Dil Galti Kar Baitha Hai - Jubin Nautiyal Song | Slowed And Reverb Lofi Mix
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- Опубліковано 5 вер 2024
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#jubinnautiyal #lofi #lofimix #slowedreverb #lofihiphop
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Always slowed lover hun...💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛💛
Mai bhi ❤
"Tum apna lo ya Thukra do-
- Tumhe hak faisle ka h"
2:33 😍😍❤❤🧡💛💙
Ooh achaaaaaaaaaaa 💩
This tone of his voice takes me flying and my heart pumping slowly
Kaun kaun 2024 me ye sun raha hai❤😊
Mi 🎉
RIP to those who don't have headphones 🎧💀
🤣🤣🤣
AirPods 😎😎😎
Focal utopia by tournair
I have soundbar😂
Or if one works and the other doesnt
HEART TOUCHING SONG
EveryOne says after Fall in Love ❣️
'Dill gelti💔 Kar Beitha Hai '
Who Searched special for this song slowed and reverb
Me 😫🌍
Me 😵
Me 💓
Kisko pahla Pyar Hua Hai😅😅❤
I like slow and reverb version❤
Only Nusrat Fateh Ali khan
♥️obviously
3:36.....!!!Phele phele ho gyi hmse diddar ki glti 💕👀🙈🖖
Kon kon apne gf ka bolana par ya gana sun raha hai ❤
Hayeeee gf
Nice lovle lofi song
2:08 💥💥💥💥💥
Palat ke ishq ki galiyon se jaana hai bada mushkil
Kon Kon 2023 Mein Yah Song Sun Raha Hai 👈
I am always with you brother✌️❤️
Same as ❤
@@ashiqueen4459 Can I get your support?❤️🌿
@@slowvibesonly6220 hm
@@ashiqueen4459 achha 🤣😂
Diameter of hemispherical bowl = 10.5 cm
Radius of hemispherical bowl, r = 10.5/2 cm = 5.25 cm
Formula for volume of the hemispherical bowl = (2/3) πr3
Volume of the hemispherical bowl = (2/3)×(22/7)×5.253 = 303.1875
Volume of the hemispherical bowl is 303.1875 cm3
Capacity of the bowl = (303.1875)/1000 L = 0.303 litres(approx.)
Therefore, the hemispherical bowl can hold 0.303 litres of milk.
6. A hemi spherical tank is made up of an iron sheet 1cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank. (Assume π = 22/7)
Solution:
Inner Radius of the tank, (r ) = 1m
Outer Radius (R ) = 1.01m
Volume of the iron used in the tank = (2/3) π(R3- r3)
Put values,
Volume of the iron used in the hemispherical tank = (2/3)×(22/7)×(1.013- 13) = 0.06348
So, the volume of the iron used in the hemispherical tank is 0.06348 m3.
7. Find the volume of a sphere whose surface area is 154 cm2. (Assume π = 22/7)
Solution:
Let r be the radius of a sphere.
The surface area of the sphere = 4πr2
4πr2 = 154 cm2 (given)
r2 = (154×7)/(4 ×22)
r = 7/2
Radius is 7/2 cm
Now,
Volume of the sphere = (4/3) πr3

8. A dome of a building is in the form of a hemi sphere. From inside, it was white-washed at the cost of Rs. 4989.60. If the cost of white-washing isRs20 per square meter, find the
(i) inside surface area of the dome (ii) volume of the air inside the dome
(Assume π = 22/7)
Solution:
(i) Cost of white-washing the dome from inside = Rs 4989.60
Cost of white-washing 1m2 area = Rs 20
CSA of the inner side of dome = 498.96/2 m2 = 249.48 m2
(ii) Let the inner radius of the hemispherical dome be r.
CSA of inner side of dome = 249.48 m2 (from (i))
Formula to find CSA of a hemisphere = 2πr2
2πr2 = 249.48
2×(22/7)×r2 = 249.48
r2 = (249.48×7)/(2×22)
r2 = 39.69
r = 6.3
So, the radius is 6.3 m
Volume of air inside the dome = Volume of hemispherical dome
Using the formula, the volume of the hemisphere = 2/3 πr3
= (2/3)×(22/7)×6.3×6.3×6.3
= 523.908
= 523.9(approx.)
Answer: The volume of air inside the dome is 523.9 m3.
9. Twenty-seven solid iron spheres, each of radius r and surface area S are melted to form a sphere with surface area S’. Find the
(i) radius r’ of the new sphere,
(ii) ratio of Sand S’.
