OH MY GOSH THANK YOU SO MUCH. NOW I FINALLY UNDERSTAND EVERYTHING THAT I MISSED IN CLASS. YOU EXPLAIN THINGS SO WELL TYSM FOR ALL YOUR VIDEOS AND PLEASE KEEP IT UP. THANKS.
@@ericcartman1168 dude im on a MacBook Pro with headphones and all the volume options on max, I just have a ceiling fan on above me and I still barely can hear what he's saying.
At 3:10 you used the total resistance to solve for the current but at 8:42 you solved for the current by only using the R of the load resistor should it not be the total (r + R) when solving for the current ?
finally somebody that knows what they're talking about, excellent job, i can't believe the other ah's on youtube that are providing so much misinfo., it is ridiculous.
Great vid .At the time 3:35 Why do we not multiply by 101 ohms being the total resistance?? Instead you multiplied by the 100 ohms resistor . I may have complicated this by asking plz explain...
If I understand your question right, the R=1ohm R=100 ohm Is more like part (i) part (ii) The question can be taken as find internal resistance when external resistance is (a) 1ohm (b) 100 ohm
Can you do the same, but a little more practical? In this situation you wanted to calculate and measure internal resistance, and you had the Emf value. But in a real situation you cant relay on the value you get from the producers. Since most batteries wear out with use (at the same time internal resistance increases) In other words. Calculate Internal resistance with Emf as an unknown value.
I have a question it actually comes from the text book titled "success in electronics" 2nd edition In Unit 2 Direct Current subtitle 2.14 problems. No 14 the last problem. It has fig 2.20, and the question says in fig 2.20, V is a high resistance voltmeter. a) it reads 6V when the switch is open and 4.8V when it is closed. Calculate the e.m.f and internal resistance of the battery battery. Please help.
2. Terminal pd across the battery is measured at 6.2 V. The battery consists of 2 cells connected in parallel. Given that R_total is 3.1Ω and A measures 2 A: 2.1 Determine the emf of the battery. How can I solve this JG?🤔
First the e.m.f is what is written on battery's by company's and nothing happens to it but The terminal potential is the actual value of the battery and as time gose it decrease bec of internal resistance of the battery and this is called lost potential Then emf= t.p + l.p
A circuit consists of a variable resistor R connected in series with an ammeter and a cell. A voltmeter is connected in parallel across the variable resistor R. the cell is of e.m.f E and internal resistance r. For a certain value of R, the voltmeter reads 4V and the ammeter reads 1A. When R is adjusted, the voltmeter reads 2V and the ammeter reads 2.5A. Draw the circuit diagram and calculate the values of E and r. Please help!!
I have a question: if I were to find the internal resistance of a battery, should I use a resistor with higher resistance or one with a lower resistance? Thank you.
For your last equation you divided by -12 and your overall result was .42 however to my understanding another way I tried which goes by the rules of transposition if you have 11.9=12-0.238r if you move the r to the other side of the = side and the same with the 11.9 makes it -r=12-0.238-11.9 then change all the signs of positive to negative to both sides making it r=-12+0.238+11.9 and get result of 0.138. either I'm wrong or you are. If there is anyone here who understands this better then me please explain. Thanks
dayum, 11.9 = 12 - 0.238r ; here 'r' is multiplied to -0.238, so you can't just simply take only the 'r' to the other side of the equation, you gotta take the whole -0.238r to the left, if you want to, and the equation will be 11.9 + 0.238r = 12, then you can carry out this...
Two resistor 12 ohm and 6 ohm are connected in parallel and this combination connected in series with 6.25 ohm and battery has internal resistance of 0.25 ohm how to find emf of battery???
Get your voltage difference between your load. With that voltage find the current using ohm's law assuming you know the resistance of the circuit. After you have the current of the circuit and the voltage difference use equation: vr( the voltage difference you measured) = ( the internal resistance of the battery which you don't know)- Current multiplied by the resistance. You simply get vr to the other side of the = sign to become a -vr and the internal resistance to the other side so the equation would be your internal resistance= - vr - ir. Vr is voltage difference and ir is current multiply by resistance that would give internal voltage.
![Lp. Сердце Вселенной #60 РОЖДЕНИЕ ЛОЛОЛОШКИ [Финал] • Майнкрафт](http://i.ytimg.com/vi/YoR0pAV9FVQ/mqdefault.jpg)
Final Exams and Video Playlists: www.video-tutor.net/
For nearly 2 years, this concept has baffled me. Now I totally understand. Big up
OH MY GOSH THANK YOU SO MUCH. NOW I FINALLY UNDERSTAND EVERYTHING THAT I MISSED IN CLASS. YOU EXPLAIN THINGS SO WELL TYSM FOR ALL YOUR VIDEOS AND PLEASE KEEP IT UP. THANKS.
