is triangular wave and it is gradually increasing to 12V. But during that rise in the voltage, when the input is less than 5V, the voltage at the cathode of the diode will be less than 5V. While at the anode voltage is 5V. So, for that duration when input is less than 5V, the diode will get forward biased (considering ideal diode). And for that time it will conduct. That means when Vin < 5V, Vout = 5V.
I hope it will clear your doubt.

[@billyandmandy286]

is it me or his vioce sounds different the whole time

[@swarnadeepbiswas9303]

Nice presentation

[@learn8614]

But consfused regarding zener voltage problem

[@abhishekabhiz5300]

Studying in day of exam😌🤣

[@user-zp6rn6ul2q]

Bro ❤❤ thanks

[@aathreynair6398]

Studying on the day of exam 😅😅😂

[@cheerladinnemouli2864]

Good lecture sir keep on upload the videos

[@akshayamerugu9152]

Watching Before going to exam 😅

[@alpha-yb7en]

for the first example i dont understand why the zeiner diode turn to an short circuit ( instead of open circuit ) when Vin < 0v ???

[@AmarSingh-rq7rj]

Great explanations

[@acforfun822]

Any vtu students here

[@hemantbagani1248]

Completely satisfactory

[@LearnandEarn-dl4ok]

At 14:08, Should the sign of zener diode not be be opposite? I think you have made a mistake declaring the sign of the zener diode. Please check it and tell me if your example 1 is correct or not

[@ALLABOUTELECTRONICS]

When the Zener diode operates in the breakdown region, then the voltage across it is equal to the Zener voltage. The polarity is correct. For more info, please check this video on Zener Diode: ua-cam.com/video/MZPeRlst8rQ/v-deo.htmlsi=f3Nb-aHyhqGYlhw_

[@ramanand6836]

thankyou sir for such a nice explanation

[@Rahulmohan-mv6nq]

nice simple

[@sandeepkumawat4982]

why is the condition Vin

[@acapjumpen]

Hi there, thanks for the informative video! Can I check why the Vin need not be larger than (0.7 + 0.5)V? To account for ideal diode voltage + bias voltage. Why is it only accounting for bias voltage (0.5) ?

[@indianlad23]

If you've found the answer, pls do share with me

[@sreeharibalachandran]

Thank You :)

[@shubhammanna]

Does all the clipper clamper circuit have zener diode? Coz i needs input voltage more than diode activation voltage

[@ALLABOUTELECTRONICS]

You can also use additional voltage source (with diode) to clip or clamp the waveform at the desired level.

[@aaliya9652]

At 7:53 when V in

[@ALLABOUTELECTRONICS]

When Vin is between V1 and -V2 both diodes are reversed biased.
If you see, the diode D1 will conduct, when the voltage at the anode is greater than V1.
Similarly, diode D2 will conduct when the voltage at the cathode is less than -V2.
That means when the input voltage is in between V1 and -V2, both diodes will be reversed biased.
I hope it will clear your doubt.

[@user-cw6ri8pp3y]

If diode is silicon diode..out voltage how

[@ayushmishra1973]

3:40 sir no effects on positive half cycle will be seen for non ideal diode?

[@ALLABOUTELECTRONICS]

No, there won't be any effect during the positive half cycle. Because if you see, during the positive half cycle, the diode remains in the reverse bias condition.
I hope it will clear your doubt.

[@ayushmishra1973]

@@ALLABOUTELECTRONICS Thank a lot sir

[@mahamatdjibrine95]

many thanks

[@ShriPhotographyOfficial]

how you edit your videos?

[@engineeringisestream5519]

I wish native english speakers made more videos on this cuz mi lass idu a word hes saying

[@tezuphysics8960]

It is great

[@naiemataliep9142]

hi, for example 2, i got the reverse version of your graph ie. my pulse was on the negative side, is this fine? I assumed this was because the direction I chose to be my positive and negative cycles were opposite to yours. Does this matter?

[@035belekaiserahmadkhan2]

bro I am also facing the same problem...so do help me out if u got the reason to it

[@Rahulkumar-yg5wr]

You can tell me , why In the parallel clipper ckt, when +ve half cycle is applying in the ckt the ckt work as a short ckt ? What is the working of resister her ?

[@ALLABOUTELECTRONICS]

The R is the current limiting resistor. And here during the analysis, it has been assumed that the diode is ideal. That means when it conducts it acts as a short circuit. But actually in the output when the diode is conducting, the voltage would be around 0.7V.
I hope it will clear your doubt.