Solution:
Volume of the solid sphere = (4/3)πr3
Volume of twenty seven solid sphere = 27×(4/3)πr3 = 36 π r3
(i) New solid iron sphere radius = r’
Volume of this new sphere = (4/3)π(r’)3
(4/3)π(r’)3 = 36 π r3
(r’)3 = 27r3
r’= 3r
Radius of the new sphere will be 3r (thrice the radius of the original sphere)
(ii) Surface area of the iron sphere of radius r, S =4πr2
Surface area of the iron sphere of radius r’= 4π (r’)2
Now
S/S’ = (4πr2)/( 4π (r’)2)
S/S’ = r2/(3r’)2 = 1/9
The ratio of S and S’ is 1: 9.
10. A capsule of medicine is in the shape of a sphere of diameter 3.5mm. How much medicine (in mm3) is needed to fill this capsule? (Assume π = 22/7)
Solution:
Diameter of capsule = 3.5 mm
Radius of capsule, say r = diameter/ 2 = (3.5/2) mm = 1.75mm
Volume of spherical capsule = 4/3 πr3
Volume of spherical capsule = (4/3)×(22/7)×(1.75)3 = 22.458
Answer: The volume of the spherical capsule is 22.46 mm3.
chat gpt
@@noobmaster13750right
Most favorite song😊
Jubin sir ❤️
Supar Song ❤
Badi mukhtasar si hai ,
Ye zindagi yaara ,
Zara paas aa jao ,
Sochte na raho
Feelings love song🎉❤
0:56 💥💥
Next level
This song is more beautiful than original
Love this song so much🖤🖤
I love you Always ❤💔🖤
Oooooo
Level Hai ❤️👌
🙏🙏👍👍
😢😢
Perfect
Ooooo sukun ❤❤❤
❤️❤️❤️❤️
💔 same to you 💔
Nice
Very nice song bhai super ♥️♥️♥️👌👌👌🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳👌👌👌👌👌👌🙏🙏🙏🤴🤴💯💯💯♥️🙏🇮🇳👌🙏🙏🤴💯💯
Thinking about someone you love while listening to➡ it this p
haiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii uffffffffffffffffffff
❤❤❤❤
ufff
❤❤😊😊
Amazing
❤❤❤❤❤❤😍😍😍
Legend listen in 2024
❤❤....
Which legend is listening this song in 2023 🤣😂🤣
😢
9:03
💖
Wow
💞💞💞💞💞🖤🖤🖤🖤
❤️❤️
Dil galti kar betha 🙂💔
Sera
Nice song ❤❤❤❤
I am first again here✌️❤️
Slowed song very sweet ♥️♥️
1:00
Congratulations on 100k🎊🎊
🤘🤘🤘🤘
Lovely song
Play 2:16 se 2:55 tak❤❤
👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍
1k view to mene hi kiye h iske
😢😢
Mast
This is the heavenly song
💕
Rain ☔ + This Song 🎵 + Chai ☕ + 2AM + Cigarette 🚬
+____
first 😍🥰
Love you 💗 priyanshi ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
I am here.
😴😴😴😴😴😴😴😴🤗
Upload spotify
Can anyone tell that last piano tune song?
Mast song
Bhai ek request hai Bengali ak song hai pyaar ka bukhar oo song ap bana o na plz request kiya hai plz... 🙏😔
😄
First Like ❤️
🤣🤣
❤❤❤❤🎉🎉😂❤
Oooooo
Plzz no add
I am first again here ❤️🤟🤟🤟🤟
2nd
Slowed mara febrat
This song is copy of nusrat fateh ali khan
Jubin became Adnan Sami lol
🤣🤣🤣🤣
😁
(Ü)
L
Given - h=500m,g10m/s2,v=340m/s ,
by , h=ut+(1/2)gt2 ,
500=0+(1/2)10t2 , (initial velocity , u=0) ,
or t2=1000/10=100 ,
or t=10s ,
it is the time taken by stone to reach the water level , after that a sound is produced due to strike of stone on water , and sound travels upwards .Let t' be the time taken by sound to reach the base of tower ,
then , t′=h/v=500/340=1.47s ,
therefore time taken by splash to hear at the top ,
T=t+t′=10+1.47=11.47s
Was this answer helpful?
