Bias Transistor Tutorial

Tutorial questions on Universal Bias BJT Transistor

[@sandeephooda9253]

awesome video, short and to the point. Very well explained

[@etiennelordeau8512]

You just saved my life. Thank you sir!

[@jonaspersson122]

Love your accent. :) Very pleasant to listen to.

[@seanbrum07]

Excellent tutorial

[@archiliusfowl3701]

Thanks.

[@miteswell]

damn wish i knew about this in college

[@ray38961]

thank you sir..:)

[@nabilnader566]

why we get iB , when we ignore loading effective transistor ?

[@orangedac]

Thanks

[@thekoko3678]

how can you assume that the IC is approximately equal to Ie? instead you can also apply a ohms law at a collector and Ie=Ic+Iv right? can anybody help?

[@nikhilraghani2896]

as we can see Ie=Ib+Ic
but Ib(base current) is in the range of micro amps well as Ic and Ie is in the range if milli amps
( micro = 10 ^ -6 milli = 10 ^ -3 )
hence Ib can be ignored as it is very very small
so the eq : Ie = Ic + Ib converts to Ie = Ic ( approx ) and hence we continue the sum take emitter and collector current equal
hope this helped (y)

[@thekoko3678]

oh yes i understand now since base is lightly dope so the value is small or micro so it is approximately equal

[@LemonsDaBest]

3:18 why is it Base +1?, its't it just Ie/ base= Ib?

[@TheJustinSokoloski]

LemonsDaBest be of the use of an emitter resistor.

[@kelvinfeliciano]

I do not understand how r1 and r2 are in series, since you will have the current coming down from r1 then splitting into the base of the transistor and the other current should go to r2. Can someone please explain me why? Is it because the current of ib is so small that we ignore it ?

[@TrueRattlehead]

Idk if it helps anymore but I believe they are in parallel, not series

[@XwpisONOMA]

I cannot understand anything of what you're saying