Power Factor Correction in True Parellel RLC Circuits

engineers.acad...
This video explains what is meant by Power Factor Correction in the context of inductive loads, such as motors and generators. PFC is used to minimise reactive power (which is wasted power) improving the efficiency of the device.
In this tutorial you will learn how to calculate the required size of capacitor in order to offset the reactive power in a given inductor coil.
To learn more about our Electrical Engineering HNC please visit: engineers.acad...

[@kee7937]

The best explaining I've got in a video so far... cheers mate✌️

[@user-ov3cn3yk7w]

Hello.
Best explanation I've heard. Well done. I appreciate very much
your investment in the explanatory videos. It is very helpful to all those who are interested. Thank you.

[@alexa8309]

thanks mate, you're a legend.

[@EngineersAcademyLTD]

Glad to help 👍

[@cebyabraham9269]

thank you so much, wonderful explanation

[@hichuunduhabeenzu3574]

Great explanation, God bless you.

[@aAnNdDyYyGIRL]

Thank you so much! ❤

[@zdzisawk5198]

Very useful information. Thanks.

[@dalenassar9152]

I see where you state that Irl=V/Z and Ic=V/X. Why is I calculated using "X" for one and "Z" for the other?
THANKS MUCH
...is "X" used because there is only one component in this current path?

[@EngineersAcademyLTD]

Yes XC is the only impedance in that branch, whereas Z is used for IRL because Z consists of both R and XL

[@jackfillah1721]

correct me if im wrong, but this capacitance value should bring us to resonant frequency. i took the solution and calculated 1/2pi x sqr(LC) and it come out 81Hz. Am i missing a concept with the relation between resonant frequency and power correction?

[@EngineersAcademyLTD]

Hi Jack - the resonant frequency formula you are referring to would be for an "ideal parallel" circuit, where the inductor only is in parallel with the capacitor. This circuit has a slightly different formula for resonant frequency - see this vid for more info: ua-cam.com/video/zVOibkXeZs8/v-deo.html

[@AJ-et3vf]

great video sir. Thank you!

[@imranali-cu7vj]

Wao what a explanation

[@eugeneg40]

Fantastic explanation

[@haidarbadavi9460]

Thats very good

[@koskobirok9760]

First i wanna say sorry, i can speak a little english.. i have a question.. the question is wt if the branch which included the capacitor was in the middle (the place of the other branch) is it the same? I mean nothing will change or wt?

[@EngineersAcademyLTD]

It doesn't matter what order the branches are in here. So if the middle branch is the capacitor, and the right-hand branch is the resistor-inductor, the method is the same.

[@princechaudharyentertainme2250]

Very useful lecture.

[@princechaudharyentertainme2250]

Great concept!

[@haidarbadavi9460]

I looked for the video you mentioned in minute 8:10 , couldnt find it .pls do you have the link if you dont mind

[@EngineersAcademyLTD]

ua-cam.com/video/-2aObOh1KX8/v-deo.html

[@KRuStyKxng]

Loved it , thank you

[@williamkopanchuk]

Excellent!

[@cooperoneill9734]

What is J? And how would you describe polar form when talking about impedance?

[@EngineersAcademyLTD]

j is the imaginary unit in this case: the square root of -1. See this vid for more info: ua-cam.com/video/C61WyIxB9b4/v-deo.html thanks

[@phathu949]

Where do we get angles

[@phathu949]

Can you help mee find the previous video so that i can know how to convert from 20+j15.71 to25,43

[@EngineersAcademyLTD]

Yes it is this one here: ua-cam.com/video/-2aObOh1KX8/v-deo.html