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SIMILAR QUESTIONS
The extension in a string, obeying Hooke's law, is x. The speed of sound in the stretched string is v. If the extension in the string is increase to 1.5 x, the speed of sound will be:
Medium
View solution
>
A policeman blows a whistle with a frequency of 500Hz. A car approaches him with a velocity of 15ms−1. The change in frequency as heard by the driver of the car as he passes the policeman is (Given, speed of sound in air is 300ms−1)
Medium
View solution
>
Longitudinal waves are produced in a certain rod of density 2600kg/m3and Young's modulus 6.5×1010 Nm−2. The speed of sound in the given rod is
Easy
View solution
>
Diameter of hemispherical bowl = 10.5 cm
Radius of hemispherical bowl, r = 10.5/2 cm = 5.25 cm
Formula for volume of the hemispherical bowl = (2/3) πr3
Volume of the hemispherical bowl = (2/3)×(22/7)×5.253 = 303.1875
Volume of the hemispherical bowl is 303.1875 cm3
Capacity of the bowl = (303.1875)/1000 L = 0.303 litres(approx.)
Therefore, the hemispherical bowl can hold 0.303 litres of milk.
6. A hemi spherical tank is made up of an iron sheet 1cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank. (Assume π = 22/7)
Solution:
Inner Radius of the tank, (r ) = 1m
Outer Radius (R ) = 1.01m
Volume of the iron used in the tank = (2/3) π(R3- r3)
Put values,
Volume of the iron used in the hemispherical tank = (2/3)×(22/7)×(1.013- 13) = 0.06348
So, the volume of the iron used in the hemispherical tank is 0.06348 m3.
7. Find the volume of a sphere whose surface area is 154 cm2. (Assume π = 22/7)
Solution:
Let r be the radius of a sphere.
The surface area of the sphere = 4πr2
4πr2 = 154 cm2 (given)
r2 = (154×7)/(4 ×22)
r = 7/2
Radius is 7/2 cm
Now,
Volume of the sphere = (4/3) πr3

8. A dome of a building is in the form of a hemi sphere. From inside, it was white-washed at the cost of Rs. 4989.60. If the cost of white-washing isRs20 per square meter, find the
(i) inside surface area of the dome (ii) volume of the air inside the dome
(Assume π = 22/7)
Solution:
(i) Cost of white-washing the dome from inside = Rs 4989.60
Cost of white-washing 1m2 area = Rs 20
CSA of the inner side of dome = 498.96/2 m2 = 249.48 m2
(ii) Let the inner radius of the hemispherical dome be r.
CSA of inner side of dome = 249.48 m2 (from (i))
Formula to find CSA of a hemisphere = 2πr2
2πr2 = 249.48
2×(22/7)×r2 = 249.48
r2 = (249.48×7)/(2×22)
r2 = 39.69
r = 6.3
So, the radius is 6.3 m
Volume of air inside the dome = Volume of hemispherical dome
Using the formula, the volume of the hemisphere = 2/3 πr3
= (2/3)×(22/7)×6.3×6.3×6.3
= 523.908
= 523.9(approx.)
Answer: The volume of air inside the dome is 523.9 m3.
9. Twenty-seven solid iron spheres, each of radius r and surface area S are melted to form a sphere with surface area S’. Find the
(i) radius r’ of the new sphere,
(ii) ratio of Sand S’.
Solution:
Volume of the solid sphere = (4/3)πr3
Volume of twenty seven solid sphere = 27×(4/3)πr3 = 36 π r3
(i) New solid iron sphere radius = r’
Volume of this new sphere = (4/3)π(r’)3
(4/3)π(r’)3 = 36 π r3
(r’)3 = 27r3
r’= 3r
Radius of the new sphere will be 3r (thrice the radius of the original sphere)
(ii) Surface area of the iron sphere of radius r, S =4πr2
Surface area of the iron sphere of radius r’= 4π (r’)2
Now
S/S’ = (4πr2)/( 4π (r’)2)
S/S’ = r2/(3r’)2 = 1/9
The ratio of S and S’ is 1: 9.
10. A capsule of medicine is in the shape of a sphere of diameter 3.5mm. How much medicine (in mm3) is needed to fill this capsule? (Assume π = 22/7)
Solution:
Diameter of capsule = 3.5 mm
Radius of capsule, say r = diameter/ 2 = (3.5/2) mm = 1.75mm
Volume of spherical capsule = 4/3 πr3
Volume of spherical capsule = (4/3)×(22/7)×(1.75)3 = 22.458
Answer: The volume of the spherical capsule is 22.46 mm3.
Maths k lode yha esw bund bjwane ka mtlb🙂
@@chanchaltiwari7176 tera maa chodunga
😢😢😢