Chem Help - Back Titrations

This video will give you the basics of the back titration. A tricky but common twist to the typical titration question.

[@PeachTeaOfficialPage]

Genuinely started to lose hope in understanding this concept. Hard to believe it was this simple. THANK you, Professor Shackleton!

[@jimshackleton]

Glad it was helpful!

[@naamanowuor5534]

Short and clear. This is incredible

[@MrCoolstopmotion]

Even shorter if you watch 2x

[@HeleddtheSea]

Excellent video on back titration! Thank you so much for explaining it in a really clear way!

[@jimshackleton]

Glad it was helpful!

[@MabukuBoysen]

clear and perfect👋' make more vedios like this sir

[@zoea5448]

I thought I was going to fail my lab tomorrow but after this video I finally got it, thanks!

[@mebhvnvbbc3909]

i wish all teachers could explain like this 😁

[@NdzalaMashava]

Clear and straight to the point...

[@markoundo8445]

Sincere thank you, from a X-struggling student

[@maxwellnanayeboah4036]

Thank u professor
God richly bless u

[@brunoloeffler8036]

Absolute Legend Mate!

[@ricecakes6008]

Helped me so much, thank you!!!!

[@nas_775]

Thanks so much, great video

[@urban_video5949]

this video is soooooooooooooooo good thank you

[@haadiawaqas1826]

This was so helpful thank you!

[@libbybakkes7594]

BEAUTIFUL

[@danielgarygabuat8683]

thank you sir! well explained!

[@alwinkachappilly7342]

absolute legend!!!!!!

[@ronanhill5891]

Thanks Jim

[@prontgamer2294]

Tnx king. This shall be of use

[@frankharrisugonabo3312]

Nice vid

[@euphoria4000]

I dived straight into yr 12 chemistry without actually knowing how to do titrations properly but this video may have saved me from failing yr 12 chem

[@yabanc_8357]

thank you this is an actually understandable explanation!

[@jimshackleton]

You're very welcome!

[@wansibho554]

Thank you

[@aphelelefanho9819]

thanks sir you realy realy helped me

[@homeallen6177]

Really helpful 👏👏

[@aCuteHarleengitis]

I spent 2 hrs oing this calculations, and then I found this video : )

[@LittleMsWanderer]

THANK YOU

[@mellowfacevevo]

good stuff mate

[@fakhirrehan8869]

sir u are the best teacher thankuu

[@stanleyanokye5622]

Thanks Man

[@humphreymulenga2145]

Thank you sir 🎉

[@pardonchishiba8942]

Wow 👏👏

[@finnharty1476]

you are the best thank you so much

[@jimshackleton]

You're welcome!

[@Zahra-zy4ze]

Great content, thanks Jim. Quick question, how is the excess HCL obtained? so once the chalk sample reacts with the HCL how is the excess HCL extracted?

[@jimshackleton]

Hi Zahra. The concept here is that a large, but measured, amount of HCl is added to the chalk. All of the chalk reacts with some of the HCl, leaving some acid in excess. You then titrate the resulting solution with a base to tell you what the excess amount of acid is - so it's not extracted from the system, it's done in the same vessel. You subtract the titre amount from the starting amount of HCl - and there's the amount that reacted with the chalk.

[@Zahra-zy4ze]

@@jimshackleton Thank you, makes absolute sense now :)

[@farahnaz1581]

brilliant explanation

[@jimshackleton]

Glad you think so!

[@ebenezeranane7672]

Can you please help me with this ❓
1. A 5.0ml mixture containing Na2CO3 and NaOH required 28.8ml of 0.5000N HCl to reach a phenolphthalein end point and an additional 14.4ml to reach a methyl orange. What are the percentage of Na2CO3 and NaOH.
2. A 2.4671grams sample was titrated with 0.5282M of HCl. It consumed a volume of 23.4ml to reach a phenolphthalein end point and an additional 47.2ml of the acid was consumed to reach a methyl orange end point. What is the identity of the sample and its percentage compositions.

[@tekelatk4340]

Where did the ½ come from

[@jimshackleton]

From the coefficients in the final question. Calcium Carbonate is 1 and Hydrochloric acid is 2. So unknown/known = 1/2. This is the mole ratio.

[@BFR-jc5np]

look a little bit like Eminem