You helped me in maths in 7th class, You helped me in math in 8th class, and now you are helping me in Chemistry in 9th class. Salute to you. I wish you were my teacher, Love ❤ from Pakistan.
4 years and nobody corrected his Hcl? It was supposed to be 2 Hcl so that the equation would be balanced but anyway other than that thanks so much for this video u saved another life here because my teacher didn’t teach redox he only touched on oxidation and reduction and expected us to know the rest and scolded us for not knowing how to do and not putting in effort to learn, or if not he just asks us to go home and learn ourselves instead of him teaching. So big thanks to you my life is saved :)) Edit: he keeps forgetting to add a 2 to balance lol but it’s ok
Thanks a lot... I was unable to understand this topic at school even after 1-2 months but after watching the video all my doubts have been cleared... Thanks again... 😄
Can you please help me out with this one 🙏🏽 State the property exhibited by nitrogen (iv) oxide in each of the following equations: 4Cu + 2NO2--4CuO + N2; H20 + 2NO2--HNO3 + HNOz.
How do I know which element I should find the oxidation number for, knowing that the question did not specify for me the element for which I should find the oxidation number? For example, O2F2, what element should I find the oxidation number for?
what about identifying reducing agent and oxiding agent in a reaction that is written as a decomposition? like product (compound) --> reactants hg + n2 or osomething like that
Alright let’s use the decomposition of water as an example. The equation would be 2H2O= H2 + O2. The oxidation number will be as followed +1 -1= 0 and 0. Hydrogen is getting reduced as it gained electrons. Oxygen is being oxidized as it lost electrons. Oxygen is being oxidized because of hydrogen so hydrogen is the oxidizing agent. Oxygen is the reducing agent since it is what cause hydrogen to be reduced.
Because Mg is from Group 2, and it has 2 valence electrons. It will donate 2 electrons to become octet, therefore forming +2 charge. As for Br, it's fro Group 17 (or 7A) and therefore has 7 valence electrons. It will accept 1 electron to become octet, therefore forming -1 charge.
Fe- Reducing agent S- oxidising agent Fe is getting oxidised as it's oxidation state becomes +2 from 0 so Sulphur is oxidising agent S is getting reduced for its oxidation state becomes -2 from 0 so Fe is reducing agent
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@@ayanagarwaliitdelhi7662 got into iit or like just JEE Aspirants saying Future IITian
Where are you going from
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The besttesttttttt lecture I have ever gotten on REDUCING AND OXIDISING AGENTS . Allhamdulillah now I have understood it. JazakAllah (thanks)
You helped me in maths in 7th class, You helped me in math in 8th class, and now you are helping me in Chemistry in 9th class. Salute to you.
I wish you were my teacher, Love ❤ from Pakistan.
How much did you gain in chemistry in 9th?
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+1 subs. increased .
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4 years and nobody corrected his Hcl? It was supposed to be 2 Hcl so that the equation would be balanced but anyway other than that thanks so much for this video u saved another life here because my teacher didn’t teach redox he only touched on oxidation and reduction and expected us to know the rest and scolded us for not knowing how to do and not putting in effort to learn, or if not he just asks us to go home and learn ourselves instead of him teaching. So big thanks to you my life is saved :))
Edit: he keeps forgetting to add a 2 to balance lol but it’s ok
ah thanks for correcting then
I found comfortable to review back chemistry contents that I learned in high school by watching your video :)
Thank you so much! This has definitely enhanced my knowledge on Oxidation-Reduction reactions!
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Thanks a lot... I was unable to understand this topic at school even after 1-2 months but after watching the video all my doubts have been cleared... Thanks again... 😄
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B
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finally i understood it! it was so difficult!
Sir for zn+hcl== h2+zncl2
Is balancing equation not nessasary
Thanks 👍
Can you please help me out with this one 🙏🏽
State the property exhibited by nitrogen (iv) oxide in each of the following equations:
4Cu + 2NO2--4CuO + N2;
H20 + 2NO2--HNO3 + HNOz.
Awesome explanation 👌👌👌👌👌
Ok
How do I know which element I should find the oxidation number for, knowing that the question did not specify for me the element for which I should find the oxidation number?
For example, O2F2, what element should I find the oxidation number for?
Thanks for your videos
Please make a video on IODOMETRY
In the second reaction there 2hcl I think so
Becoz product contains cl2 and individual h2
Thanks sir very helping
UGGHHHH THANK YOU SO MUCH
Why HCl is used in titration mixture?
K2Cr2O7+ 6KI+14HCl- I2 + 2CrCl3+8kCl
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It was awesome helped me a lot
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Thanks...
what about identifying reducing agent and oxiding agent in a reaction that is written as a decomposition? like product (compound) --> reactants hg + n2 or osomething like that
Alright let’s use the decomposition of water as an example. The equation would be 2H2O= H2 + O2. The oxidation number will be as followed +1 -1= 0 and 0. Hydrogen is getting reduced as it gained electrons. Oxygen is being oxidized as it lost electrons. Oxygen is being oxidized because of hydrogen so hydrogen is the oxidizing agent. Oxygen is the reducing agent since it is what cause hydrogen to be reduced.
thanks
Now i understand 👍
Im confused, is bromine the oxidized or is it the sodium bromide as a whole? Gotta ask for my homework.
i appreciate it mannnnnnnnnnnnnnnnnn
ty
What about chlorine in second equation ? 5:42
Is it oxidising agent or reducing agent ?
thanks so much man
Ok
Your amazing
Sir can you please tell about 5clo3 + 3as2s3 + 9h20 = 5cl + 6h + 6h2as04 + 9s
Which one is what ??
Ans this :-
2Na + H2 --> 2NaH
Then who get reduced and who get oxidised ?
Na goes from 0 to +1 so it is oxidized
H goes from 0 to -1 so it is reduced
I think...
magician.
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Great
do you know how many times I've aced my exams because of your tutorials
Why do scientists make these things complicated
Where does it get the +2 charge though. I'm so confused..
Because Mg is from Group 2, and it has 2 valence electrons. It will donate 2 electrons to become octet, therefore forming +2 charge. As for Br, it's fro Group 17 (or 7A) and therefore has 7 valence electrons. It will accept 1 electron to become octet, therefore forming -1 charge.
ChemSimplified ahh okay thank you very much!
@@Electric-Wind-Hook-Fist You're most welcome!
Cool
Fe + S =FeS ...can u tell what is oxidized agent and reducing agent in this reaction ???
Fe- Reducing agent
S- oxidising agent
Fe is getting oxidised as it's oxidation state becomes +2 from 0 so Sulphur is oxidising agent
S is getting reduced for its oxidation state becomes -2 from 0 so Fe is reducing agent
does it matter in which state is each element?
I don't think so.
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