OMFG U SAVED ME..ALTHOUGH UR VOICE ALWAYS MAKE ME SLEEP..U ARE A REALLY HELPFUL AND GOOD TEACHER..THANK YOU!
Thanks
@krisda there's this feature on the phone where you can turn up the volume
@@ericcartman1168 dude im on a MacBook Pro with headphones and all the volume options on max, I just have a ceiling fan on above me and I still barely can hear what he's saying.
My exam is in like 30 mins 💀💀
Zeyin Mukhanov I ended up getting an A 😂😂
GG
Fr😂
Lmao feelz
i have my exam in 11hours :(
Eventhough I dont take any physic class , but I'm gonna save these video so I can learn it myself this summer time
That's awesome 🎉
thu ha ada
Very good
excellent video on this topic, this was the only part of AS physics i was wobbly on before tomorrows exam
I fucked up my first paper 😭🔫
@@kyliek.9481 F
Who else is here in 2020 cause they skipped all their online classes?😂😭
I was sick for like 3 days and missed so much this man saved me
lmao me
I ended up falling.. turns out the pass rate of the course was 34% so at least im not alone...
shut up you burglAR
2021 and yes
You are killin it with this videos. Do you have plans to start magnetic fields anytime soon?
Thank you so much. It's really helpful. You are a very good teacher...
Best explanation on this subject on UA-cam. Thanks much.
i loooveeee physics yayyy i loveee staying up to study because im too anxious to sleep
This can be helpful but its more like an ASMR to me perfect vid to sleep in
Lmfao
V. clear explanation and logical working. Thank you
My final first year exam in about three hours...
Wish me luck
This video cleared up a lot of things, thank you so much
I really enjoy your subject only when you add more questions to it
This helped a ton- thanks man
Such good video. Although it is not very logic, it is great for me to review.
Ur amazing sir, all your videos r very helpfull
Excellent explanation ...I really enjoyed your lesson 🤩🤩 am just looking forward for more lessons ☺️☺️
I can't speak english but, These lessons are so good.
At 3:10 you used the total resistance to solve for the current but at 8:42 you solved for the current by only using the R of the load resistor should it not be the total (r + R) when solving for the current ?
Yeah that part confused me too
thnx a gazillion times !!!
my physics exam tmr :p
Waw clean explaination. Thanks
Thank you 🥺
I really appreciate this🙏
Very good explanation .
Nah physics is actually interesting when u understand it🎉
Thank you so much! it helped me a lot
Thank you God bless you
I am watching this video in my exam 😊 .
you are a very good teacher thanks a lot sir
finally somebody that knows what they're talking about, excellent job, i can't believe the other ah's on youtube that are providing so much misinfo., it is ridiculous.
The book is by Tom Duncan. Reprinted 2013.
Explained well
you great keep it up!
yea a magnetic fields video would be great
Usefull demo. What software are you using here?
I talk about in this video: ua-cam.com/video/rBSuMooMYrs/v-deo.html
how we can calculate it from the graph though ?
It is very helpful！
I like how that guy uses a calc for multiplying 0.11988 and 100
Hi, will you do a video on a VI graph and calculating the internal resistance + current + emf by using the graph please?
I have exams in 39 minutes 😢
so how it went?
Great vid .At the time 3:35 Why do we not multiply by 101 ohms being the total resistance?? Instead you multiplied by the 100 ohms resistor . I may have complicated this by asking plz explain...
If I understand your question right, the R=1ohm
R=100 ohm
Is more like part (i) part (ii)
The question can be taken as find internal resistance when external resistance is (a) 1ohm (b) 100 ohm
Gud explanation
Can you do the same, but a little more practical? In this situation you wanted to calculate and measure internal resistance, and you had the Emf value. But in a real situation you cant relay on the value you get from the producers. Since most batteries wear out with use (at the same time internal resistance increases)
In other words. Calculate Internal resistance with Emf as an unknown value.
Agree
Agree ......please to do so
Thats a bold statment for someone with anime profile pic
@@fabijanskrobar1750 dead body reported
Thanks a bunch🤩
Final touches 😊 exams at 2
you can also calculate internal resistance without finding current just by doing (1 - 11.9/12) x 50
What's the principle you're using?
