Thank You mam for helping me for the preparation of my final exam, If I left studying bode plot, then there would be no chances of passing my final exam of Control System 1 subject of 3rd year electrical engineering, because in college I did not understand my teacher's teaching of Bode Plot Unit Thanks a lot again 🙏🙏
@@sheebaps आप अपना ये काम ऐसे ही आगे बढ़ाते रहिए, ताकि जिनको कॉलेज में समझ नहीं आता है उनके लिए ये बहुत फायदेमंद है और ज्यादा likes भी मिलेंगे तुम्हारे videos को
Thank You mam i dont know how to express my feelings for helping me for the preparation of my final exam, If I left studying bode plot, then there would be no chances of passing my final exam of CS. TNX MAM
@@laxmandake6524 Decide on a starting frequency one decade below the least corner frequency, then draw the starting slope line & ensure that this line should pass through the k value (6.02 dB) at w=1. Draw the new slope lines at every corner frequency.
I have a doubt. You drew the the 6.02 db line which is the basis for the other +20 or -20 db/decade. What to do if the question doesn't have a constant factor like 10/5 =2? How do we determine this gain then?
@@RPT-i3rDraw a line with the starting slope. Starting slope will be the slope corresponding to poles or zeros at origin if it is present otherwise it will be slope corresponding to the lowest corner frequency term.
If k is not given, plot the bode plot assuming k=1 and find the value of k from gain margin using the equation, 20 log k= GM dB or shift the plot as per the conditions given, if any.
Phase Margin is the additional phase lag which can be introduced into the system so as to bring the system to the verge of instability at gain crossover frequency. Gain crossover frequency is the frequency at which the magnitude becomes 1 (0 dB) in Bode plot.
@@binishabhattarai8895starting w value you can select based on the lowest corner frequency, You may take one decade below than the lowest corner frequency.
1 & 5 are the corner frequencies. You can find corner frequencies from the factors in the time constant form. For first order factor of the form (1+sT), it is found by wc=1/T.
For first order zero slope is +20db/decade, first order pole it is -20db/decade, second order zero or quadratic factor it's +40 db/decade, second order pole or quadratic factor it's -40db/ decade and so on.
@@StudentofsomethingThanks for pointing out the mistake🙏 Instead of 0.5 I mistakenly took 0.3 point, my sincere apologies. Thankfully it didn't affect the values of GM & PM as it was an approximate curve 🙂
Phase Margin is the additional phase that can be added to the system to bring it to the verge of instability. For CL stability, mag=1 (0dB) & angle= -180 degree. Hence 180 degree is considered.
If the intersection point corresponding to wpc in magnitude plot is below 0 dB line, then GM is positive. If the intersection point corresponding to wgc in phase plot is above -180deg line then PM is positive.
The slope for first order pole is -20dB/decade. Gain in decibels for pole at origin is found by 20 log (1/w) dB. At w=1, gain is 0 dB & at w=10, gain is -20dB hence slope is -20dB/decade.
This video I created to give a clear understanding of the basic concepts required for plotting Bode plot on semilog sheet. Pls let me know which points I have skipped in this video so that I can include it?
GM is the gain at phase crossover frequency (frequency at which phase angle becomes -180 degree). It can be found as the difference between 0dB & the gain at point of intersection at Wpc.
Your Lecture Made me Even More Confused, Pahle to Itna Slowly Bol rHi hai aap 🙏. upar se Confusion aur Originate kar raahi hai , Kahi ladai karna ho to bahut tej aawaz aayegi, waise thoda tej nhi bol payengi aap
your explantion was the best.... i have waste 4 hr going through vidoes by honestly your way of explation is most appreciated
Thank you very much for the appreciation 🙏🙂
Thank You Soo Much Maam.....Your lectures are 1000 times better than my college faculties
Thank you 🙏😊
Best lecture for clearing all doubt on Bode plot❤️
I am not able to solve the bode plot before I visited your video, Now I am very much confident for upcoming SPPU examination for control system
Glad to know that. 🙂🙏
Good luck for your exams!
