Frequencies in the Fourier transform

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  • Опубліковано 13 гру 2024

КОМЕНТАРІ • 7

  • @abdallahmahmoud8642
    @abdallahmahmoud8642 4 роки тому +4

    Hello Dr. Mike,
    So I watched this video many times.
    Till now I don't understand how the sample rate equals the number of time points?? because you seem to visualize the srate/2 at the middle between 0 and N. Can you clarify that a bit more if you have time? Thank you

    • @aleksandrazajdel2070
      @aleksandrazajdel2070 4 роки тому +2

      The sampling rate determines the number of points in 1 s. I suppose that in this example we take period T=1s, thus the sampling rate equals the total number of points.

    • @desrucca
      @desrucca 2 роки тому +2

      It is basically a frequency : number of points in one period.

    • @voidisyinyangvoidisyinyang885
      @voidisyinyangvoidisyinyang885 Рік тому

      @@desrucca to find out the truth of "one period" study Fields Medal math professor Alain Connes. thanks

  • @JosueA_455
    @JosueA_455 3 роки тому +1

    If frequency increases in SHM, so does the acceleration. But does it make sense that high frequencies impose such a high acceleration? How do you account for this biased acceleration given by high frequencies. For instance, for SHM, a=( 2*pi*f)^2. How do you account for the fact that lower frequencies have more detrimental effects that high frequencies?

  • @hurstcycles
    @hurstcycles 3 роки тому

    If the signal points are in weeks, does that mean the sample rate is 1/52? Or if in days the sampling rate is 1/365? Great videos thank you!

  • @tilkesh
    @tilkesh Рік тому

    Thank you very much