An electron of K.E. 10 eV is If a cute angles to a uniform magnetic field. Determine the value of the moving in a circular orbit of radius 11 cm, in a plane at right flux density. (mass of an electrón= 9,1x10-31 kg, e-1.6×10-19
Given , K.E = 10eV = 10 x1.6 x 10^-19 = 1.6x10^-18 J radius , r =11cm = 11x10^-2m mass of electron = 9.1x10^-31 e = 1.6x10^-19 C B = ? we know , K.E = 1/2 mv^2 v = root under 2KE over m --> simplify v = 1.875 x 10^6 m/s Since the elctron is in circular motion centripetal force acting on it , F = mv^2 / r Also the force on electron due to magnetic field is F = Bev As electron moves in circular orbit the force on electron due to magnetic field provides necessary centripetal force i.e Bev = mv^2 / r ----> simplify B = 9.69x10^-4 T I hope you will find it useful. From someone giving 12th exam this year. Wish me luck!
4:58 magnetic field 1.25 cha calculation ma 0.25 leko cha
An electron of K.E. 10 eV is If a cute angles to a uniform magnetic field. Determine the value of the moving in a circular orbit of radius 11 cm, in a plane at right flux density. (mass of an electrón= 9,1x10-31 kg, e-1.6×10-19
Given , K.E = 10eV = 10 x1.6 x 10^-19 = 1.6x10^-18 J
radius , r =11cm = 11x10^-2m
mass of electron = 9.1x10^-31
e = 1.6x10^-19 C
B = ?
we know ,
K.E = 1/2 mv^2
v = root under 2KE over m --> simplify
v = 1.875 x 10^6 m/s
Since the elctron is in circular motion centripetal force acting on it ,
F = mv^2 / r
Also the force on electron due to magnetic field is
F = Bev
As electron moves in circular orbit the force on electron due to magnetic field provides necessary centripetal force i.e
Bev = mv^2 / r ----> simplify B = 9.69x10^-4 T
I hope you will find it useful.
From someone giving 12th exam this year. Wish me luck!
Best of luck for tomorrow's exam😂
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Sir physics ko important question haru ko video banaununa please 🥺❤️
yehi taa ho important questionss..its a complete package
Sir can you explain numerical examples of equilibrium level of output and price (class 12) economics
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suru ma 1.25 T thiyena rw sir? Why you put 0.25T
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kasari magnetic field radial banauxam haina r?
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in this video many mistake in video editing and reading the question
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Account ko class 11(new course) ko banaunu na hau over demand xa. Hamro college ma sab jana ley parkhiraxa
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Question no wrong xa haii
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Yo question haru ko solution ni haldinu na
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