Thanks mam, having my exam tomorrow ✨🎉
All the best for your exams 👍🙂
@@sheebaps btw we wanted couple more videos about same but, ✨thank you
@@omishtamwar Pls check my other video for quadratic factor too...
This is best lecture of bode plot ever🎉❤
@@TwalibMziray Thank you 🙂🙏
Edinnaaa okaa procedure meeraa exaplain chastunnaaru mam,. Nice 👍
many faculties taught me this topic but your explanation is best
Thank you 🙏🙂
Mam your method of lecture deliver is very good
Thank you 🙏🙂
Really helped in clearing this concept ma'am.The publication which i referred had unnecessary information which madhe the qn lengthy.Thank you😇
Glad to know that 🙂🙏
Thanks a lot maam,. I have exam in 2 hours, ur video helped me to get my confidence 😊
Glad to know that 🙂 All the best for your exam 👍
Very very thanks u so much mam
1 vedio me pura concept clear ❤ again thank you mam
🙂🙏
The best explanation ever
Thank you mam🤗❤️
@@Deepak-sq1rs Thank you 🙂🙏
Thank you so much mam creates more video like this....😍
From SL ❤❤
Crystal clear explanation 👏🙌
Finally understood this. Thank you very much ma'am.
Glad to know that 😊🙏
Thank You mam for helping me for the preparation of my final exam, If I left studying bode plot, then there would be no chances of passing my final exam of Control System 1 subject of 3rd year electrical engineering, because in college I did not understand my teacher's teaching of Bode Plot Unit
Thanks a lot again 🙏🙏
Glad to know that it was helpful to you 🙂🙏
@@sheebaps आप अपना ये काम ऐसे ही आगे बढ़ाते रहिए, ताकि जिनको कॉलेज में समझ नहीं आता है उनके लिए ये बहुत फायदेमंद है और ज्यादा likes भी मिलेंगे तुम्हारे videos को
thank you so much mam, helps me alot for my final exam tomorrow
Bit Mesra se ho kya
My exam also tomorrow thank you mam ✨🎉
Best lecture for bode plot
Thank you 🙂🙏
Thank u maam for the best explanation of the bode plot
🙂🙏
विषय क्लिअर, मनापासून आभार 🫡
🙏🙂
Thank You mam i dont know how to express my feelings for helping me for the preparation of my final exam, If I left studying bode plot, then there would be no chances of passing my final exam of CS. TNX MAM
Glad to know that it was helpful for you 🙂🙏
Thank u very much madam the way of teaching 💞 is wonderful 😊🥰💕
This video made my concepts clear... Thank you so much ma'am ♥️
Preparing 3 hrs before the exam😎
#backsitengineer
All the best 👍
@@sheebaps tnx 😃😃😃
Really u explained well mam and to the point.I was looking for this type of content
Tnq u soooooo much madam......ur video very helpful 🥰
🙏🙂
cleared all my doubts
thank you very much mam
🙏🙂
Thank you so much mam this helps me alot👌
🙂🙏
Very good explanation 👍
Tq🥰 for explaining. Tomorrow exam...
Good luck for your exam 👍
Very good lecture ❤
@@ayushkruikey6085 Thank you 🙂🙏
Thank you mam very helpful video 🙌 got to understand bods plot clearly
This is what i was looking for
Thank you maam
best explanation mam....thanks alot💕
Thanks.. very good explanation
🙂🙏
Thank you very much mam, May you be able to do more like this...
thanks for the lecture mam...🙏❤️
🙂🙏
Super explanation ..
Thank you 🙂🙏
Nice explanation❤
😊🙏
Please maintain video quality sis .good explanation
👍🙏
Very helpful video ...