EP1C (ocn) where did you find that? :\
Exams in 30 min😭
Nicely explained
My brain is exploding trying to understand this stuff
thank uuu soo mucchh👍👍
sir i love ur videos they helped me alot .sir if u have avideo which shows potential difference between two points in the circuit
Here it is:
ua-cam.com/video/MnpJocNB6mc/v-deo.html
God Bless you
Aren't they in parallel? You said series?
its series bro
@@oniyous2619 yeah I saw that after I commented bro 🧍
I have a question it actually comes from the text book titled "success in electronics" 2nd edition In Unit 2 Direct Current subtitle 2.14 problems. No 14 the last problem. It has fig 2.20, and the question says in fig 2.20, V is a high resistance voltmeter.
a) it reads 6V when the switch is open and 4.8V when it is closed. Calculate the e.m.f and internal resistance of the battery battery. Please help.
Why during charging V= e.m.f + Ir??
I'm writing a test tomorrow ☠☠☠🤧 it's on circuits and electrostatic
Abeg hu come from 2024😅
2. Terminal pd across the battery is measured at 6.2 V. The battery consists of 2 cells
connected in parallel. Given that R_total is 3.1Ω and A measures 2 A:
2.1 Determine the emf of the battery.
How can I solve this JG?🤔
how to find emf when no current flows?
On which app you teach us tell me plz?
Thanks boss
Is total resistance same as effective resistance?
I have an assignment i should submit in less than 3 hours from now, And i have 100 problems to solve untill then
wow thank you
Thanks! And what if it's an old battery? What happens to the e.m.f. and the internal resistance as the battery ages and loses its charge?
First the e.m.f is what is written on battery's by company's and nothing happens to it but
The terminal potential is the actual value of the battery and as time gose it decrease bec of internal resistance of the battery and this is called lost potential
Then emf= t.p + l.p
A circuit consists of a variable resistor R connected in series with an ammeter and a cell. A voltmeter is connected in parallel across the variable resistor R. the cell is of e.m.f E and internal resistance r. For a certain value of R, the voltmeter reads 4V and the ammeter reads 1A. When R is adjusted, the voltmeter reads 2V and the ammeter reads 2.5A. Draw the circuit diagram and calculate the values of E and r. Please help!!
Does it really work in "real life"? I mean calculating internal battery resistance 12V car battery the way done in the video?
I have a question: if I were to find the internal resistance of a battery, should I use a resistor with higher resistance or one with a lower resistance? Thank you.
Did you find the answer yet?
or for last r=e-v/I same thing just easier for me to solve straight away if remember this
How to find internal resistance given voltage, current and resistance? Electromotive force is not given
my exam is in 12 hours and im 12 weeks behind 💀
What do we do if they didnt give us the internal resistence? Thanks tho
tysm i got it 4jan2022 7:28 pm
🙏 thanks
life saver
Anyone studying this in 10th grade?
Me
tysm
Thanks a lot!!!!!
For your last equation you divided by -12 and your overall result was .42 however to my understanding another way I tried which goes by the rules of transposition if you have 11.9=12-0.238r if you move the r to the other side of the = side and the same with the 11.9 makes it -r=12-0.238-11.9 then change all the signs of positive to negative to both sides making it r=-12+0.238+11.9 and get result of 0.138. either I'm wrong or you are. If there is anyone here who understands this better then me please explain. Thanks
dayum, 11.9 = 12 - 0.238r ; here 'r' is multiplied to -0.238, so you can't just simply take only the 'r' to the other side of the equation, you gotta take the whole -0.238r to the left, if you want to, and the equation will be
11.9 + 0.238r = 12, then you can carry out this...
Two resistor 12 ohm and 6 ohm are connected in parallel and this combination connected in series with 6.25 ohm and battery has internal resistance of 0.25 ohm how to find emf of battery???
Do you not have the current given? Or the total power dissipated? If so, is it an expression you have to fond or a value?
Are u ever going to do a face reveal
ادعم الفديو ترجم الى العربي ارجوك
what are you saying ???
He is proposing to include Arabic captions for the video
how do i calculate terminal voltage when internal resistance (r) is unknown? :"(
Get your voltage difference between your load. With that voltage find the current using ohm's law assuming you know the resistance of the circuit. After you have the current of the circuit and the voltage difference use equation: vr( the voltage difference you measured) = ( the internal resistance of the battery which you don't know)- Current multiplied by the resistance.
You simply get vr to the other side of the = sign to become a -vr and the internal resistance to the other side so the equation would be your internal resistance= - vr - ir. Vr is voltage difference and ir is current multiply by resistance that would give internal voltage.
Hands down.
isn't that parallel?
🙏🏼
exams in an hour
Use the question I gave you plz
Why your voice make me sleep🙄🙄🙄
im so fucked
There isn't anything that you don't know.
I didn't liked this teaching... Sorrry
Thanks for wasting 19 mins of my time for knowing nothing.
???
U mean 10 mins