032. Bode Plot: Properties, Poles and Zeros, Resonance (2nd Order Peaking)
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- Опубліковано 11 лют 2025
- Introductory Circuits and Systems, Professor Ali Hajimiri
California Institute of Technology (Caltech)
chic.caltech.ed...
Bode Plot: Properties, Poles and Zeros, Resonance (2nd Order Peaking)
© Copyright, Ali Hajimiri
20161122101002EE44
11:45 -
18:40 - Deriving a Bode Plot from an Analytical Function, a Key Ingredient
32:44 - Magnitude and Phase Asymptotes
43:48 - Bode Plot of a Low-Pass
48:35 - Example with Poles and Zero
59:10 - A Complex Conjugate Pole Pair Bode Plot
hello brother, can you give me your email i want to ask you something
Sir you have cleared lot of puzzles in my mind. You explained this topic in a very fine way. May ALLAH bless you 😊
amin
very intuitive lecture thanks prof
Finally ,I understood how to draw Bode plot.
a little bit mistake at 58:15, the second segment of overall phase plot should be -90 degree,
I think the phase plot for the 1 zero and 2 pole example is wrong. The slope should be -90 between w=10 and w=100 due to the addition of the two poles phase.
So if we had only imaginary pole complex conjugate pair (pole on jw axis), we would have infinite Q, that is infinite peaking at that frequency and instant transition in phase of 90°? What does that mean (resonance)? If we had a double pole there peaking would take longer to stifle, and we would have 180° phase transition, what would that mean for resonance?
Hello sir,
My instructor mentioned that at cut off frequency the point is a half power point. Can you describe why is that?
Thank you sir
👌👌
sir, actually at a zero , the transfer function goes to zero, but that is not reflected in bode plot. Why ?
I don't see how taking 1/10th of the bell to get the decibel equates to multiplying the bell by a factor of 10, would you not divide by 10 to get the dB relationship ? :)
If a piece of wood is 3 meters long, and if you wanted to state that length in cm, would you multiply by 100 or divide? Hope this helps.