11 chap 4 | Circular Motion 04 | Derivation of Centripetal Acceleration or Centripetal Force |
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Sir aaj purane video pe?
Sir apne V=WOMEGA/R pa V ka vector sighn nahi dia
Sir , Is Centripetal acceleration always directed towards its center?
Then Sir (-) minus will come in its formula or not?
@@Humann54 omega=v by r hoga
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Method 2 or short method strt from 7:11
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Second method: if there is circular motion with constant r & constant angular motion then dr/dt =0 , so there is no centripetal force in constant r & Omega .
Right think
We diffrentiate radius vector not magnitude of radius there 😊
Sahi bole ho bhai
Ha bhai ye wrong method hh
here we used radius vector which is denoting the arc...
And the length of arc differentiate to time is velocity...
Hope u understand...
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Can anyone tell me why the f, dr/dt is v in method #2?????
I am highly triggered with it.
For those who r thinking that radius is constant yeah it is constant but radius vector is not constant. It is changing which gives velocity at right angle to radius. As velocity is changing n it's derivative is is perpendicular direction , in same way radius vector is changing n it's velocity vector is perpendicular to radius. Also velocity vector depends on radius vector.
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Sir please clear my doubt… at 19:56 the radius r is also constant so when you differentiate r it should be zero
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Sir Can You Explain How omega will be constant and radius of the circle won't be a constant
Because that 'r' is considered the linear displacement of the circle
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Sir last me (r) radius ko diffentiate karke kaise velocity ayega radius to constant hai n to derivative zero Hoga ?.
Answer mila kya??
'r' ko position mana hai i guess.
Change in displacement he took
Sir I have a doubt. It may be correct or not. Sir radius bhi to constant tha to uska differentiation kaise kar diya?
Magnitude of radius vector is constant but direction of radius vector is changing so radius vector is variable.
Yes I have same confusion
Radius constant nhi hain
@@isfaqul3333 radius kaise displacement ho sakta hai
17:57
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dr/dt is change in radius then how dr/dt is equal to linear velocity" V " in second derivation
dr/dt should actually be 0, because the radius doesn’t change I.e., radius is a constant value hence its differentiation is 0. Incorrect second method
@@psf1234 yess
That r is position vector
@@psf1234 second method is not incorrect r is position vector and dr/dt= v
@@PratimaKumari-nt2xw no ,r is radius
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Sir lekin R be constant hoga aur differential zero hoga. In last proof where u kept Dr/dt as v
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Sir method 2 me R bhi constant rahega . How can u differentiate that?
Yes I thought the same
R is radius not displacement
@@BushraKhan-ek2jc yes me too have same doubt
Yes brooo
Yes, second method is wrong
Why is perpendicular to velocity took radially inwards ? Why not radially outwards ?
If took radially outwards, cetrepetal acceleration will come radially outwards.
When we sit on Merry go round we tend to move radially outwards.
When we whirl a key ring in circular motion, it also tends to go radially outward of our finger.
Whats the paradox ?
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why in 19:33
Sir, take r as displacement
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19:40
But r is radius
And it's a constant
How can we differentiate it
It's value would be 0
Plz someone clear this doubt.
Radius vector ko differentiate kia h sir ne.uski direction change ho rahi h.
Radius ki direction kaha change ho rahi h
@@chhaganlal7649 jese V ka magnitude constant tha but direction change ho rhi thi isliye differentiate hokar 'centripetal acc.' ban gaya vese hi radius vector ki bhi direction change ho rhi thi har point par to vo bhi differentiate ho gya
@@harshsoni3320 radii ki direction ni hoti bhai.. Vo kaise change hogi
@@RakeshYadav-ke8gk oh my god you're so stupid. We are talking about rafiys VECTOR not radius. Clearly the direction changes
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hello sir... i have two questions regarding the two methods
Q1. In method1 u said centripetal acceleration is along the radius , cant it be radially outwards as it also contains 90 degree angle?
Q2. in method2 u said radius is also constant as v and omega both are constants, so y why u took omega as constant and radius is not constant while differentiation the RHS with respect to time?
waiting for your reply sir.
thanka
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