LIST COMPREHENSION & LOOPING - PYTHON PROGRAMMING
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- Опубліковано 1 жов 2024
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Instagram : / sundeepsaradhikanthety
Sir, Incorrect Program.
Correct Program is as below
list1=[1,3,5,7,9]
list2=[2,4,6,8]
pair=[(x,y) for x in list1 for y in list2 if x-y==-1]
print(pair)
Thank you so much
pair =[(x,y) for x in list1 for y in list if x-y==-1]
gives the output shown at 11:30
Also
pair=[(x,y) for x in list1 for y in list2 if list1.index(x)==list2.index(y)]
list1 = [1,3,5,7]
list2 = [2,4,6,8]
list = ([(list1[i],list2[i]) for i in range(len(list1)) ])
print(list)
print(type(list1))
Output - [(1, 2), (3, 4), (5, 6), (7, 8)]
It would be easy if we just,
pair = [(x, y) for x, y in zip(list1, list2)]
result=[(list1[i],list2[j]) for i in range(len(list1)) for j in range(len(list2))if i==j]
try this last one is wrong
Hello Sundeep, The list for merging as x,y didn't work as expected. It showed the output as product join instead of (1,2,) (3,4) ( 5,6) (7,8)
pair will give a different result from what you have shown.
Great explanation sir....just after watchg tz video....i did subscribtion
Sir list comprehension and specially list looping is not clear to me , sir please make a complete implementation video.
wow man...made my life..
Nice one Subscribed...Keep'em comin....
Sir @10.37sec video, you may given wrong output
appreciate your affort
Code corrected @10.37
seq1=[1,3,5]
seq2=[2,4,6,8]
finallist=[(x,y) for k,x in enumerate(seq1) for l,y in enumerate(seq2) if k==l ]
print(finallist)
Why k and l ? Can you please explain?
sir please correct the concept of looping of list at 11:28
the ans should be this.
Sir you have explained everything from root it's best
Sir please make videos on data structure using python programming language please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please please.... sir
One doubt
Matrix = [ [1,2,3,4],[5,6, 7,8],[9,10,11,12]
[[Row[i ] for row in matrix] for i in range(len( matrix[0]))]
How it is work please explain anyone
We want more examples about this list comprehension sir....
what is the use of this list ???
It is just like array in c but here it will store the elements of different datatypes
Very nice sir.useful for my studies.
Thank you Sir!!
Sir, video is not playing....
Thanks anna
Wonderful zest
Good
Sr what is defnitiom of list comparison