[@aaryan__bondekar9778]

at 4:30 wont R affect the voltage at all? how can we directly compare V and Vin

[@ALLABOUTELECTRONICS]

It restricts the flow of current through diode. When the diode is conducting, then remaining voltage will drop across this resistor. (e.g Vin - V will drop across the resistor, when diode is conducting.) I hope, it will clear your doubt.

[@eee_bangla]

Please make a video on communication for radio frequency...

[@snigdhadhar32]

Loved it

[@nivetha.s9892]

Why clippers are used in tv receivers

[@huyhq_official1601]

Thanks soooo muchhh

[@golu4625]

Positive side of graph is why first taken in side of forward side why it is not taken in reverse side

[@aryanmishra399]

11:33
It shouldn't be (Vin)-V>0.7?
Please explain Sir!!

[@ALLABOUTELECTRONICS]

Here the diode is assumed as an ideal diode. If it's not, then yes, Vin - V should be greater than 0.7V.

[@abhirajmishra7436]

Sir pls explain in more easy terms coz u are unable to clear some doubts

[@ALLABOUTELECTRONICS]

If you have any doubt please let me know here. I will try to resolve it.

[@Eren-vz5vb]

2:47 why Vo is not 0 here?? There is resistance but no voltage drop

[@ALLABOUTELECTRONICS]

Since diode acts as open circuit, so there is no current through the diode. ( Considering ideal diode). And since, diode is open, so circuit will not get completed and hence no current through the circuit. So even though there is a resistor in series with voltage source, but there will not be any voltage drop across it. And hence, Vo = Vin during that negative half cycle. I hope it will clear your doubt.

[@balakaladabk8450]

12:43 series clipper with biasing , the signal not get clipped , it get smaller form .why?

[@ALLABOUTELECTRONICS]

The series clipper circuit clips the certain portion of the waveform (in time domain), much like a rectifier. Similar to the rectifier circuit, here the diode will conduct when the voltage across the anode of the diode is more than cathode. And during the ON time of the diode, the output voltage is Vin - V (assuming ideal diode for a moment). That is why you are seeing the reduced voltage during the conduction of the diode. I hope, it will clear your doubt.

[@nitishguptarbl]

Excellent man 🙏🙏

[@v.mp3592]

kyuki theoretically ideal diode dekh sakte ho lekin practically ideal diode kon dega tere haath mein?

[@enthusiastic_7]

In example 2 when the Vin less than 5V the Vout is 5V ..I have some doubt in that part .Is there is no effect for Vin in Vout when the Vin less than 5V .I think Vout =5V -Vin when Vin is less than 5V..? Pliz clarify this part..

[@ALLABOUTELECTRONICS]

The input signal plays role in turning on or off the diode. (Here it has been assumed that the diode is ideal diode). Depending on the conduction of the diode, the output will change.
Vout is the output across the one terminal of the diode and reference node. You can simply find that voltage by applying the KVL.
You can also simulate the same circuit and check the result by yourself.

[@abhimanyubishnoi8727]

Eg 2 is contradictory to what u explain earlier.when Vi5V then Vout=Vin-5V. Please explain this.

[@ALLABOUTELECTRONICS]

In example 2, when Vin

[@abhimanyubishnoi8727]

Now I’ll understand. Thank u 😊

[@gyanukumar7081]

Sir kuch v nahi samajh aaya

[@kanchanmeena9150]

Great explanation sir

[@harishramangari8009]

Unbiased series diode negative clipper to remove the negative half of the wave form diode is connected the reverse biased no current passing through the diode
How to form out put singnal

[@Ramu-mv8co]

Guys, in parallel clipper circuit in reverse bias the voltage is not zero..... Whereas in series clipper circuit in reverse bias the voltage is not zero na .....why? Like this can anyone explain me

[@user-ed3em6qw4o]

bro only at short circuit the input follows the output. you re saying that every time at open circuit outrput follows the input

[@ALLABOUTELECTRONICS]

It depends, whether it is a series clipper or a parallel clipper. In a parallel, clipper circuit, the output is measured across the diode. When the diode is short-circuited, then output will also get short-circuited.
And hence the output is 0 in case of a parallel clipper circuit. But in a series clipper circuit , when the diode conducts, there is a short circuit between input and output. And that's why the output follows the input.

[@ephraimyousaf5845]

change your mic, please

[@musfidurrahman8406]

Could not Example 2 😢

[@mayurshah9131]

Excellent 👌👌

[@vanikians4585]

sir last k dono example paralllel k lg rhe the to series k concepts kyu lga h

[@chethank8716]

0.7volt is shown in time axis?

[@sauravkumarnayak]

Sir thoda hindi se bhi explain kr liya kijiye......

[@owen7185]

excellent lecture

[@Suryatechniacademy98]

Could you please explain breafly

[@jackyunlucky8432]

Thank you , appreciate it