Thank you 🙂🙏
Thank you sooo much mam create more video like this
Hello Mam, Lect is very useful but I have doubt that In the Gain Plot, -20db/dec Slope should start from Gain of 6.0 db ?
@@laxmandake6524 Decide on a starting frequency one decade below the least corner frequency, then draw the starting slope line & ensure that this line should pass through the k value (6.02 dB) at w=1. Draw the new slope lines at every corner frequency.
Thank You Mam💐
I ploted on matlab. I think there is a problem because when the w=1 rad/s amplitude appears to be 2dB2.8dB on matlab
@@sheebaps thank you for your answer 😍
I have a doubt. You drew the the 6.02 db line which is the basis for the other +20 or -20 db/decade. What to do if the question doesn't have a constant factor like 10/5 =2? How do we determine this gain then?
@@RPT-i3rDraw a line with the starting slope. Starting slope will be the slope corresponding to poles or zeros at origin if it is present otherwise it will be slope corresponding to the lowest corner frequency term.
Ma'am can u solve the quadratic equation type in the same bode plot
Nice explanation
do you have any video about how to plot using the root locus
great explanation
Mam once clearly explain the Nyquist plot vedios and theory
Pls check my past videos on Nyquist plot.
Make more videos on frequency analysis lecture.
Hello, what if the numerator is K? Like there is no value and we have to find the range of K to make the system stable.
If k is not given, plot the bode plot assuming k=1 and find the value of k from gain margin using the equation, 20 log k= GM dB or shift the plot as per the conditions given, if any.
Mam I have a doubt while making a table for phase plot shouldn't we substitute omega value as 5 too ?
Yes, You can take as many closer values for more accuracy.
Thank you mam
Thanks mam...But I didnt undrstand how to find phase angle..Will you help me out plzz?
Thanks a lot...
Thank you❤❤❤
🙂🙏
Pls do video on quadratic equations
K/s(s+1) probleame vedio cheyyandi...
Thanku mam plz explain about pm i didnt understand it🙏❤️
Phase Margin is the additional phase lag which can be introduced into the system so as to bring the system to the verge of instability at gain crossover frequency. Gain crossover frequency is the frequency at which the magnitude becomes 1 (0 dB) in Bode plot.
What can be done if there are terms of exponential?
Exponential term usually comes for time delay in time domain.
Thanku so much maam❤
🙂🙏
mam wo jo aapne 0 and 20 ye sab hum 5 interval main bhi lesakte hai in graph
I didn't understand what you meant to say.
mam hum omega value kuch bhi suppose karsakte hai 1000 tak@@sheebaps
@@binishabhattarai8895starting w value you can select based on the lowest corner frequency, You may take one decade below than the lowest corner frequency.
mam and agar sab phase plot positive aaye and even if negative aaye and doesnt pass through 180 tab kya karna hai@@sheebaps
@@binishabhattarai8895 Then Gain margin is infinity
Very good
🙂🙏
Thank You From SL
Thanks a lot mam🙏
Thank you mam...
🙏🙂
Mam i have doubt on calculation part how to take 1 and 5
1 & 5 are the corner frequencies. You can find corner frequencies from the factors in the time constant form. For first order factor of the form (1+sT), it is found by wc=1/T.
@@sheebaps thank you mam
Thank you mam
Mam plz make video on state space representation
Pls check this Playlist for few videos I made for state space analysis:
ua-cam.com/play/PLUkdZRfU84Jmk-UuqKjwueHM50lNTdIWS.html
State space Analysis or representation are same topic
@@nikhilbinawade1422 Representatiom is by means of state space model... Pls let me know which specific topic you are looking for?
Smmall community channel pettandi madem ,,avasaram aythay anchulo. Required questions aduguthamm
Couldn't understand your language..
Thanks a lot
🙂🙏
Which banker is paying your salary ???
Mam how to find slope in 4th step
For first order zero slope is +20db/decade, first order pole it is -20db/decade, second order zero or quadratic factor it's +40 db/decade, second order pole or quadratic factor it's -40db/ decade and so on.
How to solve if we have equal no. Of poles and zeros .... mam....
But here the magnitude plot intersects odb twice . Which point can I take for gain cross over frequency calculation? Ma'am.
Pls make a vedio on this question ma'am pls ...
Okay mam that clear, if my phase angles are in postive then my phase margin formula i.e 180+pi gc is same or it differs ?
how the gain margin is + when we are going to -ve scale ?
@@sheebaps ok thank you :)
Thank u mam❤
thank you so much mam
Thank you Mam🙏
W = 1 pe 6.22 dB he graph me but agar hum w =1 put karenge function me ,,, magnitude 6.22 dB toh nahin aa raha he.... Aise kyun
6.02dB is the decibel value of the constant factor k. (20 log k, k=2). It is independent of the frequency.
You r confusing me even more 😢
Pls let me know what you are confused with?
@@sheebapsthe 0.5 line marked at different place but you have marked it at 0.3.
27:24
@@StudentofsomethingThanks for pointing out the mistake🙏 Instead of 0.5 I mistakenly took 0.3 point, my sincere apologies. Thankfully it didn't affect the values of GM & PM as it was an approximate curve 🙂
thanks madam😇
🙂🙏
Mam, i have one question
Pls let me know your doubts
@@sheebaps clear
31:52 why 180 degree is only taken why not other angle
Phase Margin is the additional phase that can be added to the system to bring it to the verge of instability. For CL stability, mag=1 (0dB) & angle= -180 degree. Hence 180 degree is considered.
Thank you
🙏🙂
Thanks mam✌
Thanks madam
Why everyone drawing bode plot differently
@@sameersingh8828 This is the straight line approximation I have done here.
Due to voice problem i can't understand what are you say
Please use headset.
How PM and GM positive?
If the intersection point corresponding to wpc in magnitude plot is below 0 dB line, then GM is positive. If the intersection point corresponding to wgc in phase plot is above -180deg line then PM is positive.
@@sheebaps ok miss♥️
In Slope column why take -20dB for 1/jw
The slope for first order pole is -20dB/decade. Gain in decibels for pole at origin is found by 20 log (1/w) dB. At w=1, gain is 0 dB & at w=10, gain is -20dB hence slope is -20dB/decade.
mam little bit concept's not understood then we are choose youtube , but you are skip important points,why mam ......?
This video I created to give a clear understanding of the basic concepts required for plotting Bode plot on semilog sheet.
Pls let me know which points I have skipped in this video so that I can include it?
best
🙂🙏
Ma'am aap bhagwan ho
Thank you 🙂🙏
how to find tan inverse any one have an idea ?
Tan(theta)= opposite side/adjacent side
Therefore , theta= inverse tan(opposite/adjacent)
i still didn't get how you found GM
GM is the gain at phase crossover frequency (frequency at which phase angle becomes -180 degree). It can be found as the difference between 0dB & the gain at point of intersection at Wpc.
@@sheebaps what are the terms you have summed/multiplied/subtracted so that gain is coming12db .....please explain mam!
@@studbanda9426Corresponding to the intersection point, from Y-axis you can get the value as -12dB (approximately) . So GM is 0dB - (-12dB)= 12dB.
@@sheebaps ok now got it thank you so much mam!..............
Mam I can't understand easily
@@sheebaps I want your what's app number
Yes mam if any time I will get doubt I will ask in whatsapp mam
🎉🎉
❤️❤️❤️🙌🙌🙌
❤
Your Lecture Made me Even More Confused, Pahle to Itna Slowly Bol rHi hai aap 🙏. upar se Confusion aur Originate kar raahi hai , Kahi ladai karna ho to bahut tej aawaz aayegi, waise thoda tej nhi bol payengi aap
Not clear video mam